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Find the component form of \(\mathbf{v}\) and sketch the specified vector operations geometrically, where \(\mathbf{u}=2 \mathbf{i}-\mathbf{j}\) and \(\mathbf{w}=\mathbf{i}+2 \mathbf{j}\). $$\mathbf{v}=\frac{3}{2} \mathbf{u}$$

Short Answer

Expert verified
The component form of \( \mathbf{v} \) is \( 3 \mathbf{i} - 1.5 \mathbf{j} \).

Step by step solution

01

Write down the given vector components

We have the vector \( \mathbf{u} = 2 \mathbf{i} - \mathbf{j} \) in component form, meaning its x-component is 2 and its y-component is -1.
02

Multiply the vector by 3/2

Given \( \mathbf{v} = \frac{3}{2} \mathbf{u} \), to find the components of \( \mathbf{v} \) we multiply the components of \( \mathbf{u} \) by \( \frac{3}{2} \). Thus, the x-component of \( \mathbf{v} \) is \( \frac{3}{2} \) * 2 = 3 and the y-component of \( \mathbf{v} \) is \( \frac{3}{2} \) * -1 = -1.5. Therefore, \( \mathbf{v} = 3 \mathbf{i} - 1.5 \mathbf{j} \).
03

Draw the vectors geometrically

Represent the original vector \( \mathbf{u} \) and the result vector \( \mathbf{v} \) from the origin on the plane. As mentioned earlier, the x-component represents the movement along the x-axis, while the y-component represents the movement along the y-axis. For \( \mathbf{u} \), it goes 2 units right and 1 unit down from the origin. The vector \( \mathbf{v} \) goes 3 units right and 1.5 units down from the origin. The effect of the scalar multiplication by \( \frac{3}{2} \) will be evident by comparing the lengths of vectors. \( \mathbf{v} \) should be longer than \( \mathbf{u} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Component Form of a Vector
The component form of a vector provides a clear and precise way to represent the magnitude and direction of a vector in a coordinate system. It is expressed as an ordered pair or tuple, reflecting the vector's influence along the axes of the system. For instance, if a vector is denoted as \( \mathbf{v} = a\mathbf{i} + b\mathbf{j} \), the components \(a\) and \(b\) correspond to the movements along the x-axis and y-axis, respectively.

Understanding the component form is crucial, especially when you want to perform operations like addition, subtraction, or multiplication of vectors. By breaking down a vector into its components, these operations become straightforward, as they can be done on each corresponding component independently.
Scalar Multiplication of Vectors
Scalar multiplication involves multiplying a vector by a real number, known as a scalar. When we multiply a vector by a scalar, the result is a new vector whose magnitude is scaled by the absolute value of the scalar, and whose direction is the same as the original vector if the scalar is positive, or opposite if the scalar is negative.

For example, if we have a vector \( \mathbf{u} \) and a scalar \( k \), then the scalar multiplication of \( \mathbf{u} \) by \( k \) is written as \( k\mathbf{u} \). Each component of the vector is multiplied by \( k \), resulting in a new vector. Scalar multiplication affects the length and potentially the direction of the vector, but not the angle it makes with the axes, unless the scalar is negative.
Sketching Vectors Geometrically
Sketching vectors geometrically involves representing them as arrows on a graph, where the direction of the arrow indicates the direction of the vector, and the length represents the magnitude (or size) of the vector. To sketch a vector starting from the origin, you begin at the point (0,0) and draw an arrow that points towards the coordinates given by the vector's components.

One common misconception when sketching vectors is confusing the vector's position with its magnitude and direction. Remember, a vector's essence lies in its magnitude and direction, not its initial position. Therefore, a vector can be moved parallel to itself without changing its characteristics, as long as the magnitude and direction remain the same. This is why vectors are often depicted as starting from the origin for simplicity.
Vector Representation on Plane
Representing a vector on a plane illustrates the vector's components and their respective influences along the x and y axes. In a two-dimensional coordinate system, every vector can be represented by a directed line segment. Its tail starts at the origin, or any other specified starting point, and its head points towards the terminal point determined by the vector's components.

For instance, the component form of a vector \( \mathbf{v} = c\mathbf{i} + d\mathbf{j} \) would mean that we move \( c \) units along the x-axis and \( d \) units along the y-axis to reach the head of the vector from its tail. Additionally, vectors can be added graphically by 'tip-to-tail' method, where the tail of one vector is placed at the tip of another, depicting vector addition as a consecutive path.

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Most popular questions from this chapter

Find the angle between the forces given the magnitude of their resultant. (Hint: Write force 1 as a vector in the direction of the positive \(x\) -axis and force 2 as a vector at an angle \(\theta\) with the positive \(x\) -axis.) $$\begin{array}{cc} \text{Force 1} && \text{Force 2} && \text{Resultant Force} \\\ \text{3000 pounds} && \text{1000 pounds} && \text{3750 pounds} \end{array}$$

Find the component form of the sum of u and v with direction angles \(\boldsymbol{\theta}_{\mathrm{u}}\) and \(\boldsymbol{\theta}_{\mathrm{v}}\). $$\begin{array}{cc} \text{Magnitude} && \text{Angle} \\ \|\mathbf{u}\|=5 && \theta_{\mathrm{u}}=0^{\circ} \\ \|\mathbf{v}\|=5 && \theta_{\mathrm{v}}=90^{\circ} \end{array}$$

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Ohm's law for alternating current circuits is \(E=I \cdot Z\) where \(E\) is the voltage in volts, \(I\) is the current in amperes, and \(Z\) is the impedance in ohms. Each variable is a complex number. (a) Write \(E\) in trigonometric form when \(I=6\left(\cos 41^{\circ}+i \sin 41^{\circ}\right)\) amperes and \(Z=4\left[\cos \left(-11^{\circ}\right)+i \sin \left(-11^{\circ}\right)\right]\) ohms. (b) Write the voltage from part (a) in standard form. (c) A voltmeter measures the magnitude of the voltage in a circuit. What would be the reading on a voltmeter for the circuit described in part (a)?

Find the component form of \(\mathbf{v}\) and sketch the specified vector operations geometrically, where \(\mathbf{u}=2 \mathbf{i}-\mathbf{j}\) and \(\mathbf{w}=\mathbf{i}+2 \mathbf{j}\). $$\mathbf{v}=-\mathbf{u}+\mathbf{w}$$

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