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Use trigonometric identities to transform the left side of the equation into the right side \((\mathbf{0} < \boldsymbol{\theta} < \pi \mathbf{2})\). $$(1+\sin \theta)(1-\sin \theta)=\cos ^{2} \theta$$

Short Answer

Expert verified
The left-hand side of the equation can be transformed into the right-hand side by first expanding it, then substituting \( \sin^{2}\theta \) using the Pythagorean identity, and finally, simplifying the result. The result \( \cos^{2}\theta \) confirms the correctness of the steps.

Step by step solution

01

Expand the Left Hand Side

Start by expanding the left hand side of the equation: \( (1+\sin\theta)(1-\sin\theta) \) using the distributive law of multiplication results in \( 1 - \sin^{2}\theta \)
02

Apply the Pythagorean Identity

Next, apply the Pythagorean identity \( \sin^{2}\theta + \cos^{2}\theta = 1 \). Solving for \( \sin^{2}\theta \) gives \( \sin^{2}\theta = 1 - \cos^{2}\theta \). Thus, the left side of the equation becomes \( 1 - (1 - \cos^{2}\theta) \)
03

Simplify the Result

Simplifying the left side gives \( 1 - 1 + \cos^{2}\theta \), which simplifies further to \( \cos^{2}\theta \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean Identity
The Pythagorean identity is a fundamental component in the field of trigonometry. It states that for any angle \( \theta \) in a right-angled triangle, the square of sine of that angle plus the square of cosine of that angle equals one, expressed as \( \sin^2\theta + \cos^2\theta = 1 \). This relationship emerges from the Pythagorean theorem applied to the unit circle, where the hypotenuse is always 1. Understanding this identity is crucial because it enables you to express one trigonometric function entirely in terms of another, simplifying complex equations.

For example, if you know the value of \( \sin\theta \), you can find \( \cos\theta \) without needing additional information about the angle \( \theta \). The Pythagorean identity is particularly useful in transforming and solving trigonometric equations. As illustrated in the exercise, by recognizing that \( 1 - \sin^2\theta \) is equivalent to \( \cos^2\theta \) through this identity, the equation simplifies elegantly to its desired form.
Solving Trigonometric Equations
Solving trigonometric equations can often be a challenging endeavor, but with a solid understanding of trigonometric identities, it becomes much more approachable. The process typically involves manipulating the equation using these identities to isolate the trigonometric function of interest.

When solving an equation such as \( (1+\sin\theta)(1-\sin\theta) = \cos^2\theta \), it's beneficial to look for patterns that suggest the use of a particular identity. Expanding expressions and looking for common trigonometric forms can reveal how you can apply specific identities to progress towards a solution. Importantly, not all trigonometric equations have a single solution; some may have multiple solutions, especially considering the periodic nature of trigonometric functions. It's also vital to pay attention to the domain restriction, as it can limit the range of acceptable solutions for \( \theta \).
Trigonometric Functions
Trigonometric functions are a class of functions that relate the angles of a triangle to the ratios of its sides. The three primary trigonometric functions are sine (sin), cosine (cos), and tangent (tan), each representing different angle-to-side ratios in a right triangle. These functions are essential in various fields, from physics to engineering, and are the basis for more complex trigonometric equations.

The sine function relates the length of the opposite side to the hypotenuse of a right triangle. In contrast, the cosine function correlates to the adjacent side and the hypotenuse. The tangent function is the ratio of the sine to the cosine of an angle. Other functions, such as secant (sec), cosecant (csc), and cotangent (cot), are reciprocals of cosine, sine, and tangent, respectively. These functions are periodic and exhibit specific patterns on a graph, allowing them to model cyclical phenomena in real-world applications.

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Most popular questions from this chapter

For the simple harmonic motion described by the trigonometric function, find (a) the maximum displacement, (b) the frequency, (c) the value of \(d\) when \(t=5,\) and (d) the least positive value of \(t\) for which \(d=0 .\) Use a graphing utility to verify your results. $$d=9 \cos \frac{6 \pi}{5} t$$

A ship leaves port at noon and has a bearing of \(\mathrm{S} 29^{\circ} \mathrm{W}\). The ship sails at 20 knots. (a) How many nautical miles south and how many nautical miles west will the ship have traveled by 6: 00 P.M.? (b) At 6: 00 P.M., the ship changes course to due west. Find the ship's bearing and distance from the port of departure at 7: 00 P.M.

Polynomial Approximations Using calculus, it can be shown that the sine and cosine functions can be approximated by the polynomials $$\sin x \approx x-\frac{x^{3}}{3 !}+\frac{x^{5}}{5 !}$$ and $$\cos x \approx 1-\frac{x^{2}}{2 !}+\frac{x^{4}}{4 !}$$ where \(x\) is in radians. (a) Use a graphing utility to graph the sine function and its polynomial approximation in the same viewing window. How do the graphs compare? (b) Use the graphing utility to graph the cosine function and its polynomial approximation in the same viewing window. How do the graphs compare? (c) Study the patterns in the polynomial approximations of the sine and cosine functions and predict the next term in each. Then repeat parts (a) and (b). How did the accuracy of the approximations change when an additional term was added?

Graph \(f\) and \(g\) in the same coordinate plane. Include two full periods. Make a conjecture about the functions. $$f(x)=\sin x, \quad g(x)=-\cos \left(x+\frac{\pi}{2}\right)$$

Use a graphing utility to graph the function. Describe the behavior of the function as \(x\) approaches zero. $$h(x)=x \sin \frac{1}{x}$$

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