Chapter 8: Problem 83
Complete the square and write the circle's equation in standard form: $$x^{2}+y^{2}-2 x+4 y=4$$ Then give the center and radius of the circle and graph the equation.
Short Answer
Expert verified
The circle's equation in standard form is \((x-1)^2+(y+2)^2=9\). The center of the circle is at (1,-2) and the radius is 3.
Step by step solution
01
Complete the Square for X and Y
First, we need to group the x and y terms separately and complete the square for both. This involves adding and subtracting the square of half of coefficient of x and y from both sides of the equation. Separate the x and y terms: \((x^2-2x)+(y^2+4y)=4\). Half of 2 is 1 and half of 4 is 2, square these to get 1 and 4 respectively. Add these to both sides of the equation: \((x^2-2x+1)+(y^2+4y+4)=4+1+4\). Now, simplify this as \((x-1)^2+(y+2)^2=9\).
02
Writing in Standard Form
Now that we've completed the square, we've got the equation in the standard form for a circle, \((x-a)^2+(y-b)^2=r^2\), where (a,b) is the center and r is the radius: \((x-1)^2+(y+2)^2=9\). This tells us the coordinates of the center and the radius of the circle.
03
Identify the Center and the Radius
From the standard form equation, \((x-1)^2+(y+2)^2=9\), we can identify the center of the circle by changing the signs from (-1,2) to (1,-2). The radius is the square root of the number on the right side of the equation, i.e., \(r=\sqrt{9}=3\). So the center is (1,-2) and the radius is 3.
04
Graphing the Circle
To graph this, you'd plot the center point at (1,-2) and then draw a circle with a radius of 3 units. Points on the circle will be 3 units away from the center in all directions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equation of a Circle
The equation of a circle provides a mathematical description of a circle in a coordinate plane. It allows us to understand and specify the position and size of a circle precisely. A circle is defined as the set of all points that are equidistant from a central point, known as the center. This distance is called the radius. In algebraic terms, the standard form for the equation of a circle is
- \((x-a)^2 + (y-b)^2 = r^2\)
- \((a, b)\) is the center of the circle
- \(r\) is the radius of the circle
Standard Form
The standard form of a circle’s equation is a powerful tool that makes it easy to work with circles. It simplifies the examination of a circle's properties by breaking down the equation into parts that clearly define the circle's center and radius. To transform a quadratic equation into the standard form
- \((x-a)^2 + (y-b)^2 = r^2\)
- Collecting all x-terms and y-terms together
- Adding and subtracting the square of half the coefficient of the linear terms
- Simplifying to transform each quadratic expression into a perfect square trinomial
Center and Radius of a Circle
Finding the center and radius of a circle from its equation involves recognizing specific patterns in the equation. In the standard form
- \((x-a)^2 + (y-b)^2 = r^2\)
- The terms inside the squared expressions indicate the coordinates of the center. For instance, \((x-1)^2 + (y+2)^2\) tells us the center is at (1, -2) because we take the opposite signs of what is in the brackets.
- The number on the right side of the equation gives us the square of the radius. By taking the square root of this value, we find the radius. In \((x-1)^2 + (y+2)^2 = 9\), the radius is \(\sqrt{9} = 3\).
Graphing Circles
Graphing a circle involves plotting it on the coordinate plane based on its center and radius, which are derived from its equation. To accurately graph a circle:
- First, plot the center point on the coordinate plane. For example, with a center at (1, -2), find this point on your graph.
- The radius determines how far the circle extends from its center in all directions. With a radius of 3, measure 3 units from the center point in all directions.
- Draw a smooth, round curve that is equidistant from the center whenever possible to complete your circle.