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Describe the relationship between the graphs of \(f\) and \(g .\) Consider amplitude, period, and shifts. $$\begin{array}{l} f(x)=\cos 4 x \\ g(x)=-2+\cos 4 x \end{array}$$

Short Answer

Expert verified
The functions \(f(x)\) and \(g(x)\) have the same amplitude of 1 and the same period of \( \pi / 2\). The function \(g(x)\) is shifted down 2 units compared to \(f(x)\)

Step by step solution

01

Understanding Amplitude

The amplitude of a cosine function is the absolute value of the coefficient of \(cos(x)\), which represents the maximum displacement from its mean position. In \(f(x)=cos 4x\), the amplitude is 1 since the coefficient of \(cos(x)\) is 1. In \(g(x)=-2+cos4x\), the amplitude is also 1, because the coefficient of \(cos(x)\) is still 1, so maximum displacement from its mean position is also 1.
02

Understanding Period

The period of a cosine function is the value \(2 \pi\) divided by the absolute value of the coefficient of \(x\), which represents the length of one full cycle. In both \(f(x)=cos 4x\) and \(g(x)=-2+cos 4x\), the period is \(2 \pi / 4 = \pi / 2\), because the coefficient of \(x\) in the cosine function is 4.
03

Understanding Vertical Shifts

A vertical shift is the addition of a constant to the function, which shifts the function upward or downward. In \(f(x)=cos 4x\), there is no vertical shift, because there is no constant added or subtracted from the function. However, in \(g(x)=-2+cos4x\), there is a vertical shift of -2, because the constant -2 is added to the function, shifting the entire graph downwards by 2 units.
04

Summary of Comparison

So the relationship between \(f(x)\) and \(g(x)\) is that they have the same amplitude and period, but \(g(x)\) is shifted down 2 units compared to \(f(x)\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amplitude of Cosine Function
The amplitude of a cosine function is a key concept that helps us understand how 'tall' and 'deep' the function's graph will be. It is defined as the absolute value of the coefficient that precedes the cosine term. To put it simply, if you have a function like \(f(x) = A \cdot \cos(Bx)\), the amplitude would be \(A\).

Let's look at the given exercise's function \(f(x) = \cos(4x)\). The coefficient of the cosine term is 1 (since it's not explicitly written, but understood to be there). Therefore, the amplitude of \(f\) is 1. This means the graph will reach 1 unit at its highest and -1 unit at its lowest from the centerline of the graph. For \(g(x) = -2 + \cos(4x)\), the amplitude remains the same since the coefficient in front of the cosine term is still 1. Despite the vertical shift, which we will touch on later, this does not affect the amplitude.
Period of Cosine Function
The period of a cosine function describes the length of one complete cycle of the wave before it begins to repeat itself. To determine the period of a cosine function with the general form \(y = A\cos(Bx+C)+D\), we use the formula \(\frac{2\pi}{|B|}\).

In the functions \(f(x) = \cos(4x)\) and \(g(x) = -2 + \cos(4x)\), we can see that the coefficient \(B\) is 4. Therefore, the period for both functions is \(\frac{2\pi}{4} = \frac{\pi}{2}\). This signifies that both graphs complete a cycle every \(\frac{\pi}{2}\) radians. For students to truly understand how period impacts the graph, imagining or sketching the function on the coordinate system helps. It reveals how quickly the waves of the cosine function rise and fall within a 360° span (or \(2\pi\) radians).
Vertical Shifts in Trigonometry
Vertical shifts move the graph of a trigonometric function up or down on the coordinate plane. This shift is noted by a constant added or subtracted from the function. If we have \(y = A\cos(Bx+C)+D\), \(D\) determines the vertical shift. A positive value moves the graph upwards, while a negative value moves it downwards.

Comparing our functions, \(f(x)\) has no vertical shift, while \(g(x) = -2 + \cos(4x)\) introduces a shift of -2. This downward shift takes the entire graph of \(f(x)\) and simply moves it down 2 units, altering its vertical position but not its shape. Understanding vertical shifts is crucial for students as it allows them to easily adjust the basic cosine graph to fit transformed functions, like \(g(x)\), without altering their amplitude or period.

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Most popular questions from this chapter

Consider the function \(f(x)=x-\cos x\) (a) Use a graphing utility to graph the function and verify that there exists a zero between 0 and 1 . Use the graph to approximate the zero. (b) Starting with \(x_{0}=1,\) generate a scquence \(x_{1}, x_{2}\) \(x_{3}, \ldots,\) where \(x_{n}=\cos \left(x_{n-1}\right) .\) For example, \(x_{0}=1\) \(x_{1}=\cos \left(x_{0}\right)\) \(x_{2}=\cos \left(x_{1}\right)\) \(x_{3}=\cos \left(x_{2}\right)\) \(\vdots\) What value does the sequence approach?

After exercising for a few minutes, a person has a respiratory cycle for which the velocity of airflow is approximated by $$v=1.75 \sin \frac{\pi t}{2}$$ where \(t\) is the time (in seconds). (Inhalation occurs when \(v > 0,\) and exhalation occurs when \(v < 0 .\) ) (a) Find the time for one full respiratory cycle. (b) Find the number of cycles per minute. (c) Sketch the graph of the velocity function.

A photographer is taking a picture of a three-foot-tall painting hung in an art gallery. The camera lens is 1 foot below the lower edge of the painting (see figure). The angle \(\beta\) subtended by the camera lens \(x\) feet from the painting is given by $$\beta=\arctan \frac{3 x}{x^{2}+4}, \quad x>0$$ (a) Use a graphing utility to graph \(\beta\) as a function of \(x .\) (b) Move the cursor along the graph to approximate the distance from the picture when \(\beta\) is maximum. (c) Identify the asymptote of the graph and discuss its meaning in the context of the problem.

Use a graphing utility to graph the function. $$f(x)=2 \arccos (2 x)$$

Fill in the blank. If not possible, state the reason. As \(x \rightarrow-1^{+},\) the value of arccos \(x \rightarrow\) \(\square\).

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