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Write the function in the form \(f(x)=(x-k) q(x)+r\) for the given value of \(k,\) and demonstrate that \(f(k)=r.\) $$f(x)=-3 x^{3}+8 x^{2}+10 x-8, \quad k=2+\sqrt{2}$$

Short Answer

Expert verified
Apply polynomial division with the divisor \(x-(2+\sqrt{2})\) to the given polynomial \(-3x^3 + 8x^2 + 10x - 8\). The result will give the new form \(f(x) = (x - k) q(x) + r\). Finally, validate by equating \(f(k)\) and \(r\). If they match, the problem is solved correctly.

Step by step solution

01

Applying Polynomial Division

Start by applying polynomial division to express \(f(x)\) in the required form. The polynomial function is \(-3 x^{3}+8 x^{2}+10 x-8\), and the divisor is \(x-(2+\sqrt{2})\). We divide the polynomial by this divisor using the polynomial division method.
02

Calculation of q(x) and r

After completing the polynomial division process, the quotient, q(x), and the remainder, r, are obtained. These are the coefficients of the new polynomial form.
03

Validate the Result

Substitute \(k = 2 + \sqrt{2}\) into \(f(x)\) to calculate \(f(k)\). If \(f(k) = r\), then the exercise is correctly solved. Otherwise it means that an error was made during the polynomial division.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient and Remainder
When working with polynomials, one of the key concepts is dividing them to find the quotient and remainder. Imagine you have a big polynomial you need to break down. It's like cutting a loaf of bread, where you split it into equal parts (quotient) with a bit left over (remainder). In polynomial division, we divide a polynomial by another polynomial, often a simpler linear one of the form \(x - k\).

The goal is to express the original polynomial, \(f(x)\), in a form that looks like \(f(x) = (x - k)q(x) + r\). Here, \(q(x)\) is the quotient, and \(r\) is the remainder. It’s crucial to understand that unlike numbers, polynomials can leave a remainder that is not zero or even a whole number.

For example, when we divide the given polynomial \(-3x^3 + 8x^2 + 10x - 8\) by \(x - (2 + \sqrt{2})\), we perform polynomial division to find the quotient \(q(x)\) and the remainder \(r\), which can be any constant or polynomial of lower degree than the divisor. Lastly, we verify the process by checking if \(f(k) = r\). This confirmation step ensures the accuracy of the division result.
Polynomial Functions
Polynomial functions are expressions that involve sums and powers of variables with constant coefficients. They are written in the form \(a_nx^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0\). These are mathematical sentences using polynomials, which can describe a wide range of real-world behavior.

Key properties of polynomial functions include their degrees, which tell us the highest power of the variable, and their coefficients, which are the numbers multiplying the variables. The degree of a polynomial gives us insights into the behavior of the polynomial function, such as how it grows or decays as the variable increases or decreases.

In the exercise example, the polynomial \(-3x^3 + 8x^2 + 10x - 8\) is a third-degree polynomial, because the highest power of \(x\) is 3. Understanding the function's degree is crucial when performing polynomial division, as it helps determine how many times you can "fit" the divisor into the dividend before completing the process.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations (like addition or subtraction). They are a fundamental part of algebra, allowing us to create mathematical models of real-world situations and solve problems.

In polynomial division specifically, we turn these algebraic expressions into a form that's more manageable. This form often allows us to simplify complex problems into basic components, which is what we achieved with \(f(x) = (x-k)q(x) + r\).

Think of the process as breaking down a complex recipe into simple ingredients. Each term in our polynomial is an ingredient, and our task is to isolate these terms to see how they combine to form the whole expression. Through careful manipulation and substitution, particularly using known values like \(k = 2 + \sqrt{2}\), we arrive at simplified versions that retain all the original information but in a much neater package.

Understanding how to work with algebraic expressions through polynomial division helps in everything from calculating areas in geometry to solving equations in physics, showcasing the power and versatility of algebra.

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Most popular questions from this chapter

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