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In Exercises \(23-34\), find the exact value of each of the remaining trigonometric functions of \(\theta\). \(\tan \theta=\frac{5}{12}, \quad \cos \theta<0\)

Short Answer

Expert verified
\(\sin \theta = \frac{5}{13}\), \(\cos \theta =-\frac{12}{13}\), \(\csc \theta = \frac{13}{5}\), \( \sec \theta = -\frac{13}{12}\), \( \cot \theta = \frac{12}{5}\)

Step by step solution

01

Calculate the Hypotenuse

We know that the opposite side to \(\theta\) is 5 (from \(\tan \theta = \frac {opposite}{adjacent}\)) and the adjacent side to \(\theta\) is 12. Using the Pythagorean theorem (\(hypotenuse^2 = opposite^2 + adjacent^2\)), we can solve for the hypotenuse to be 13 (as \(sqrt {5^2 + 12^2} = 13\)).
02

Find Cosine Value

Cosine is defined as the ratio of the adjacent side to the hypotenuse, therefore, \(\cos \theta = \frac{12}{13}\). However, as previously noted, we are in the 2nd or 3rd quadrant where cosine is negative, hence \(\cos \theta =-\frac{12}{13}\).
03

Find Sine Value

Sine is defined as the ratio of the opposite side to the hypotenuse, hence \(\sin \theta = \frac{5}{13}\). Considering quadrant, as \(\cos \theta < 0\), \(\theta\) is in the 2nd or 3rd quadrant where sine is positive in the 2nd quadrant and negative in the 3rd quadrant. However, since \(\tan \theta > 0\) and tan is negative in the 2nd quadrant, \(\theta\) is in the 2nd quadrant. Therefore, \(\sin \theta = \frac{5}{13}\).
04

Find values of cosecant, secant and cotangent

Cosecant, secant and cotangent are reciprocals of sine, cosine, and tangent respectively. From step 3, we know that \(\sin \theta = \frac{5}{13}\) and from step 2, \(\cos \theta =-\frac{12}{13}\). Hence we can find the others as follows: \(\csc \theta = \frac{1}{sin \theta} = \frac{13}{5}\), \( \sec \theta = \frac{1}{\cos \theta} = -\frac{13}{12}\), and \( \cot \theta = \frac{1}{tan \theta} = \frac{12}{5}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in geometry that describes the relationship between the sides of a right triangle. It states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This relationship is typically written as \(a^2 + b^2 = c^2\), where \(a\) and \(b\) are the lengths of the legs, and \(c\) is the length of the hypotenuse.

In the given exercise, the tangent of angle \(\theta\) is used to find the lengths of the opposite and adjacent sides of the triangle. Once we know these two sides, we use the Pythagorean theorem to calculate the length of the hypotenuse, which is essential in finding the sine and cosine values.

Understanding the Pythagorean theorem is not only critical for solving many problems in trigonometry but also for appreciating the properties of space and shapes. It's often one of the first steps in finding the values of trigonometric functions when you know the lengths of any two sides of a right triangle.
Unit Circle
The unit circle is a powerful tool in trigonometry that helps visualize and understand the trigonometric functions. It is a circle with a radius of one unit, centered at the origin of a coordinate plane. The unit circle allows for the definition of the trigonometric functions cosine, sine, and tangent based on the coordinates of points along its circumference.

Each point on the unit circle corresponds to an angle measured from the positive x-axis, going counter-clockwise. The coordinates of these points \( (x, y) \) provide the values of \( \cos(\theta) \) and \( \sin(\theta) \) for the angle \(\theta\). Specifically, \(\cos(\theta) = x\) and \(\sin(\theta) = y\). The quadrant in which the terminal side of the angle lies will determine the sign of those trigonometric values.

In our exercise, knowing that \(\cos(\theta) < 0\) implies that angle \(\theta\) must lie in either the second or third quadrant, where the x-coordinates (and thus the cosine values) are negative. The unit circle is not just a theoretical construct but is used practically to solve problems and understand trigonometric function properties and their periodic nature.
Reciprocal Trigonometric Functions
Trigonometry isn't only about the primary functions like sine, cosine, and tangent; understanding their reciprocal functions is equally important for a comprehensive grasp of the subject. The reciprocal trigonometric functions are secant (\(\sec\)), cosecant (\(\csc\)), and cotangent (\(\cot\)), which are reciprocals of cosine, sine, and tangent, respectively.

Specifically, \(\sec(\theta) = \frac{1}{\cos(\theta)}\), \(\csc(\theta) = \frac{1}{\sin(\theta)}\), and \(\cot(\theta) = \frac{1}{\tan(\theta)}\). These functions are useful when the primary trigonometric functions' values become inconvenient or impractical to use. They are also critical in various areas of calculus and applied mathematics.

In the provided solution, after finding the values of sine and cosine, the reciprocal functions' values are determined. For example, since \(\cos(\theta)\) was found to be negative, \(\sec(\theta)\) will also be negative, as they are reciprocal. Understanding these relationships can unlock further aspects of trigonometry in both theoretical and real-world applications.

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Most popular questions from this chapter

What is a periodic function? Why are the sine and cosine functions periodic?

Exercises \(117-119\) will help you prepare for the material covered in the next section. In each exercise, complete the table of coordinates. Do not use a calculator. $$y=3 \sin \frac{\pi}{2} x$$ $$\begin{array}{|l|l|l|l|l|l|l|l|l|} \hline x & 0 & \frac{1}{3} & 1 & \frac{5}{3} & 2 & \frac{7}{3} & 3 & \frac{11}{3} & 4 \\ \hline y & & & & & & & \\ \hline \end{array}$$ After completing this table of coordinates, plot the nine ordered pairs as points in a rectangular coordinate system. Then connect the points with a smooth curve.

Will help you prepare for the material covered in the first section of the next chapter. The exercises use identities, introduced in Section \(4.2,\) that enable you to rewrite trigonometric expressions so that they contain only sines and cosines: $$\begin{array}{ll} \csc x=\frac{1}{\sin x} & \sec x=\frac{1}{\cos x} \\ \tan x=\frac{\sin x}{\cos x} & \cot x=\frac{\cos x}{\sin x} \end{array}$$ Rewrite each expression by changing to sines and cosines. Then simplify the resulting expression. $$\sec x+\tan x$$

Explain the difference between positive and negative angles. What are coterminal angles?

Use the keys on your calculator or graphing utility for converting an angle in degrees, minutes, and seconds \(\left(D^{\circ} M^{\prime} S^{\prime \prime}\right)\) into decimal form, and vice versa. Convert each angle to a decimal in degrees. Round your answer to two decimal places. $$65^{\circ} 45^{\prime} 20^{\prime \prime}$$

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