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(a) find the inverse function of \(f\). (b) graph both \(f\) and \(f^{-1}\) on the same set of coordinate axes, (c) describe the relationship between the graphs of \(f\) and \(f^{-1},\) and (d) state the domains and ranges of \(f\) and \(f^{-1}\). $$f(x)=\sqrt{4-x^{2}}, \quad 0 \leq x \leq 2$$

Short Answer

Expert verified
The inverse function \(f^{-1}(x)\) is \(\sqrt{4 - x^{2}}\) for \(0 \leq x \leq 2\). The graphs of \(f\) and \(f^{-1}\) are half circles on either side of the \(y = x\) line, and they reflect each other over this line. The domain and range of \(f(x)\) are both \(0 \leq x \leq 2\) and \(0 \leq y \leq 2\), and for \(f^{-1}(x)\), they are \(0 \leq x \leq 2\) and \(-2 \leq y \leq 0\), respectively.

Step by step solution

01

Find the inverse of the function

To find the inverse \(f^{-1}(x)\) of a function \(f(x)\), first replace \(f(x)\) with \(y\). This gives us \(y = \sqrt{4-x^{2}}\). Then, switch \(x\) and \(y\), and solve for \(y\). So we get \(x = \sqrt{4-y^{2}}\). Squaring both sides gives \(x^{2} = 4 - y^{2}\), then solving for \(y\), we find \(y = \sqrt{4 - x^{2}}\). Therefore, \(f^{-1}(x) = \sqrt{4 - x^{2}}\) for \(0 \leq x \leq 2\).
02

Graph \(f\) and \(f^{-1}\)

Both \(f\) and \(f^{-1}\) are half circles with a radius of 2. \(f\) is the upper half and \(f^{-1}\) is the lower half. We can draw a semicircle for the given range \(0 \leq x \leq 2\) and cut it in half at \(x=2\). The upper semicircle will represent \(f\) and the lower semicircle will represent \(f^{-1}\). The coordinate axes will serve as the boundaries of the domain and range.
03

Describe the relationship between \(f\) and \(f^{-1}\)

The graphs of \(f\) and \(f^{-1}\) are reflections of each other over the line \(y = x\). If a point \((a, b)\) is on the graph of \(f\), then the point \((b, a)\) is on the graph of \(f^{-1}\). This shows the 'interchanging of roles' of \(x\) and \(y\) in the original function and its inverse.
04

State the domains and ranges of \(f\) and \(f^{-1}\)

For \(f(x) = \sqrt{4 - x^{2}}\), the domain is \(0 \leq x \leq 2\) and the range is \(0 \leq y \leq 2\). For the inverse function, \(f^{-1}(x) = \sqrt{4 - x^{2}}\), the domain and range switch, so the domain is \(0 \leq x \leq 2\) and the range is \(-2 \leq y \leq 0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Graphs
Function graphs are an excellent way to visualize mathematical relationships. A graph is a pictorial representation of all the points that satisfy a given function. By plotting these points on a coordinate plane, you can easily see trends and patterns.

In the case of the function \(f(x) = \sqrt{4-x^2}\), we are dealing with the top half of a circle with radius 2. This is because the expression \(x^2 + y^2 = 4\) represents a full circle, and when solved for \(y\), you get the positive square root, representing the top half.

The graph of the inverse function \(f^{-1}(x)\), meanwhile, is simply the reflection of \(f(x)\) across the line \(y=x\). Consequently, this turns the top half into the bottom half of the circle. By plotting these two functions on a coordinate axis, you'll see a mirror image, highlighting their inverse nature.
  • \(f(x)\): Upper semicircle
  • \(f^{-1}(x)\): Lower semicircle
Domain and Range
Understanding the domain and range of a function, as well as its inverse, allows you to know where the function is defined and what values it can take.

The domain of a function is the set of all possible input values (\(x\) values), while the range is the set of all possible output values (\(y\) values). For \(f(x) = \sqrt{4-x^2}\), the domain is \(0 \leq x \leq 2\), which indicates the function is defined from \(x=0\) to \(x=2\). Its range is \(0 \leq y \leq 2\), meaning the output \(y\) can vary from 0 to 2.

Inverse functions essentially swap domain and range between the original function and its inverse. Thus, for the inverse function \(f^{-1}(x)\), the domain is \(0 \leq x \leq 2\) and the range is \(-2 \leq y \leq 0\). This interchange significantly emphasizes the close relationship between a function and its inverse.
  • \(f(x)\) Domain: \(0 \leq x \leq 2\); Range: \(0 \leq y \leq 2\)
  • \(f^{-1}(x)\) Domain: \(0 \leq x \leq 2\); Range: \(-2 \leq y \leq 0\)
Reflection over the Line y=x
An important property of inverse functions is how they graphically relate to each other via reflection over the line \(y = x\). This line is the bisector of the first and third quadrants, effectively acting as a mirror.

For any function \(f\) and its inverse \(f^{-1}\), every point \((a, b)\) on the graph of \(f\) corresponds to a point \((b, a)\) on the graph of \(f^{-1}\). This 'swapping' of coordinates is due to the nature of inverse functions, where outputs become inputs and vice versa.

Visualizing this reflection on a graph can deepen your understanding of inverse relationships. As you plot both the function and its inverse, you will notice they perfectly "mirror" each other across the line \(y = x\). This symmetry is why inverses are so fascinating and vital in mathematics.
  • Each point \((a, b)\) on \(f(x)\) maps to \((b, a)\) on \(f^{-1}(x)\)
  • Both graphs are symmetrical about \(y=x\)

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