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Use a graphing utility to graph the exponential function. $$s(t)=3 e^{-0.2 t}$$

Short Answer

Expert verified
The exponential function \(s(t)=3 e^{-0.2 t}\) represents an exponential decay. The '3' is the initial value and '-0.2' is the rate of decay. The graph will start from point (0,3) and descend gradually towards zero as \(t\) increases.

Step by step solution

01

Understanding the function

First, let's understand the given exponential function \(s(t)=3 e^{-0.2 t}\). The function is an example of exponential decay because the exponent of \(e\) is negative. The '3' represent the initial value, which is when \(t=0\) the value of \(s(t)\) is 3. The '0.2' is the rate of decay.
02

Algebraic manipulation

Before graphing, Rewrite the function so that it's easier to understand the decay effect. Rewrite given function as \(s(t)=3 e^{-0.2 t}\) to \(s(t)=3 (1/e^{0.2t})\). Now, one can see that for each 1 unit increase in \(t\), the quantity 's(t)' is divided by approximately \(e\^{0.2}\), representing a decay.
03

Graphing function

Now, plot the graph using the graphing utility by entering the function in the specific format requested by your graphing tool. For the x-axis use 't' and for the y-axis use 's(t)'. The graph will descend gradually from a starting point of 3 when \(t = 0\) towards zero as \(t\) increases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Function
An exponential function is a powerful tool in mathematics used to model situations where growth or decay is constant relative to the current amount. The function is of the form \( y = ab^{x} \) where \( a \) is the initial value, \( b \) is the base, and \( x \) is the exponent. When the base \( b \) is greater than 1, we observe exponential growth, while a base \( b \) between 0 and 1 leads to exponential decay. The function \( s(t)=3e^{-0.2t} \) from the exercise shows decay since the base, \( e^{-0.2} \) is less than 1. The constant \( 3 \) signifies the starting value of the function at time \( t=0 \).

Understanding how to manipulate and graph these functions is essential in various fields such as finance, biology, and physics, where they describe phenomena like radioactive decay, population growth, or investment growth.
Exponential Decay
Exponential decay describes a process where quantities decrease over time at a rate proportional to their current value. This rate of decay is constant and can be seen in the exercise through the function \( s(t) = 3e^{-0.2t} \), where \( -0.2 \) is the decay rate. Unlike linear decay, which decreases by the same amount over equal time intervals, exponential decay becomes progressively slower as time passes, approaching zero but never quite reaching it. This concept is illustrated in real-world scenarios such as cooling of a hot object or depreciation of a car's value. Graphing these functions helps visualize this diminishing behavior and is key in predicting long-term trends.
Graphing Utility
A graphing utility, such as a graphing calculator or software, transforms complex equations into visual graphs. This visual representation makes it easier to understand the behavior of functions, especially exponential ones with their rapid increases or decreases. To graph an exponential decay function effectively using a graphing utility, you must correctly input the equation and choose appropriate scales for the axes to capture the nature of the decay. For the function \( s(t) = 3e^{-0.2t} \), a graphing utility would depict a curve starting at \( s(0) = 3 \) and approaching zero as \( t \) increases. This visualization is particularly helpful for students to grasp how the function behaves without relying solely on the abstract formula.
Algebraic Manipulation
Algebraic manipulation is the process of rearranging and simplifying algebraic expressions to make them clearer or easier to work with. In the context of the given exercise, the algebraic manipulation involved rewriting the exponential decay function \( s(t) = 3e^{-0.2t} \) as \( s(t) = 3(1/e^{0.2t}) \). This small adjustment helps to highlight the decay aspect of the function, indicating that the value of \( s(t) \) reduces by a factor of approximately \( e^{0.2} \) for each unit increase in \( t \). Manipulation skills are vital for algebraic interpretation, problem-solving, and in this case, revealing the exponential decay in a form that is easier to digest for graphing and analysis.

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