Chapter 5: Problem 60
Prove the identity.$$\cos \left(\frac{5 \pi}{4}-x\right)=-\frac{\sqrt{2}}{2}(\cos x+\sin x)$$
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Chapter 5: Problem 60
Prove the identity.$$\cos \left(\frac{5 \pi}{4}-x\right)=-\frac{\sqrt{2}}{2}(\cos x+\sin x)$$
These are the key concepts you need to understand to accurately answer the question.
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Verify the identity. $$\tan \frac{u}{2}=\csc u-\cot u$$$$\tan \frac{u}{2}=\csc u-\cot u$$
Find all solutions of the equation in the interval \(0,2 \pi) .\) Use a graphing utility to graph the equation and verify the solutions. $$\cos 2 x-\cos 6 x=0$$
Use the figure, which shows two lines whose equations are \(y_{1}=m_{1} x+b_{1}\) and \(y_{2}=m_{2} x+b_{2}\). Assume that both lines have positive slopes. Derive a formula for the angle between the two lines. Then use your formula to find the angle between the given pair of lines.\(y=x\) and \(y=\sqrt{3} x\).
Use inverse functions where needed to find all solutions of the equation in the interval \(\mathbf{0}, \mathbf{2} \boldsymbol{\pi}\) ). $$\sec ^{2} x+\tan x-3=0$$
(a) use a graphing utility to graph the function and approximate the maximum and minimum points on the graph in the interval \(\mathbf{0}, \mathbf{2} \boldsymbol{\pi}\) ), and (b) solve the trigonometric equation and demonstrate that its solutions are the \(x\) -coordinates of the maximum and minimum points of \(f .\) (Calculus is required to find the trigonometric equation.) $$\begin{array}{cc}\text{Function} && \text {Trigonometric Equation} \\\ f(x)=\sin ^{2} x+\cos x && 2 \sin x \cos x-\sin x=0 \end{array}$$
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