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Solve each system for \((x, y, z)\) in terms of the nonzero constants \(a, b,\) and \(c\).$$\left\\{\begin{aligned} a x-b y-2 c z &=21 \\ a x+b y+c z &=0 \\ 2 a x-b y+c z &=14 \end{aligned}\right.$$

Short Answer

Expert verified
Finally the solutions for \(x, y, z\) in terms of \(a, b, c\) are given by: \(x = \frac{14+2*7*21}{3a}\), \(y = \frac{7*-21 + 21}{3b}\) and \(z = \frac{-21}{c}\) respectively.

Step by step solution

01

Add and subtract equations

We begin by subtracting the second equation from the first to get an equation of only \(y\) and \(z\). This is done by:\[ax - by - 2cz - (ax + by + cz) = 21 - 0\]which simplifies to \[ - 2by - 3cz = 21 \] Let this be equation [1] \n Next, subtract the second from the third to get:\[2ax - by + cz - (ax + by + cz) = 14 - 0\]which simplifies to \[ax - 2by = 14 \] Let this be equation [2]
02

Solve equation [2] for x

In equation [2], isolate \(x\) on one side by dividing all terms by \(a\):\[ x = \frac{14+2by}{a} \] Let this be equation [3]
03

Substitute equation [3] into first equation

Substitute \(x\) from equation [3] into the first original equation which is \( ax - by - 2cz = 21 \). This gives:\[ a * \left(\frac{14+2by}{a}\right) - by - 2cz = 21 \]Simplifying this, we get:\[ y = \frac{7cz + 21}{3b} \] Let this be equation [4]
04

Substitute equations [3] and [4] into second equation

Substitute from equations [3] and [4] into the second original equation which is \( ax + by + cz = 0 \). This gives:\[ a * \left(\frac{14+2by}{a}\right) + b * \left(\frac{7cz + 21}{3b}\right) + cz = 0 \]Simplifying this, we get:\[ z = \frac{-21}{c} \] Let this be equation [5]
05

Substitute equation [5] into equations [3] and [4]

Substitute \(z\) from equation [5] into equations [3] and [4] to solve for \(x\) and \(y\) respectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Equations
Linear equations are equations of the first order, which means they involve only the first power of the variable. The general form of a linear equation in two variables is:- \[ ax + by = c \]where:
  • \(a, b\), and \(c\) are constants, and
  • \(x\) and \(y\) are variables.
In this form:-
  • \(a\) and \(b\), called coefficients, represent the slope of the line.
  • \(c\) is the y-intercept, where the line crosses the y-axis if plotted on a graph.
A crucial property of linear equations is that they produce a straight line when graphed. Because they simply involve adding and subtracting terms, they are among the easiest equations to solve analytically. Remember to maintain balance by performing the same operations on both sides of the equation. This makes it easier to isolate and solve for a specific variable.
Simultaneous Equations
Simultaneous equations are a set of equations with multiple variables. The solution to a system of simultaneous equations is the set of values that satisfies all the equations at the same time.- In our exercise, we have three equations with three variables \((x, y, z)\).While this can seem complex, solving them follows a methodical process:
  • First, identify relationships between equations that allow for algebraic manipulation.
  • Next, increase the focus on finding simpler connections among variables by either adding or subtracting equations to eliminate variables gradually.
  • Finally, substitute known values back into the simplified equations to find solutions for the remaining variables.
Each equation represents a condition that the solution must fulfill. Solving simultaneous equations often involves strategies such as substitution or elimination to reduce the number of variables step by step. This reduction eventually yields simple linear equations that can be used to find particular solutions.
Algebraic Manipulation
Algebraic manipulation involves various techniques to simplify or rearrange equations. It's a cornerstone concept for solving systems of equations, such as the one in the given exercise. - The primary tools used in algebraic manipulation are:
  • Addition or subtraction: Used to eliminate a variable by combining two equations together.
  • Multiplication or division: Applied to both sides of an equation to isolate a certain variable.
  • Substitution: Involves replacing a variable with an equivalent expression from another equation.
In our solution, we employ these techniques by isolating each variable, reducing the complexity of the system step by step. The beauty of algebraic manipulation lies in its ability to convert a seemingly complex web of equations into much simpler forms, ultimately leading to solutions that satisfy every equation in the system. Thorough practice of these techniques is essential for mastering the solution of simultaneous and linear equations.

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Most popular questions from this chapter

Graphing utilities can be used to shade regions in the rectangular coordinate system, thereby graphing an inequality in two variables. Read the section of the user's manual for your graphing utility that describes how to shade a region. Then use your graphing utility to graph the inequalities. $$y \geq x^{2}-4$$

Harsh, mandatory minimum sentences for drug offenses account for more than half the population in U.S. federal prisons. The bar graph shows the number of inmates in federal prisons, in thousands, for drug offenses and all other crimes in 1998 and \(2010 .\) (Other crimes include murder, robbery, fraud, burglary, weapons offenses, immigration offenses, racketeering, and perjury.) (GRAPH CAN'T COPY) a. In \(1998,\) there were 60 thousand inmates in federal prisons for drug offenses. For the period shown by the graph, this number increased by approximately 2.8 thousand inmates per year. Write a function that models the number of inmates, \(y,\) in thousands, for drug offenses \(x\) years after 1998. b. In \(1998,\) there were 44 thousand inmates in federal prisons for all crimes other than drug offenses. For the period shown by the graph, this number increased by approximately 3.8 thousand inmates per year. Write a function that models the number of inmates, \(y,\) in thousands, for all crimes other than drug offenses \(x\) years after 1998 . c. Use the models from parts (a) and (b) to determine in which year the number of federal inmates for drug offenses was the same as the number of federal inmates for all other crimes. How many inmates were there for drug offenses and for all other crimes in that year?

Solve each system by the method of your choice. $$\left\\{\begin{array}{l} 3 x^{2}-2 y^{2}=1 \\ 4 x-y=3 \end{array}\right.$$

When graphing \(3 x-4 y<12,\) it's not necessary for me to graph the linear equation \(3 x-4 y=12\) because the inequality contains a \(<\) symbol, in which equality is not included.

What does a dashed line mean in the graph of an inequality?

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