/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 Find the difference quotient and... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the difference quotient and simplify your answer. $$f(t)=\frac{1}{t-2}, \frac{f(t)-f(1)}{t-1}, t \neq 1$$

Short Answer

Expert verified
The simplified difference quotient is \(\frac{1}{t-2}\), \(t \neq 1\).

Step by step solution

01

Insert function into difference quotient

First of all, replace \(f(t)\) and \(f(1)\) in the difference quotient formula with \(\frac{1}{t-2}\) and \(\frac{1}{1-2}\) respectively, so it will be \(\frac{\frac{1}{t-2} - \frac{1}{1-2}}{t-1}\).
02

Simplify fractions

Now, simplify the fractions to get \(\frac{\frac{1}{t-2} + \frac{1}{1}}{t-1}\).
03

Common denominator

Next, find the common denominator for the fractions in numerator, which leads to \(\frac{\frac{1(t-1)+(t-2)}{(t-2)(t-1)}}{t-1}\).
04

Simplify the numerator

Then, simplify the numerator, \((t-1)+(t-2)\), to get t-3 in the numerator. Therefore, it becomes \(\frac{t-3}{(t-2)(t-1)}\).
05

Cancel out factor in denominator

Finally, cancel out the (t-1) factor in the numerator and denominator, leaving us with the final answer \(\frac{1}{t-2}\). However, remember that \(t \neq 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simplifying Expressions
Understanding how to simplify mathematical expressions is foundational for algebra. It involves reducing an expression to its most basic form without changing its value. To approach simplification, start by combining like terms and applying algebraic rules. In the context of difference quotients, simplification can get tricky due to the presence of fractions and variables.

Consider the steps taken in the provided solution. The complex fraction formed by the difference quotient was simplified step-by-step. The process began by substituting the function values and moved on to combining the fractions in the numerator by finding a common denominator. Terms were then simplified across the numerator and denominator. Simplification plays a crucial role in understanding and solving complex algebraic problems and seeing clearer relationships between variables.
Rational Functions
Rational functions are fractions that involve polynomials in both the numerator and the denominator. The function provided, \(f(t) = \frac{1}{t-2}\), is an example of a rational function. A key aspect of dealing with rational functions is identifying restrictions on the variable, as these functions are not defined when their denominator is zero.

In the example, \(t eq 2\) is an implicit restriction because \(t-2\) cannot be zero. When working with the difference quotient of a rational function, as shown in our exercise, we have to carefully manipulate the function while upholding these constraints. The final expression, \(\frac{1}{t-2}\), clearly shows where the function is undefined and gives us insights into its behavior near those values.
Algebraic Fractions
Algebraic fractions, also known as fractional expressions, involve variables in the numerator, the denominator, or both. They follow the same principles as numerical fractions but can appear more complex due to the presence of variables.

To simplify algebraic fractions, follow steps similar to simplifying numerical fractions: find a common denominator, combine terms, and reduce. In our example, the numerator of the difference quotient formed an algebraic fraction with the expression \(\frac{t-3}{(t-2)(t-1)}\). The key to simplifying was reducing the fraction by canceling out the common \(t-1\) term in the numerator and denominator. It is essential to state the variable restrictions clearly, as illustrated by the condition \(t eq 1\) in the solution, because variables represent unknown values, and it's critical to avoid division by zero.

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