Chapter 7: Problem 55
$$\text { Solve: } \frac{x+3}{4}-\frac{x+1}{10}=\frac{x-2}{5}-1$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 7: Problem 55
$$\text { Solve: } \frac{x+3}{4}-\frac{x+1}{10}=\frac{x-2}{5}-1$$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
a. Graph the solution set of the system: $$\left\\{\begin{array}{c}x \geq 0 \\\y \geq 0 \\\3 x-2 y \leq 6 \\\y \leq-x+7\end{array}\right.$$ b. List the points that form the corners of the graphed region in part (a). c. Evaluate \(2 x+5 y\) at each of the points obtained in \(\operatorname{part}(\mathrm{b})\)
Solve each system by the method of your choice. $$\left\\{\begin{array}{l} (x-1)^{2}+(y+1)^{2}=5 \\ 2 x-y=3 \end{array}\right.$$
Solve the system for \(x\) and \(y\) in terms of \(a_{1}, b_{1}, c_{1}, a_{2}, b_{2}\) and \(c_{2}\): $$\left\\{\begin{array}{l}a_{1} x+b_{1} y=c_{1} \\\a_{2} x+b_{2} y=c_{2}\end{array}\right.$$
Use the formula for the area of a rectangle and the Pythagorean Theorem to solve A small television has a picture with a diagonal measure of 10 inches and a viewing area of 48 square inches. Find the length and width of the screen. (IMAGE CAN NOT COPY)
Graphing utilities can be used to shade regions in the rectangular coordinate system, thereby graphing an inequality in two variables. Read the section of the user's manual for your graphing utility that describes how to shade a region. Then use your graphing utility to graph the inequalities. $$y \leq 4 x+4$$
What do you think about this solution?
We value your feedback to improve our textbook solutions.