/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Use the given function value(s) ... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the given function value(s) and the trigonometric identities to find the indicated trigonometric functions. $$\cos \beta=\frac{\sqrt{7}}{4}$$ (a) \(\sec \beta\) (b) \(\sin \beta\) (c) \(\cot \beta\) (d) \(\sin \left(90^{\circ}-\beta\right)\)

Short Answer

Expert verified
(a) \( \sec \beta = \frac{4\sqrt{7}}{7}\) , (b) \( \sin \beta = \frac{3}{4}\), (c) \( \cot \beta = \frac{\sqrt{7}}{3}\), (d) \( \sin (90^{\circ} - \beta) = \frac{\sqrt{7}}{4}\)

Step by step solution

01

Find the secant of beta (\(\sec \beta\))

Secant is the reciprocal of cosine. Therefore, \(\sec \beta\) = \( \frac{1}{ \cos \beta }\). Substitute for \(\cos \beta\), hence \(\sec \beta\) = \( \frac{1}{ \frac{\sqrt{7}}{4} }\) which simplifies to \( \frac{4}{\sqrt{7}}\). Rationalize the denominator to obtain \( \sec \beta = \frac{4\sqrt{7}}{7}\) as the final answer.
02

Find the sine of beta (\(\sin \beta\))

Recall the Pythagorean identity \(\sin^2 \beta = 1- \cos^2 \beta\). Substitute the value of \(\cos \beta\), hence \(\sin \beta = \sqrt{1- \left( \frac{\sqrt{7}}{4} \right)^2}\). Upon simplification you get \( \sin \beta = \frac{\sqrt{9}}{4} = \frac{3}{4}\).
03

Find the cotangent of beta (\(\cot \beta\))

Cotangent is the reciprocal of tangent. Also, tangent is \( \frac{\sin \beta}{\cos \beta}\). Therefore, \(\cot \beta = \frac{ \cos \beta}{\sin \beta}\). Substitute the values of \(\cos \beta\) and \(\sin \beta\) which were found earlier to get \(\cot \beta = \frac{\frac{\sqrt{7}}{4}}{\frac{3}{4}} = \frac{\sqrt{7}}{3}\).
04

Find the sine of (90 degrees - beta) (\(\sin \left(90^{\circ}-\beta\right)\)

Always remember that \(\sin(90^{\circ} - X) = \cos X\). So, \(\sin (90^{\circ} - \beta) = \cos \beta \). Substituting the value of \(\cos \beta\), \(\sin (90^{\circ} - \beta) = \frac{\sqrt{7}}{4} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Secant Function
The secant function, often represented as \( \sec \theta \), is a trigonometric function that is the reciprocal of the cosine function. This means that \( \sec \theta = \frac{1}{\cos \theta} \). Understanding this relationship is essential when calculating secant values from known cosine values.
In the given exercise, you start with \( \cos \beta = \frac{\sqrt{7}}{4} \). To find \( \sec \beta \), you take the reciprocal: \( \sec \beta = \frac{1}{\frac{\sqrt{7}}{4}} \).
This simplifies to \( \frac{4}{\sqrt{7}} \). To present it in a more standard form, rationalize the denominator to get \( \sec \beta = \frac{4\sqrt{7}}{7} \).
This method is one of the key applications of the reciprocal identities in trigonometry, allowing you to transform the cosine function into a secant function efficiently.
  • Reciprocal of cosine gives secant.
  • Simplification and rationalization are crucial steps.
  • Key for converting between these two functions.
Sine Function
The sine function, represented as \( \sin \theta \), is another fundamental trigonometric function. It describes the ratio of the opposite side to the hypotenuse in a right triangle. Knowing one of the angles and using trigonometric identities can help you find the sine of an angle.
The Pythagorean identity, \( \sin^2 \theta + \cos^2 \theta = 1 \), is particularly useful. For this problem, we focus on \( \sin^2 \beta = 1 - \cos^2 \beta \). By substituting \( \cos \beta = \frac{\sqrt{7}}{4} \), you solve for \( \sin \beta \).
After simplification, you get \( \sin \beta = \sqrt{1 - (\frac{\sqrt{7}}{4})^2} = \frac{\sqrt{9}}{4} = \frac{3}{4} \). This accurate calculation is crucial for using other trigonometric functions.
  • Remember, \( \, \sin^2 \beta = 1 - \cos^2 \beta \).
  • Carefully substitute and simplify for precise results.
Cotangent Function
The cotangent function, denoted as \( \cot \theta \), is the reciprocal of the tangent function, which means \( \cot \theta = \frac{1}{\tan \theta} \). Tangent is defined as the ratio of the sine of an angle to the cosine of the same angle, \( \tan \theta = \frac{\sin \theta}{\cos \theta} \). Therefore, \( \cot \theta = \frac{\cos \theta}{\sin \theta} \).
In this exercise, you have \( \cos \beta = \frac{\sqrt{7}}{4} \) and \( \sin \beta = \frac{3}{4} \).
Using these values, \( \cot \beta = \frac{(\frac{\sqrt{7}}{4})}{(\frac{3}{4})} = \frac{\sqrt{7}}{3} \). Understanding the reciprocal relationship and the ability to use known sine and cosine values simplifies the computation of cotangent values.
  • Cotangent = reciprocal of tangent.
  • Direct calculation from known sine and cosine values.
Pythagorean Identity
The Pythagorean identity is a cornerstone of trigonometry, stating that for any angle \( \theta \), \( \sin^2 \theta + \cos^2 \theta = 1 \). This identity can be manipulated to find missing values of sine or cosine when one is known.
In the original exercise, this identity helps find \( \sin \beta \) when \( \cos \beta = \frac{\sqrt{7}}{4} \) is given. You rearrange it to \( \sin^2 \beta = 1 - \cos^2 \beta \), allowing you to substitute known values and solve for \( \sin \beta \).
This identity not only helps in computing basic trigonometric functions but also plays a vital role in transformations and solving trigonometric equations involving angles. It bridges between different trigonometric functions and simplifies complex calculations in geometry and calculus.
  • Extremely useful for finding complementary values in trigonometry.
  • Transforms and unifies various trigonometric expressions.

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