/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Evaluate (if possible) the six t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate (if possible) the six trigonometric functions at the real number. $$t=5 \pi / 6$$

Short Answer

Expert verified
The six trigonometric function values for \(t= \frac{5Ï€}{6}\) are: \(\sin = \frac{1}{2}, \cos = -\frac{\sqrt{3}}{2}, \tan = -\sqrt{3}, \csc = 2, \sec = -2\sqrt{3}, \cot = -\frac{\sqrt {3}}{3}\).

Step by step solution

01

Calculate Sine

Sine (sin) for the given angle can be found as follows: Firstly, identify the corresponding y-coordinate from the unit circle for the point at \(\frac{5Ï€}{6}\). The y-coordinate gives us the value of sine. For this case, \(\sin(\frac{5Ï€}{6}) = \frac{1}{2}\).
02

Calculate Cosine

Cosine (cos) is the x-coordinate on the unit circle for the given angle. The x-coordinate for the point at \(\frac{5Ï€}{6}\) is \(-\frac{\sqrt {3}}{2}\). Hence, \(\cos(\frac{5Ï€}{6}) = -\frac{\sqrt {3}}{2}\).
03

Calculate Tangent

The tangent (tan) can be calculated as the ratio of sine to cosine. Therefore, \(\tan(\frac{5Ï€}{6}) = \frac{\sin(\frac{5Ï€}{6})}{\cos(\frac{5Ï€}{6})} = \frac{\frac{1}{2}}{-\frac{\sqrt{3}}{2}} = -\frac{1}{\sqrt{3}} = -\sqrt{3}\).
04

Calculate Cosecant

Cosecant (csc) is the reciprocal of sine. Therefore, \(\csc(\frac{5Ï€}{6}) = \frac{1}{\sin(\frac{5Ï€}{6})} = \frac{1}{\frac{1}{2}} = 2.\)
05

Calculate Secant

Secant (sec) is the reciprocal of cosine. Therefore, \(\sec(\frac{5Ï€}{6}) = \frac{1}{\cos(\frac{5Ï€}{6})} = \frac{1}{- \frac{\sqrt {3}}{2}} = -\frac{2}{\sqrt {3}} = -2\sqrt{3}\).
06

Calculate Cotangent

Cotangent (cot) is the reciprocal of tangent. Therefore, \(\cot(\frac{5Ï€}{6}) = \frac{1}{\tan(\frac{5Ï€}{6})} = \frac{1}{-\sqrt {3}} = -\frac{1}{\sqrt {3}} = -\frac{\sqrt {3}}{3}.\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Circle
The unit circle is a fundamental concept in trigonometry. It's a circle with a radius of 1 unit, centered at the origin (0,0) on the coordinate plane. The unit circle allows us to define all the trigonometric functions for any angle in a very intuitive way.

When we talk about an angle on the unit circle, like the example of \(t=5\pi/6\), we're referring to the standard position where the angle's vertex is at the origin, one side lies on the positive x-axis, and the other side is rotated counterclockwise.

The x-coordinate of any point on the unit circle represents the cosine of that angle, while the y-coordinate represents the sine. This is fundamental in explaining why \(\cos(5\pi/6)=-\frac{\sqrt{3}}{2}\) and \(\sin(5\pi/6)=\frac{1}{2}\).
Sine and Cosine
The sine and cosine functions are the most basic trigonometric functions. They can be easily understood using the unit circle.

Sine (\(\sin\)) of an angle is the y-coordinate of the point where the terminal side of the angle intersects the unit circle. In our example, \(\sin(5\pi/6)\) yields \(\frac{1}{2}\), indicating the point's height above the x-axis.

Cosine (\(\cos\)) of an angle is the x-coordinate of the same point on the unit circle. This represents the horizontal distance to the y-axis. For the angle \(5\pi/6\), the cosine is \(\cos(5\pi/6)=-\frac{\sqrt{3}}{2}\), reflecting the point's position to the left of the y-axis.
Tangent and Cotangent
The functions of tangent (\(\tan\)) and cotangent (\(\cot\)) round out the primary trigonometric functions and are related to sine and cosine.

For any angle, tangent is the ratio of sine over cosine. In practical terms, it represents the slope of the line created by the angle on the unit circle. For our angle \(5\pi/6\), we have \(\tan(5\pi/6)=-\sqrt{3}\), which suggests a downward sloping line.

The cotangent function is simply the reciprocal of tangent. That is, \(\cot(x) = 1/\tan(x)\). For our example, \(\cot(5\pi/6)=-\frac{\sqrt{3}}{3}\), indicating a gentler negative slope compared to the tangent.
Secant and Cosecant
The secant (\(\sec\)) and cosecant (\(\csc\)) functions are often less intuitive as they don't directly relate to the coordinate axes like sine and cosine.

Secant is the reciprocal of the cosine, and for an angle on the unit circle, it can be seen as the distance from a point on the circle to the x-axis along a line that intersects the circle and the origin. For angle \(5\pi/6\), we find \(\sec(5\pi/6) = -2\sqrt{3}\), denoting this distance in the negative direction on the x-axis.

Cosecant is similarly defined as the reciprocal of the sine. It measures the distance from the circle to the y-axis along a line from the origin. Hence, \(\csc(5\pi/6) = 2\), indicating twice the unit circle radius above the x-axis.
Radians
In trigonometry, angles can be measured in degrees or radians. Radians provide a more natural way of expressing angles in terms of circle measurements, because they relate the arc length to the radius of the circle.

There are \(2\pi\) radians in a full circle, which equals 360 degrees. This means that \(\pi\) radians are equivalent to 180 degrees. The given angle in the exercise, \(5\pi/6\), can thus be understood as 5/6 of the way from 0 to \(\pi\), or equivalently, 5/6 of 180 degrees, which is 150 degrees.

When working with radians, the trigonometric functions can be directly applied to the unit circle, providing a seamless connection between the angle measurement and the coordinates used to determine the function values.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The numbers of hours \(H\) of daylight in Denver, Colorado, on the 15 th of each month are: \(1(9.67), 2(10.72), 3(11.92), 4(13.25)\) \(5(14.37), \quad 6(14.97), \quad 7(14.72), \quad 8(13.77), \quad 9(12.48)\) \(10(11.18), \quad 11(10.00), \quad 12(9.38) . \quad\) The month is represented by \(t,\) with \(t=1\) corresponding to January. A model for the data is $$H(t)=12.13+2.77 \sin \left(\frac{\pi t}{6}-1.60\right)$$. (a) Use a graphing utility to graph the data points and the model in the same viewing window. (b) What is the period of the model? Is it what you expected? Explain. (c) What is the amplitude of the model? What does it represent in the context of the problem? Explain.

For the simple harmonic motion described by the trigonometric function, find (a) the maximum displacement, (b) the frequency, (c) the value of \(d\) when \(t=5,\) and (d) the least positive value of \(t\) for which \(d=0 .\) Use a graphing utility to verify your results. $$d=\frac{1}{2} \cos 20 \pi t$$

The displacement from equilibrium of an oscillating weight suspended by a spring is given by \(y(t)=2 \cos 6 t,\) where \(y\) is the displacement (in centimeters) and \(t\) is the time (in seconds). Find the displacement when (a) \(t=0,\) (b) \(t=\frac{1}{4}\) and \((\mathrm{c}) t=\frac{1}{2}.\)

Use a graphing utility to graph the function. $$f(x)=\pi-\sin ^{-1}\left(\frac{2}{3}\right)$$

Fill in the blank. If not possible, state the reason. As \(x \rightarrow-1^{+},\) the value of arcsin \(x \rightarrow\) \(\square\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.