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Find the distance between the points. $$(-2,6),(3,-6)$$

Short Answer

Expert verified
The distance between the points (-2,6) and (3,-6) is 13 units.

Step by step solution

01

Identify the Coordinates

First, identify the given coordinates. The coordinates are (-2,6) and (3,-6). Thus, (-2,6) is Point 1 where x鈧 = -2 and y鈧 = 6, and (3,-6) is Point 2 where x鈧 = 3 and y鈧 = -6.
02

Apply the Euclidean Distance Formula

The formula to find a distance between two points in a 2D plane is based on the Pythagorean Theorem and is given by the formula:\[d = \sqrt{ (x鈧 - x鈧)虏 + (y鈧 - y鈧)虏 }\] Substitute the identified coordinates into the formula. In this case, \(x鈧 = -2\), \(y鈧 = 6\), \(x鈧 = 3\), and \(y鈧 = -6\). Accordingly, the formula will be as followed:\[ d = \sqrt{ (3 - (-2))虏 + ((-6) - 6)虏 } \]
03

Solve the Equation

Perform the calculations inside the brackets and square root. Remember to observe the maths rules, especially for dealing with negative numbers. \[ d = \sqrt{ (5)虏 + (-12)虏 }\]The distance d can be calculated as:\[ d = \sqrt{ 25 + 144 }\]\[ d = \sqrt{ 169 }\]So the distance d between the points (-2,6) and (3,-6) is 13 units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordinate Geometry
Coordinate Geometry is a branch of geometry where points are defined by coordinates on a plane. Each point has two coordinates, known as the x-coordinate and the y-coordinate, which determine its position in a two-dimensional space. Think of a point on this grid as a specific location defined by these numbers.

For our exercise, the points given are \((-2, 6)\) and \((3, -6)\). Here:
  • Point 1 has an x-coordinate of -2 and a y-coordinate of 6.
  • Point 2 has an x-coordinate of 3 and a y-coordinate of -6.
These coordinates tell us the exact location of each point on the coordinate plane. Understanding how to read these coordinates is a foundation for more complex calculations, such as finding the distance between two points.
Distance Formula
The Distance Formula in coordinate geometry helps us calculate how far apart two points are on a plane. It is a straightforward application of the Pythagorean Theorem, transforming it to work with coordinates. The formula is:\[d = \sqrt{ (x_2 - x_1)^2 + (y_2 - y_1)^2 }\]This formula requires arithmetic manipulation to find the difference between the x-coordinates and y-coordinates of the two points and then use these differences to compute the distance.

For our points:
  • Substitute \(x_1 = -2, y_1 = 6, x_2 = 3, y_2 = -6\) into the formula.
  • Calculate each part: \((x_2 - x_1) = 3 - (-2) = 5\) and \((y_2 - y_1) = -6 - 6 = -12\).
  • Square both results: \(5^2 = 25\) and \((-12)^2 = 144\).
  • Add them together: \(25 + 144 = 169\).
  • Take the square root: \(\sqrt{169} = 13\).
The result gives us the direct Euclidean distance between these two points.
Pythagorean Theorem
The Pythagorean Theorem is a fundamental principle in geometry, stating that in a right-angled triangle, the square of the length of the hypotenuse \(c\) (the side opposite the right angle) is equal to the sum of the squares of the other two sides \(a\) and \(b\). It is expressed mathematically as:\[c^2 = a^2 + b^2\]This theorem laid the groundwork for the Distance Formula used in coordinate geometry by treating the distance between two points as the hypotenuse of a right triangle.

In our exercise, when we find the differences \((x_2 - x_1)\) and \((y_2 - y_1)\), these differences form the two shorter sides \(a\) and \(b\) of a right-angled triangle. The diagonal or hypotenuse \(c\), which is the distance we calculate, fully utilizes the theorem.

Breaking this down:
  • The side "a" is the horizontal difference between the x-coordinates.
  • "b" is the vertical difference between the y-coordinates.
  • The calculated distance \(d\) is the length of the hypotenuse.
Thus, the Pythagorean Theorem seamlessly aids in understanding how distances between points are measured in the coordinate plane.

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Most popular questions from this chapter

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