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If possible, find (a) \(A+B,(b) A-B,(c) 3 A,\) and \((d) 3 A-2 B\). $$\begin{aligned} &A=\left[\begin{array}{lllll} 4 & 5 & -1 & 3 & 4 \\ 1 & 2 & -2 & -1 & 0 \end{array}\right]\\\ &B=\left[\begin{array}{rrrrr} 1 & 0 & -1 & 1 & 0 \\ -6 & 8 & 2 & -3 & -7 \end{array}\right] \end{aligned}$$

Short Answer

Expert verified
(a) \(A+B = [\begin{array}{lllll}5 & 5 & -2 & 4 &4\ -5 & 10 & 0 & -4 & -7\ \end{array}]\) (b) \(A-B = [\begin{array}{lllll}3 & 5 & 0 & 2 & 4\ 7 & -6 & -4 & 2 & 7\ \end{array}]\) (c) \(3A = [\begin{array}{lllll}12 & 15 & -3 & 9 & 12\ 3 & 6 & -6 & -3 & 0\ \end{array}]\) (d) \(3A - 2B = [\begin{array}{lllll}10 & 15 & -1 & 7 & 12\ 15 & -10 & -10 & 3 & 14\ \end{array}]\)

Step by step solution

01

Addition of matrices A and B

The addition of two matrices is done element by element:\(A + B = [\begin{array}{lllll}4+1 & 5+0 & -1+(-1) & 3+1 & 4+0\ 1+(-6) & 2+8 & -2+2 & -1+(-3) & 0+(-7)\ \end{array}] = [\begin{array}{lllll}5 & 5 & -2 & 4 & 4\ -5 & 10 & 0 & -4 & -7\ \end{array}] \)
02

Subtraction of matrices A and B

The subtraction of a matrix from another is also done by subtracting corresponding elements:\(A - B = [\begin{array}{lllll}4-1 & 5-0 & -1-(-1) & 3-1 & 4-0\ 1-(-6) & 2-8 & -2-2 & -1-(-3) & 0-(-7)\ \end{array}] = [\begin{array}{lllll}3 & 5 & 0 & 2 & 4\ 7 & -6 & -4 & 2 & 7\ \end{array}]\)
03

Scalar multiplication of matrix A

Each element in matrix A is multiplied by the scalar 3:\(3A = 3 * [\begin{array}{lllll}4 & 5 & -1 & 3 & 4\ 1 & 2 & -2 & -1 & 0\ \end{array}] = [\begin{array}{lllll}12 & 15 & -3 & 9 & 12\ 3 & 6 & -6 & -3 & 0\ \end{array}]\)
04

3A - 2B

To calculate \(3A - 2B\), we first multiply each matrix by their respective scalars, then subtract the second matrix from the first:\(3A - 2B = 3 * [\begin{array}{lllll}4 & 5 & -1 & 3 & 4\ 1 & 2 & -2 & -1 & 0\ \end{array}] - 2 * [\begin{array}{lllll}1 & 0 & -1 & 1 & 0\ -6 & 8 & 2 & -3 & -7\ \end{array}] = [\begin{array}{lllll}12-2 & 15 & -3+2 & 9-2 & 12\ 3+12 & 6-16 & -6-4 & -3+6 & 0+14\ \end{array}] = [\begin{array}{lllll}10 & 15 & -1 & 7 & 12\ 15 & -10 & -10 & 3 & 14\ \end{array}]\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Addition
Matrix addition is a fundamental operation in linear algebra. It involves combining two matrices with the same dimensions by adding their corresponding elements together. For example, if we have matrices \( A \) and \( B \) of the same size, the sum \( A + B \) is a new matrix where each element is the sum of the elements from \( A \) and \( B \) in the same position.
Here's how matrix addition works:
  • Check that both matrices have the same dimensions. If not, addition is not possible.
  • Add corresponding elements: if \( A = \begin{bmatrix} a_{11} & a_{12} \ a_{21} & a_{22} \end{bmatrix} \) and \( B = \begin{bmatrix} b_{11} & b_{12} \ b_{21} & b_{22} \end{bmatrix} \), then \( A + B = \begin{bmatrix} a_{11} + b_{11} & a_{12} + b_{12} \ a_{21} + b_{21} & a_{22} + b_{22} \end{bmatrix} \).
Practicing matrix addition with actual numbers helps better understand the process and is an essential skill in solving more complex problems in linear algebra.
Matrix Subtraction
Matrix subtraction is very similar to matrix addition. It involves subtracting corresponding elements of two matrices that share the same dimensions. The result is a new matrix formed by these differences. For instance, if matrices \( A \) and \( B \) are of the same size, we calculate \( A - B \) element-wise.
The steps for matrix subtraction include:
  • Ensure both matrices are identical in dimensions. If not, subtraction cannot occur.
  • Subtract each element from matrix \( B \) from the corresponding element in matrix \( A \): For example, if \( A = \begin{bmatrix} a_{11} & a_{12} \ a_{21} & a_{22} \end{bmatrix} \) and \( B = \begin{bmatrix} b_{11} & b_{12} \ b_{21} & b_{22} \end{bmatrix} \), then \( A - B = \begin{bmatrix} a_{11} - b_{11} & a_{12} - b_{12} \ a_{21} - b_{21} & a_{22} - b_{22} \end{bmatrix} \).
Understanding how to effectively conduct matrix subtraction is crucial for progressing in topics such as systems of equations and other applications in linear algebra.
Scalar Multiplication
Scalar multiplication is a straightforward process in linear algebra, where each element of a matrix is multiplied by a constant, known as a scalar. This operation scales the entire matrix by the scalar value.
To perform scalar multiplication:
  • Select a scalar, say \( k \).
  • Multiply each element of matrix \( A \) by this scalar to get \( kA \). For example, if \( A = \begin{bmatrix} a_{11} & a_{12} \ a_{21} & a_{22} \end{bmatrix} \), then \( kA = \begin{bmatrix} k*a_{11} & k*a_{12} \ k*a_{21} & k*a_{22} \end{bmatrix} \).
This operation is helpful in various applications, such as modifying the magnitude of vectors and matrix transformations. Practically, scalar multiplication simplifies solving equations involving matrices and forms a basis for discussing matrix operations in larger concepts.
Linear Algebra
Linear algebra is a branch of mathematics dealing with vectors, vector spaces, and linear equations. It's a powerful tool for understanding systems in various fields, from computer science and engineering to physics and statistics.
In linear algebra, matrices represent linear transformations and systems of equations. Key operations like matrix addition, subtraction, scalar multiplication, and others are essential tools in analyzing and solving these systems.
Some core concepts in linear algebra include:
  • Vectors and vector spaces: Vectors are entities with magnitude and direction, used in numerous applications.
  • Matrix operations: Essential operations such as addition, subtraction, and scalar multiplication permit the manipulation and solution of linear systems.
  • Eigensystems: Understanding eigenvalues and eigenvectors, critical for systems stability and dynamics in differential equations.
Linear algebra serves as the foundation for many machine learning algorithms and plays a crucial role in fields like data science and robotics, making it a valuable knowledge base for students.

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Most popular questions from this chapter

Consider the circuit in the figure. The currents \(I_{1}, I_{2},\) and \(I_{3}\) in amperes are given by the solution of the system of linear equations. \(\left\\{\begin{aligned} 4 I_{1} &+8 I_{3}=2 \\ & 2 I_{2}+8 I_{3}=6 \\\ I_{1}+& I_{2}-I_{3}=0 \end{aligned}\right.\) Use Cramer's Rule to find the three currents.

use the matrices $$A=\left[\begin{array}{rr} 2 & -1 \\ 1 & 3 \end{array}\right] \quad \text { and } \quad B=\left[\begin{array}{rr} -1 & 1 \\ 0 & -2 \end{array}\right].$$ $$\text { Show that }(A-B)^{2} \neq A^{2}-2 A B+B^{2}$$.

Determine whether the statement is true or false. Justify your answer. The points \((-5,-13),(0,2),\) and (3,11) are collinear.

The table shows the numbers of international travelers \(y\) (in thousands) to the United States from South America from 2008 through 2010 . $$\begin{array}{|l|c|}\hline \text { Year } & \begin{array}{c}\text { Travelers, } y \\\\\text { (in thousands) }\end{array} \\\\\hline 2008 & 2556 \\\ \hline 2009 & 2742 \\\\\hline 2010 & 3250 \\\\\hline\end{array}$$ (a) The data can be modeled by the quadratic function \(y=a t^{2}+b t+c .\) Create a system of linear equations for the data. Let \(t\) represent the year, with \(t=8\) corresponding to 2008. (b) Use the matrix capabilities of a graphing utility to find the inverse matrix to solve the system from part (a) and find the least squares regression parabola \(y=a t^{2}+b t+c\). (c) Use the graphing utility to graph the parabola with the data. (d) Do you believe the model is a reasonable predictor of future numbers of travelers? Explain.

use the matrices $$A=\left[\begin{array}{rr} 2 & -1 \\ 1 & 3 \end{array}\right] \quad \text { and } \quad B=\left[\begin{array}{rr} -1 & 1 \\ 0 & -2 \end{array}\right].$$ $$\text { Show that }(A+B)(A-B) \neq A^{2}-B^{2}$$.

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