/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 Find the vertex, focus, and dire... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the vertex, focus, and directrix of the parabola. Then sketch the parabola. $$y=\frac{1}{4}\left(x^{2}-2 x+5\right)$$

Short Answer

Expert verified
Vertex of the parabola is (4,4), focus is (4,5), and the directrix is \(y = 3\). This parabola opens upwards.

Step by step solution

01

Find the vertex

The vertex of the parabola is given by the formula \((-b/2a , c - b^2/4a)\). Here a = 1/4, b = -2, and c = 5. Therefore, the vertex is given by \(-( -2 / (2 * 1/4) , 5 - (-2)^2 / (4 * 1/4) )= (4 , 4)\), hence the vertex is (4, 4).
02

Find the focus

The formula for the focus of a parabola \(y = ax^2 + bx + c\) is given by \((h , k + 1/4a)\), where (h, k) is the vertex of the parabola. Here, a = 1/4, and the vertex (h, k) = (4, 4). So, the focus is given by \(( 4 , 4 + 1/(4 * 1/4) )= (4 , 5)\). Thus, the focus of the parabola is (4, 5).
03

Find the directrix

The equation for the directrix of a parabola \(y = ax^2 + bx + c\) is given by \(y = k - 1/(4a)\), here a = 1/4 and the vertex (h, k) = (4, 4). So, the directrix is given by \(y = 4 - 1/(4*1/4) = 3\). Hence, the equation of the directrix is \(y = 3\).
04

Sketch the parabola

Now that we have the vertex at (4,4), the focus at (4,5), and the directrix at \(y = 3\), we can sketch the parabola. The parabola will be opening upwards as the coefficient of \(x^2\) is positive.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

vertex of a parabola
The vertex of a parabola is a crucial point that helps us understand the parabola's position and shape. It is the parabola's highest or lowest point, depending on its orientation. In mathematical terms, for a parabola expressed in the form \( y = ax^2 + bx + c \), the vertex is calculated using the formula \((-b/2a , c - b^2/4a)\). This formula is derived from completing the square method that standardizes the parabola's equation.

In this exercise, we have the equation \( y = \frac{1}{4}(x^2 - 2x + 5) \). By identifying \( a = 1/4 \), \( b = -2 \), and \( c = 5 \), and plugging these into the vertex formula, we get the vertex of the parabola to be \((4, 4)\).

The vertex provides us with a starting point for sketching the parabola and also gives insight into how the parabola opens—upwards or downwards. Here, since the value of \( a \) is positive, the parabola opens upwards.
focus of a parabola
The focus of a parabola is one of its essential properties. It represents a point about which the parabola is constructed. For any point on the parabola, the distance to the focus is equal to the distance to the directrix line.

To find the focus, you employ the vertex form \( (h, k) \) alongside the formula \((h, k + 1/(4a))\) for a parabola expressed as \( y = ax^2 + bx + c \). Basically, the distance between the vertex and focus is determined by \( 1/(4a) \).

From the given parabola equation \( y = \frac{1}{4}x^2 - \frac{1}{2}x + \frac{5}{4} \), we already identified our vertex \( (4, 4) \). With \( a = 1/4 \), the focus can be calculated as \((4, 4 + 1/(4 \times 1/4)) = (4, 5)\), meaning that the focus is at the point (4, 5) just above the vertex. The focus is an indicator of the parabola's direction and how 'open' or 'sharp' it is.
directrix of a parabola
The directrix of a parabola is a line that serves as a reference point for defining and positioning the parabola alongside the focus. It is parallel to the parabola's axis of symmetry and is located in the opposite direction of the focus from the vertex.

In the standard form \( y = ax^2 + bx + c \), the equation of the directrix is \( y = k - 1/(4a) \), where \( k \) is the y-coordinate of the vertex. Essentially, the directrix is separated from the vertex by the same distance as the focus but in the reverse direction.

Using our found vertex \( (4, 4) \) for the given parabola and \( a = 1/4 \), we calculate the directrix as \( y = 4 - 1/(4 \times 1/4) = 3 \). Hence, the equation of the directrix is \( y = 3 \), indicating it runs horizontally below the vertex, giving balance to the parabola's shape.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use a graphing utility to graph the polar equation. Identify the graph. $$r=\frac{-5}{2+4 \sin \theta}$$

Find a polar equation of the conic with its focus at the pole. $$\begin{array}{cc}\text{Conic} & \text{Eccentricity} & \text{Directrix} \\\ \text{Ellipse} & e=\frac{3}{4} & y=-2 \end{array}$$

Identify the conic and sketch its graph. $$r=\frac{4}{4+\sin \theta}$$

The center of a Ferris wheel lies at the pole of the polar coordinate system, where the distances are in feet. Passengers enter a car at \((30,-\pi / 2) .\) It takes 45 seconds for the wheel to complete one clockwise revolution. (a) Write a polar equation that models the possible positions of a passenger car. (b) Passengers enter a car. Find and interpret their coordinates after 15 seconds of rotation. (c) Convert the point in part (b) to rectangular coordinates. Interpret the coordinates.

A satellite in a 100 -mile-high circular orbit around Earth has a velocity of approximately 17,500 miles per hour. If this velocity is multiplied by \(\sqrt{2},\) then the satellite will have the minimum velocity necessary to escape Earth's gravity and will follow a parabolic path with the center of Earth as the focus (see figure). (a) Find a polar equation of the parabolic path of the satellite (assume the radius of Earth is 4000 miles). (b) Use a graphing utility to graph the equation you found in part (a). (c) Find the distance between the surface of the Earth and the satellite when \(\theta=30^{\circ}\). (d) Find the distance between the surface of Earth and the satellite when \(\theta=60^{\circ}\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.