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Write the quadratic function $$f(x)=a x^{2}+b x+c$$ in standard form to verify that the vertex occurs at $$\left(-\frac{b}{2 a}, f\left(-\frac{b}{2 a}\right)\right)$$

Short Answer

Expert verified
The verification is successful. The vertex of the quadratic function \(f(x) = ax^2 + bx + c\) is indeed at \(\left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)\)

Step by step solution

01

Express the Quadratic in Terms of x^2 and Rest

First express \(f(x)\) in terms of \(x^2\) and rest, like this: \(f(x) = ax^2 + bx + c = a(x^2 + \frac{b}{a}x) + c\)
02

Complete the Square

The next step is to complete the square. This is done by taking half of the coefficient of x, squaring it and adding it inside the parenthesis and subtracting it outside to maintain equality. So we have: \(f(x) = a \left(x^2 + \frac{b}{a}x + \left(\frac{b}{2a}\right)^2 \right) + c - a \left( \frac{b}{2a} \right)^2 = a \left(x + \frac{b}{2a}\right)^2 + \left( c - \frac{b^2}{4a} \right)\)
03

Identify the Vertex

From the standard form that we obtained we have \(h = -\frac{b}{2a}\) and \(k = c - \frac{b^2}{4a}\). Hence, the vertex of the parabolic function \(f(x)\) is at \(\left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Completing the Square
Completing the square is a mathematical technique used to convert a quadratic expression into a perfect square trinomial. This method simplifies the function and makes it easier to identify its properties. A quadratic expression is generally of the form \(ax^2 + bx + c\). By completing the square, we rewrite it in a way that highlights the vertex form \(a(x-h)^2 + k\), which is useful for graphing and analysis.

To complete the square, we start by isolating the \(x^2\) and \(x\) terms, like \(x^2 + \frac{b}{a}x\). Next, we take half of the coefficient of \(x\), square it, and add it inside the parentheses. We also subtract it outside to preserve equality. This transforms the quadratic into a perfect square trinomial.
  • This results in the expression \(a\left(x + \frac{b}{2a}\right)^2\)
  • Subsequently, adjust the constant term by subtracting \(a\left(\frac{b}{2a}\right)^2\)
Completing the square helps in identifying the vertex of the quadratic function easily and is a crucial step for converting to vertex form.
Quadratic Functions
Quadratic functions are polynomial functions of degree two, and they have the general form \(f(x) = ax^2 + bx + c\). These functions graph as parabolas, which are symmetrical, U-shaped curves.

Each quadratic function has important characteristics that are defined by its coefficients. Here are the key features:
  • **The leading coefficient \(a\)** determines the direction of the parabola. If \(a > 0\), the parabola opens upwards, and if \(a < 0\), it opens downwards.
  • **The vertex** is the highest or lowest point on the graph, depending on the orientation of the parabola. It can be found using the vertex form \((h, k)\).
  • **The axis of symmetry** is a vertical line passing through the vertex, given by \(x = -\frac{b}{2a}\).
Quadratic functions can be solved graphically and algebraically. Understanding the structure of these functions aids in graph interpretation and problem-solving efficiency.
Vertex of a Parabola
The vertex of a parabola is a crucial point that defines its direction and position. For quadratic functions, the vertex can be determined directly from the function's vertex form, or by completing the square.

In the function \(f(x) = ax^2 + bx + c\), the vertex can be found using the formula \((-\frac{b}{2a}, f(-\frac{b}{2a}))\). This formula gives us two components:
  • **The x-coordinate \( h = -\frac{b}{2a} \)**, which defines the parabola's axis of symmetry.
  • **The y-coordinate**, determined by substituting \(h\) back into the quadratic function.
The vertex is important for graphing since it allows us to pinpoint the extremum of the parabola—either a maximum or minimum.

Once you can efficiently find the vertex, graphing a quadratic function becomes much more straightforward. This step simplifies understanding the parabola's shape and direction, enhancing problem-solving capabilities.

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Most popular questions from this chapter

Use synthetic division to verify the upper and lower bounds of the real zeros of \(f\) \(f(x)=x^{3}-4 x^{2}+1\) (a) Upper: \(x=4\) (b) Lower: \(x=-1\)

Use a graphing utility to graph the quadratic function. Identify the vertex, axis of symmetry, and \(x\) -intercept(s). Then check your results algebraically by writing the quadratic function in standard form. $$f(x)=x^{2}+10 x+14$$

Use a graphing utility to graph the quadratic function. Identify the vertex, axis of symmetry, and \(x\) -intercept(s). Then check your results algebraically by writing the quadratic function in standard form. $$g(x)=x^{2}+8 x+11$$

Write the quadratic function in standard form and sketch its graph. Identify the vertex, axis of symmetry, and \(x\) -intercept(s). $$f(x)=\frac{1}{4} x^{2}-2 x-12$$

You want to make an open box from a rectangular piece of material, 15 centimetres by 9 centimetres, by cutting equal squares from the corners and turning up the sides. (a) Let \(x\) represent the side length of each of the squares removed. Draw a diagram showing the squares removed from the original piece of material and the resulting dimensions of the open box. (b) Use the diagram to write the volume \(V\) of the box as a function of \(x .\) Determine the domain of the function. (c) Sketch the graph of the function and approximate the dimensions of the box that will yield a maximum volume. (d) Find values of \(x\) such that \(V=56 .\) Which of these values is a physical impossibility in the construction of the box? Explain.

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