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Use trigonometric identities to transform the left side of the equation into the right side \((\mathbf{0} < \boldsymbol{\theta} < \pi \mathbf{2})\). $$(\sec \theta+\tan \theta)(\sec \theta-\tan \theta)=1$$

Short Answer

Expert verified
Therefore, using trigonometric identities, we have transformed the left side of the equation \( (\sec \theta+\tan \theta)(\sec \theta-\tan \theta)=1 \) into the right side, proving that the equation indeed equals 1 for all \(\theta\).

Step by step solution

01

Apply the Identity

We first need to put the equation \((\sec \theta+\tan \theta)(\sec \theta-\tan \theta)=1\) in the form of \(a^2 - b^2\) which is equivalent to \((a-b)(a+b)\). This falls under the difference of the squares identity.
02

Simplify

Applying the difference of squares, the left hand side expression becomes \(\sec^2 \theta - \tan^2 \theta\). This brings us to the next step where we have to apply another identity.
03

Apply Pythagorean Identity

We express \(\sec^2 \theta\) in terms of \(\tan^2 \theta\) using the Pythagorean Identity \(\sec^2 \theta = 1 + \tan^2 \theta\). Replacing \(\sec^2 \theta\) with \(1 + \tan^2 \theta\) in the equation we get \(1 + \tan^2 \theta - \tan^2 \theta\).
04

Simplify the Expression

This simplifies to 1 since \(\tan^2 \theta - \tan^2 \theta = 0\). So, the left side of the equation simplifies to 1 which is the same as the right side of the equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference of Squares
The difference of squares is a fundamental algebraic identity. It is represented by the pattern \(a^2 - b^2 = (a-b)(a+b)\). This identity is used to simplify expressions where two perfect squares are subtracted from each other. In our exercise, we began with \(\text{(\sec \theta+\tan \theta)(\sec \theta-\tan \theta)}\). Here, \((\sec \theta)^2\) and \((\tan \theta)^2\) are the perfect squares. Applying the difference of squares allows us to transform the expression into \(\sec^2 \theta - \tan^2 \theta\). This simplification is crucial for solving trigonometric problems, as it often leads to further reductions or reveals hidden identities. Mastering this concept will help you streamline calculations and understand the processes behind more complex expressions.
Pythagorean Identity
The Pythagorean Identity is a well-known equation in trigonometry. It states that for any angle \(\theta\), the identity \(\sec^2 \theta = 1 + \tan^2 \theta\) holds true. This identity is derived from the Pythagorean Theorem in geometry. In our specific problem, we used the Pythagorean Identity to substitute \(\sec^2 \theta\) within the expression \(\sec^2 \theta - \tan^2 \theta\).
  • By replacing \(\sec^2 \theta\) with \(1 + \tan^2 \theta\), we facilitate the process of simplification.
  • This identity is vital for solving trigonometric equations because it connects the relationships between secant and tangent functions.
Knowing how to apply this identity effectively can lead to quicker solutions and deeper insights into trigonometric principles. It plays a key role in proof techniques and simplification processes in trigonometry.
Trigonometric Simplification
Trigonometric simplification involves rewriting trigonometric expressions in a more straightforward or alternative form. The aim is to make the expression easier to handle or to compare it with another expression. In this exercise, we began with a complex expression on the left side of the equation and successfully simplified it down to 1, matching the right side of the equation.
  • The initial step was employing the difference of squares to reduce the complexity by dealing with squared terms.
  • Next, the Pythagorean identity was utilized to further simplify the equation by substituting equivalent expressions.
Simplification helps reveal equalities that are not immediately apparent and allows for solving equations more efficiently. Practicing simplification techniques improves problem-solving skills and enhances understanding of the intricacies of trigonometry.

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Most popular questions from this chapter

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