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Graph the solution set of system of inequalities or indicate that the system has no solution. $$\left\\{\begin{aligned}x^{2}+y^{2} & \leq 1 \\\y-x^{2} &>0\end{aligned}\right.$$

Short Answer

Expert verified
The solution to the system of inequalities is the region that lies inside the circle \(x^{2} + y^{2} \leq 1\) (including points on the circle) and above the parabola \(y > x^{2}\).

Step by step solution

01

Analyze the First Inequality

The first inequality \(x^{2} + y^{2} \leq 1\) is a circle centered at the origin with radius 1. This represents the circle and the area inside it.
02

Graph the First Inequality

Plot the circle with center at (0,0) and radius 1. The solution includes points on the circle and points inside the circle.
03

Analyze the Second Inequality

The second inequality, \(y - x^{2} > 0 \), can be rearranged to \(y > x^{2}\). This represents the area above the parabola \(y = x^{2}\).
04

Graph the Second Inequality

Plot the parabola \(y = x^{2}\). The solution is any point above this parabola.
05

Find the Solution Set

The solution to the system of inequalities is the area that satisfies both inequalities simultaneously. It is the region that is inside the circle and above the parabola.
06

Analyze the Solution

The common region is the solution set for the system. If there is no common area, it means the system has no solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circle and Parabola Intersections
Understanding the interaction between circles and parabolas is crucial to solving systems that include both types of equations. A circle is defined by the set of points that are equidistant from a central point, while a parabola is defined as the set of points that are equidistant from a point (the focus) and a line (the directrix).
When graphing these shapes, intersections may occur if the parabola passes through the circle. Analyzing the algebraic equations of a circle, such as \(x^2 + y^2 \leq 1\), and a parabola, such as \(y > x^2\), aids in determining their points of intersection. These points of intersection will be key in finding the solution set for the system.

To improve comprehension, it is beneficial to include a visual representation of the graphs alongside their respective equations. This illustration can demonstrate how and where these two shapes intersect, which, in turn, will help students understand the concept of the combined solution set.
Inequality Solution Sets
Inequality solution sets consist of all the possible solutions that satisfy a given inequality. When dealing with a system of inequalities, such as the one in our exercise, the solution set becomes the area of overlap where all the individual inequalities are true simultaneously. For visual learners, shading the graph regions that correspond to each inequality separately and then highlighting the overlap can be extremely effective.

For the system \(\left\{\begin{aligned}x^{2} + y^{2} & \leq 1 \ y - x^{2} & > 0\end{aligned}\right.\), the combined solution set would be the region that is within the unit circle and also above the parabola \(y = x^{2}\). Describing the methods of finding this overlapping region, possibly with the use of colors or patterns in the graph, could support better student understanding of this concept.
Plotting Inequalities
Plotting inequalities on a graph is a visual way of representing the solution sets. It's important to use a clear and systematic approach to ensure that all students can follow along. Start by drawing the boundary of the inequality, which could be a line for a linear inequality or a curve for a quadratic or circular one. It is also crucial to use a dashed or solid line to indicate whether the boundary is included in the solution set (solid for \(\leq\) or \(\geq\)) or not (dashed for \(>\) or \(<\)).

When it comes to shading, which represents the area of solutions, students should be advised to shade lightly and use different patterns for each inequality, making it easier to identify the overlap or 'solution set'. An approach involving step-by-step examples, such as starting with simple lines and progressing to curves, can help beginners gradually build their plotting skills.
Quadratic and Circular Inequalities
Quadratic and circular inequalities involve quadratic equations, like \(y > x^{2}\), and circle equations, like \(x^{2} + y^{2} \leq 1\). These inequalities denote regions on a graph, not just lines or curves. For quadratic inequalities, solutions typically lie either above or below the parabola, depending upon the direction of the inequality sign. Similarly, for circular inequalities, solutions lie either inside or outside the circle, again based on whether the inequality is less than or equal to (\(\leq\)), or greater than (\(>\)).

To build a deeper understanding, discuss the features of the parabola (such as vertex and direction of opening) and the circle (like the center and radius). Adding examples of how to find the vertex of a parabola or the center and radius of a circle will enhance comprehension. Practical exercises plotting both on the same coordinate plane will allow students to visualize the relationship between these two types of inequalities.

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Most popular questions from this chapter

What does a solid line mean in the graph of an inequality?

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. A system of two equations in two variables whose graphs are two circles must have at least two real ordered-pair solutions.

Between 1990 and 2013 , there was a drop in violent crime and a spike in the prison population in the United States. The bar graph shows the number of violent crimes per \(100,000\) people and the number of imprisonments per \(100,000\) people for six selected years from 1990 through 2013. (GRAPH CAN NOT COPY) a. Based on the information in the graph, it appears that there was a year when the number of violent crimes per \(100,000\) Americans was the same as the number of imprisonments per \(100,000\) Americans. According to the graph, between which two years did this occur? b. The data can be modeled by quadratic and linear functions. Violent erime rate \(\quad y=0.6 x^{2}-28 x+730\) Imprisonment tate \(-15 x+y=300\) In each function, \(x\) represents the number of years after 1990 and \(y\) represents the number per \(100,000\) Americans. Solve a nonlinear system to determine the year described in part (a). Round to the nearest year. How many violent crimes per \(100,000\) Americans and how many imprisonments per \(100,000\) Americans were there in that year?

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