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Solve the system graphically. $$\left\\{\begin{aligned} x-3 y &=-3 \\ 5 x+3 y &=-6 \end{aligned}\right.$$

Short Answer

Expert verified
The system's solution is the point where the two lines intersect. The exact solution could be determined either algebraically or by using a graphing tool.

Step by step solution

01

Rewriting The Equations to Slope-Intercept Form

Let's rewrite the system of equations in the slope-intercept form \(y = mx + c\). The first equation of the system can be rewritten as \(y = \frac{1}{3}x + 1\), and the second equation can be rewritten as \(y = -\frac{5}{3}x - 2\). Now the system of equations is \(\left\{\begin{aligned} y = \frac{1}{3}x + 1 \\ y = -\frac{5}{3}x - 2 \end{aligned}\right.\)
02

Plotting The Equations on the Graph

Now plot the two lines on the same graph using the revised forms of our system of linear equations. The line \(y = \frac{1}{3}x + 1\) will have a positive slope and intersect the y-axis at positive 1. The line \(y = -\frac{5}{3}x - 2\) will have a negative slope and intersect the y-axis at negative 2.
03

Find The Intersection Point

The solution to the system of equations is the point where the two lines intersect. In graph, it could be observed visually. However, to find the exact value, it's necessary to solve the system either algebraically or use a graphing tool.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope-Intercept Form
The slope-intercept form is essential for graphing linear equations conveniently. It is written as \( y = mx + c \), where \( m \) represents the slope of the line, and \( c \) denotes the y-intercept—the point where the line crosses the y-axis.

When working with linear systems, the first step usually involves rearranging the equations into this form. This was evident in the exercise where both equations; \( x - 3y = -3 \) and \( 5x + 3y = -6 \) were converted into the slope-intercept form, yielding \( y = \frac{1}{3}x + 1 \) and \( y = -\frac{5}{3}x - 2 \) respectively. This format immediately tells you how steep the line is (slope) and where it anchors on the y-axis (y-intercept), providing a clear approach to graphing.
System of Linear Equations
A system of linear equations consists of two or more linear equations that are collectively considered. The solutions to this system are the points that satisfy all the equations in the system simultaneously.

Equations within a system can have one solution (intersecting at a point), no solution (parallel lines that never intersect), or infinitely many solutions (coincident lines, indicating they're the same line). The textbook exercise we're looking at contains a 'system of linear equations' which we're aiming to solve graphically.
Graphing Linear Equations
Graphing linear equations involves plotting lines on a coordinate plane based on their equations in slope-intercept form.

To graph a line, you need two critical pieces of information from its equation: the slope and the y-intercept. Once the y-intercept is placed as a point on the y-axis, the slope—a ratio that describes the rise over run—tells you how to move from that point to another point on the line. For example, a slope of \( \frac{1}{3} \) means you go up 1 unit vertically and 3 units horizontally to find another point. As seen in the exercise solution, plotting both equations provided a visual representation of each line’s behaviour on the graph.
Intersection Point of Lines
The intersection point of two lines is the core of solving a system of linear equations graphically. It's the point at which two lines on a graph cross, signifying that both equations are true for that pair of x and y values.

In the given exercise, after graphing the lines from the slope-intercept form of each equation, the intersection point is found where they meet. This point represents the solution to the system. If executed carefully, graphing provides a visual solution to the system, making it a fundamental concept in understanding linear equations and their relationships.

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Most popular questions from this chapter

Find the equation of the parabola $$y=a x^{2}+b x+c$$ that passes through the points. To verify your result, use a graphing utility to plot the points and graph the parabola. $$(0,3),(1,4),(2,3)$$

\(\mathrm{A}\) store sells two models of laptop computers. Because of the demand, the store stocks at least twice as many units of model \(\mathrm{A}\) as of model \(\mathrm{B}\). The costs to the store for the two models are \(\$ 800\) and \(\$ 1200\), respectively. The management does not want more than \(\$ 20,000\) in computer inventory at any one time, and it wants at least four model A laptop computers and two model B laptop computers in inventory at all times. Find and graph a system of inequalities describing all possible inventory levels.

Find the equation of the parabola $$y=a x^{2}+b x+c$$ that passes through the points. To verify your result, use a graphing utility to plot the points and graph the parabola. $$(0,0),(2,-2),(4,0)$$

Determine whether the statement is true or false. Justify your answer. When solving a linear programming problem, if the objective function has a maximum value at more than one vertex, then there are an infinite number of points that will produce the maximum value.

The linear programming problem has an unusual characteristic. Sketch a graph of the solution region for the problem and describe the unusual characteristic. Find the minimum and maximum values of the objective function (if possible) and where they occur. Objective function: \(z=2.5 x+y\) Constraints: $$\begin{array}{r}x \geq 0 \\\y \geq 0 \\ 3 x+5 y \leq 15 \\\5 x+2 y \leq 10\end{array}$$

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