Chapter 5: Problem 71
Use inverse functions where needed to find all solutions of the equation in the interval \(\mathbf{0}, \mathbf{2} \boldsymbol{\pi}\) ). $$\sec ^{2} x-4 \sec x=0$$
Short Answer
Expert verified
The solutions to the equation \(\sec^{2} x-4 \sec x=0\) in the interval [0, 2Ï€] are \(x = \cos^{-1}(1/4)\) and \(x = 2\pi - \cos^{-1}(1/4)\).
Step by step solution
01
Rewrite the equation
The equation \(\sec^{2}x - 4\sec{x} = 0\) can be rewritten with secant as a common factor. The factored form of the equation is \(\sec{x}(\sec{x} - 4) = 0\).
02
Set each factor to zero
Setting each factor individually equal to zero gives the equations 1) \(\sec{x} = 0\) and 2) \(\sec{x} - 4 = 0\). Solve these equations for \(x\).
03
Solve the first Equation
The first equation, \(\sec{x} = 0\), means that the cosine of \(x\) is undefined. In the interval \([0, 2\pi]\), there aren't any values for which cosine is undefined. Therefore, this equation has no solutions.
04
Solve the second Equation
The second equation, \(\sec{x} - 4 = 0\), means that the cosine of \(x\) equals 1/4. We first rewrite this equation as \(\cos{x} = 1/4\). One must use inverse cosine or reference to the unit circle to find \(x\). The solutions are then \(x = \cos^{-1}(1/4), x = 2\pi - \cos^{-1}(1/4)\).
05
Check the Validity of solutions
Check if the solutions obtained are within the interval [0,2Ï€]. Since \(\cos^{-1}(1/4)\) and \(2\pi - \cos^{-1}(1/4)\) are both in the interval [0,2Ï€], both are valid solutions. Therefore, the solutions to the equation are \(x = \cos^{-1}(1/4)\) and \(x = 2\pi - \cos^{-1}(1/4)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Secant Function
The secant function, commonly denoted as \( \sec{x} \), is one of the six fundamental trigonometric functions. It is defined as the reciprocal of the cosine function: \( \sec{x} = \frac{1}{\cos{x}} \). This implies that wherever the cosine function is zero, the secant is undefined.
Key points to remember about the secant function are:
Key points to remember about the secant function are:
- It is undefined at points where \( \cos{x} = 0 \).
- It only provides positive values in the first and fourth quadrants of the unit circle when both secant and cosine are positive.
- The range of the secant function is \(( -\infty, -1] \cup [1, \infty )\), as it takes values outside the range of cosine, which is \([-1, 1]\).
Solving Trigonometric Equations
When faced with an equation like \( \sec^2{x} - 4\sec{x} = 0 \), your first task is to manipulate it in a way that makes solving simpler. Factoring can take a complex equation and break it down into simpler components. Here, the equation factors into \( \sec{x}(\sec{x} - 4) = 0 \).
Next, set each factor equal to zero:
Next, set each factor equal to zero:
- \( \sec{x} = 0 \): This is impossible in the defined interval \([0, 2\pi]\), as secant (\( \sec{x} = \frac{1}{\cos{x}} \)) doesn't reach zero values.
- \( \sec{x} - 4 = 0 \): Solving gives \( \sec{x} = 4 \), which implies \( \cos{x} = \frac{1}{4} \).
Cosine Function
The cosine function, denoted as \( \cos{x} \), is integral in trigonometry. It's defined as the x-coordinate on the unit circle of an angle \(x\). Its range is \([-1, 1]\), and it exhibits even symmetry, meaning \( \cos{(-x)} = \cos{x} \).
Using the cosine function in solving equations involves a few steps. For example, translating the equation \( \sec{x} = 4 \) to \( \cos{x} = \frac{1}{4} \) allows you to apply inverse trigonometric functions to find specific angle solutions:
Using the cosine function in solving equations involves a few steps. For example, translating the equation \( \sec{x} = 4 \) to \( \cos{x} = \frac{1}{4} \) allows you to apply inverse trigonometric functions to find specific angle solutions:
- \( \cos^{-1}\left(\frac{1}{4}\right) \) gives you one angle within the interval.
- Due to the periodicity of cosine, another solution is \( 2\pi - \cos^{-1}\left(\frac{1}{4}\right) \), leveraging the even symmetry.