/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 In Exercises \(23-34\), find the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises \(23-34\), find the exact value of each of the remaining trigonometric functions of \(\theta\). \(\cos \theta=\frac{4}{5}, \quad \theta\) in quadrant IV

Short Answer

Expert verified
The exact values of the trigonometric functions are: sin(θ) = -\(3/5\), tan(θ) = -\(3/4\), csc(θ) = \(5/3\), sec(θ) = \(5/4\), cot(θ) = -\(4/3\)

Step by step solution

01

Calculate the value of sin(θ)

For calculating the value of sin(θ), use the Pythagorean identity \(sin^2(θ) + cos^2(θ) = 1\). Rewrite it as \(sin^2(θ) = 1 - cos^2(θ)\). Given, cos(θ) = \(4/5\), hence, \(sin^2(θ) = 1 - (4/5)^2 = 1 - 16/25 = 9/25\). So, sin(θ) = ± √(9/25). But since θ falls in the 4th quadrant where sine is negative, so sin(θ) = - √(9/25) = -\(3/5\)
02

Find the rest of the trigonometric functions

Utilizing the values of sin(θ) and cos(θ), the remaining trigonometric functions can be calculated. tan(θ) = sin(θ)/cos(θ) = -\(3/5\) / \(4/5\) = -\(3/4\). By inversion, we get the values of csc(θ), sec(θ) and cot(θ). Hence, csc(θ) = -1/sin(θ) = -1/(-\(3/5\)) = \(5/3\), sec(θ) = 1/cos(θ) = 1/\(4/5\) = \(5/4\), cot(θ) = 1/tan(θ) = 1/(-\(3/4\)) = -\(4/3\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean Identity
When studying trigonometric functions, the Pythagorean identity is a crucial concept to grasp. It relates the squares of the sine and cosine functions to the number one. The main equation for the Pythagorean identity is \[ \sin^2(\theta) + \cos^2(\theta) = 1 \].
This equation is always true for any angle \( \theta \).
The identity is derived from the Pythagorean theorem which applies to right triangles and the unit circle. In the unit circle, the radius is 1, and the coordinates of any point on the circle are \( (\cos(\theta), \sin(\theta)) \). Therefore, by the Pythagorean theorem applied in this setting, \( \cos^2(\theta) + \sin^2(\theta) = 1 \).
This identity helps to solve various trigonometric problems.- For instance, if you know \( \cos(\theta) \), you can find \( \sin(\theta) \) using this identity.- Always remember to consider the sign of \( \sin(\theta) \) or \( \cos(\theta) \) based on the quadrant in which the angle \( \theta \) is located.
Unit Circle
The unit circle is a fundamental idea in trigonometry that helps understand angles and trigonometric functions better. The unit circle is simply a circle with a radius of 1, centered at the origin of a coordinate plane.
The significance of the unit circle is that it allows us to define the sine and cosine of any angle.Here are some key points to consider about the unit circle:
  • The angle \( \theta \) is measured from the positive x-axis, and it increases counterclockwise.
  • Each point on the unit circle can be represented as \( (\cos(\theta), \sin(\theta)) \).
  • The circle divides the plane into four regions known as quadrants, which impact the sign of the trigonometric functions.
  • The unit circle is particularly helpful for understanding periodic properties of trig functions as it visually displays how functions repeat.
Using the unit circle, you can quickly determine trigonometric functions' values for commonly encountered angles, like \( 0, \frac{\pi}{2}, \pi, \text{and } \frac{3\pi}{2} \).
It's a tool to interpret the behavior of trig functions easily.
Quadrants of Angles
Understanding the quadrants of angles is essential, especially when determining the signs of trigonometric functions. The coordinate plane is divided into four quadrants. Each quadrant affects the sign of sine, cosine, and tangent values.Here's a breakdown of the quadrants:
  • Quadrant I: Both sine and cosine values are positive.
  • Quadrant II: Sine is positive, while cosine is negative.
  • Quadrant III: Both sine and cosine values are negative.
  • Quadrant IV: Cosine is positive, while sine is negative.
These sign changes can be remembered using the acronym "All Students Take Calculus," which stands for:- **A**: All (positive in the first quadrant)- **S**: Sine (positive in the second quadrant)- **T**: Tangent (positive in the third quadrant)- **C**: Cosine (positive in the fourth quadrant)
In our example, since \( \theta \) is in quadrant IV, we know cosine is positive and sine is negative, guiding us to determine \( \sin(\theta) \) correctly.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The number of hours of daylight, \(H,\) on day \(t\) of any given year (on January \(1, t=1\) ) in San Diego, California, can be modeled by the function $$H(t)=12+2.4 \sin \left[\frac{2 \pi}{365}(t-80)\right]$$ a. March \(21,\) the 80 th day of the year, is the spring equinox. Find the number of hours of daylight in San Diego on this day. b. June \(21,\) the 172 nd day of the year, is the summer solstice, the day with the maximum number of hours of daylight. Find, to the nearest tenth of an hour, the number of hours of daylight in San Diego on this day. c. December \(21,\) the 355 th day of the year, is the winter solstice, the day with the minimum number of hours of daylight. To the nearest tenth of an hour, find the number of hours of daylight in San Diego on this day.

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$\tan ^{2} 15^{\circ}-\sec ^{2} 15^{\circ}=-1$$

Write an equation in slope-intercept form for the line passing through \((1,-1)\) and perpendicular to the line whose equation is \(x+10 y-13=0\)

Exercises \(117-119\) will help you prepare for the material covered in the next section. In each exercise, complete the table of coordinates. Do not use a calculator. $$y=3 \sin \frac{\pi}{2} x$$ $$\begin{array}{|l|l|l|l|l|l|l|l|l|} \hline x & 0 & \frac{1}{3} & 1 & \frac{5}{3} & 2 & \frac{7}{3} & 3 & \frac{11}{3} & 4 \\ \hline y & & & & & & & \\ \hline \end{array}$$ After completing this table of coordinates, plot the nine ordered pairs as points in a rectangular coordinate system. Then connect the points with a smooth curve.

Find all zeros of \(f(x)=2 x^{3}-5 x^{2}+x+2\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.