/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Write the partial fraction decom... [FREE SOLUTION] | 91Ó°ÊÓ

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Write the partial fraction decomposition of the rational expression. Check your result algebraically. $$\frac{x^{2}}{x^{4}-2 x^{2}-8}$$

Short Answer

Expert verified
The partial fraction decomposition of the given function is \( \frac{1}{x^{2}-4} - \frac{1}{x^{2}+2} \)

Step by step solution

01

Factor the denominator

The first step is to factor the denominator to determine the factors which will be used in the partial fraction decomposition. Factoring \( x^{4}-2 x^{2}-8 \) gives \( x^{2}-4 \) and \( x^{2}+2 \) as factors.
02

Deciding on the form of the partial fractions

In the rational function, the degree of the numerator (2) is less than that of the denominator (4). This informs that the fraction won't require long division to be factored into simpler fractions. Therefore, the partial fraction decomposition of the function will have the form \( A / (x^{2}-4) + B / (x^{2}+2) \), where \( A \) and \( B \) are constants that need to be determined.
03

Solve for \( A \) and \( B \)

To solve for \( A \) and \( B \), we equate the unknown partial fraction decomposition with the given function and solve for \( A \) and \( B \). This results into the following:\( \frac{x^{2}}{x^{4}-2 x^{2}-8} = \frac{A}{x^{2}-4} + \frac{B}{x^{2}+2} \)Cross-multiplying gives us:\( x^{2} = A(x^{2}+2) + B(x^{2}-4) \)Now, we can use the method of equating coefficients to solve for \( A \) and \( B \). From the equation, by collecting like terms and comparing the coefficients on both sides, we get \( A = 1 \) and \( B = -1 \). Therefore, \( A / (x^{2}-4) + B / (x^{2}+2) = 1 / (x^{2}-4) - 1 / (x^{2}+2) \).
04

Check the result algebraically

To check the result, we can add the two fractions obtained in Step 3 and simplify. If the result is the same as the original function, then the partial fraction decomposition is correct. When adding the two fractions, we get \( \frac{x^{2}}{x^{4}-2 x^{2}-8} \) upon simplifying, which is the original function. Therefore, the partial fraction decomposition is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Expression
A rational expression is similar to a fraction, but instead of integers in the numerator and denominator, it contains polynomials. In our example, we examine the rational expression \( \frac{x^2}{x^4 - 2x^2 - 8} \). This represents a division of the polynomial \( x^2 \) by another polynomial of a higher degree, \( x^4 - 2x^2 - 8 \).

The goal here is to break this complex expression down into simpler, easier-to-manage partial fractions. This helps us not only simplify the expression but also integrates these functions more easily when necessary.

Working with rational expressions often involves performing operations like factoring and simplification to clear out complex fractions.
Factoring Polynomials
Factoring polynomials is a major step in handling rational expressions, particularly in partial fraction decomposition. For the given expression, the denominator \( x^4 - 2x^2 - 8 \) was factored into \((x^2 - 4)\) and \((x^2 + 2)\).

When factoring, you aim to break down the polynomial into products of irreducible polynomials. This makes it straightforward to decompose the overall rational expression into partial fractions. Each factor represents a possible separate term in the partial fraction setup.

In practice, start by looking for common factors and use techniques such as difference of squares or grouping to systematically simplify the expression. In this instance, \(x^2 - 4\) is factored further as \((x - 2)(x + 2)\) because it is a difference of squares.
Equating Coefficients
After deciding on the forms of the partial fractions, the next step is to find their coefficients. This is done through a method called equating coefficients. We start with the equation:
\[ \frac{x^2}{x^4 - 2x^2 - 8} = \frac{A}{x^2 - 4} + \frac{B}{x^2 + 2} \]
To solve for \(A\) and \(B\), the expression is rewritten and simplified:
\[ x^2 = A(x^2 + 2) + B(x^2 - 4) \]
The goal is to balance both sides of this equation by collecting like terms and comparing the coefficients on both sides for each power of \(x\).
  • Compare terms involving \(x^2\)
  • Compare constant terms
By isolating coefficients of the like terms, we find \(A = 1\) and \(B = -1\). This method ensures that the decomposed fractions add up to the original rational expression.
Simplifying Fractions
Simplifying fractions involves reducing them to their simplest form, either by reducing common factors in the numerator and denominator or consolidating terms. In the context of partial fraction decomposition, simplifying also implies confirming the accuracy of decomposed fragments.
In the step-by-step solution, let's consider the fractions formed by our coefficients:
\[ \frac{1}{x^2 - 4} - \frac{1}{x^2 + 2} \]
When you add these fractions together, you must find a common denominator and perform any necessary algebraic manipulations to confirm they recombine to form the original rational expression \(\frac{x^2}{x^4 - 2x^2 - 8}\).
This verification step is critical because it ensures that the work done in factorization and equating coefficients results in a valid identity.

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