/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Use the Quadratic Formula to sol... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the Quadratic Formula to solve the quadratic equation.$$x^{2}-2 x+2=0$$.

Short Answer

Expert verified
The solutions of the equation \(x^{2}-2x+2=0\) are complex: \(x= 1+i\) and \(x= 1-i\).

Step by step solution

01

Identifying coefficients

The equation \(x^{2}-2x+2=0\) is of the form \(ax^{2}+bx+c=0\). Equating coefficients, we get \(a=1\), \(b=-2\), and \(c=2\).
02

Calculating the Discriminant

The discriminant is calculated as \(b^{2}-4ac\). Substituting the values we get: \((-2)^{2}-4*1*2 = 4 - 8 = -4\).
03

Applying the Quadratic Formula

The roots of the equation can be found using the quadratic formula: \[x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a} \]. Substituting the given values we get: \[x = \frac{2 \pm \sqrt{-4}}{2}\]. The square root of a negative number is imaginary, so the roots of the equation will be complex. Thus, \[x= 1 \pm i\].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Quadratic Equations
Solving quadratic equations is a fundamental concept in algebra that any student needs to master. A quadratic equation is typically in the form of ax^2 + bx + c = 0, where a, b, and c are constants, and a ≠ 0. The solutions to these equations are known as the 'roots' of the equation and can be real or complex numbers.

To solve a quadratic equation, one standard method is to apply the Quadratic Formula:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This formula provides a direct way to calculate the roots by simply substituting the coefficients a, b, and c from the equation. However, the formula only yields real roots when the discriminant—b^2 - 4ac—is non-negative. If the discriminant is negative, the equation has complex roots, which brings us to our next concept.
Finding Complex Roots
When it comes to quadratic equations with negative discriminants, their solutions are not real numbers but complex numbers. Complex numbers include both a real part and an imaginary part, which is linked to the square root of negative one (i).

Following the Quadratic Formula, if our discriminant (b^2 - 4ac) is negative, the expression under the square root becomes a negative number. As in our example, taking the square root of a negative number - in this case, -4 - gives us complex roots:
\[1 \pm i\]
Here, 1 represents the real part, and ±¾± represents the imaginary part of the complex roots. With the understanding of complex numbers, students can expand their abilities to solve a wider array of algebraic equations.
Calculating the Discriminant
The discriminant of a quadratic equation is the part of the Quadratic Formula under the square root: b^2 - 4ac. It is a powerful determinant that reveals the nature and number of roots without solving the equation.

Here's what the discriminant tells us:
  • If b^2 - 4ac > 0, there are two distinct real roots.
  • If b^2 - 4ac = 0, there is exactly one real root (also known as a repeated or double root).
  • If b^2 - 4ac < 0, there are two complex roots, which are conjugates of each other.

For example, the discriminant of the equation x^2 - 2x + 2 = 0 is -4, indicating that its roots are complex. This critical step in the problem-solving process not only provides insight into the type of solutions to anticipate but also equips students with a deeper understanding of quadratic relationships and their graphical representations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the quadratic function in standard form and sketch its graph. Identify the vertex, axis of symmetry, and \(x\) -intercept(s). $$f(x)=x^{2}-x+\frac{5}{4}$$

An indoor physical fitness room consists of a rectangular region with a semicircle on each end. The perimeter of the room is to be a 200 -meter single-lane running track. (a) Draw a diagram that gives a visual representation of the problem. Let \(x\) and \(y\) represent the length and width of the rectangular region, respectively. (b) Determine the radius of each semicircular end of the room. Determine the distance, in terms of \(y,\) around the inside edge of each semicircular part of the track. (c) Use the result of part (b) to write an equation, in terms of \(x\) and \(y,\) for the distance traveled in one lap around the track. Solve for \(y\) (d) Use the result of part (c) to write the area \(A\) of the rectangular region as a function of \(x .\) What dimensions will produce a rectangle of maximum area?

The ordering and transportation cost \(C\) (in thousands of dollars) for machine parts is \(C=100\left(\frac{200}{x^{2}}+\frac{x}{x+30}\right), \quad x \geq 1\) where \(x\) is the order size (in hundreds). In calculus, it can be shown that the cost is a minimum when \(3 x^{3}-40 x^{2}-2400 x-36,000=0\) Use a calculator to approximate the optimal order size to the nearest hundred units.

Write the quadratic function in standard form and sketch its graph. Identify the vertex, axis of symmetry, and \(x\) -intercept(s). $$f(x)=x^{2}+34 x+289$$

The profit \(P\) (in hundreds of dollars) that a company makes depends on the amount \(x\) (in hundreds of dollars) the company spends on advertising according to the model \(P=230+20 x-0.5 x^{2} . \quad\) What expenditure for advertising will yield a maximum profit?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.