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In Exercises \(99-104,\) find two values of \(\theta, 0 \leq \theta<2 \pi,\) that satisfy each equation. $$\sin \theta=-\frac{\sqrt{2}}{2}$$

Short Answer

Expert verified
The two values of \(\theta\) that satisfy \(\sin\theta=-\frac{\sqrt{2}}{2}\) are \(\theta=5\pi/4\) and \(\theta=\pi\).

Step by step solution

01

Identify the quadrants where sine is negative

The sine function is negative in the third and fourth quadrants of the unit circle. In the unit circle, an angle \(\theta\) is measured in counter-clockwise direction from the positive x-axis, so the third quadrant corresponds to \(\pi < \theta < 3\pi/2\) and the fourth quadrant corresponds to \(3\pi/2 < \theta < 2\pi\).
02

Find the associated positive sine value

Next, we identify the positive sine value that is associated with the given negative sine value of \(-\sqrt{2}/2\). From the unit circle, we want to find an angle in the first or second quadrant where \(\sin\theta=\sqrt{2}/2\). This corresponds to angles of \(\pi/4\) and \(3\pi/4\).
03

Find the desired angles in the third and fourth quadrants

Now, as \(\sin\theta\) is the same for \(\theta\) and \(\pi-\theta\), and \(\sin(\pi+\theta)=-\sin\theta\) (since sine is negative in the third quadrant), we add \(\pi/4\) to \(\pi\) to find the angle in the third quadrant: \(\theta_1=\pi+\pi/4 = 5\pi/4\). Similarly, we subtract \(\pi/4\) from \(3\pi/2\) to find the angle in the fourth quadrant. The subtracting instead of adding here is due to the fact that subtraction gives us an angle still within the bounds of the fourth quadrant: \(\theta_2 = 3\pi/2 - \pi/4 = 4\pi/4=\pi\).
04

Confirm the Solutions

To confirm these solutions, verify that both \(\sin(5\pi/4)\) and \(\sin(\pi)\) equal \(-\sqrt{2}/2\). Both evaluations yield \(-\sqrt{2}/2\), confirming that \(\theta=5\pi/4\) and \(\theta=\pi\) are the solutions within the given bounds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Circle
The Unit Circle is a fundamental tool in trigonometry. It is a circle with a radius of 1, centered at the origin of a coordinate system. This circle helps us understand the relationships between angles and the corresponding values of trigonometric functions like sine and cosine.

When we measure angles on the unit circle, we start from the positive x-axis and move counter-clockwise for positive angles. A full rotation around the circle is equal to an angle of \(2\pi\) radians, which corresponds to 360 degrees. So, each point on the unit circle provides us with values for the sine and cosine functions, based on the coordinates \((x, y)\) of that point. The cosine value is the x-coordinate, and the sine value is the y-coordinate.

Understanding the unit circle is essential because it connects angles to algebraic expressions, serving as a bridge for solving trigonometric equations like \(\sin \theta = -\frac{\sqrt{2}}{2}\).
Sine Function
The sine function is one of the primary trigonometric functions. For any given angle in the unit circle, the sine value corresponds to the y-coordinate of the point where that angle intersects the circle.

This function is periodic with a cycle of \(2\pi\), meaning its values repeat every \(2\pi\) interval. The range of the sine function is between -1 and 1, encompassing all y-coordinate values possible on the unit circle.

For example, when solving the equation \(\sin \theta = -\frac{\sqrt{2}}{2}\), we are looking for angles where the sine function's output matches the given value. Here, finding equivalent angles means understanding symmetry and periodicity properties of this function, as well as its relationship to specific points on the unit circle.
Quadrants of the Unit Circle
The unit circle is divided into four quadrants, each having distinct characteristics with respect to the sine and cosine values:
  • Quadrant I: Both sine and cosine values are positive.
  • Quadrant II: Sine values are positive, while cosine values are negative.
  • Quadrant III: Both sine and cosine values are negative.
  • Quadrant IV: Sine values are negative, while cosine values are positive.
Identifying which quadrant an angle is in helps determine the sign of trigonometric functions for that angle. Since the sine function is negative for angles in Quadrants III and IV, this plays a crucial role in solving equations where we expect negative sine values. Understanding these quadrant properties is key to navigating the unit circle effectively.
Negative Sine Values
Negative sine values occur in the third and fourth quadrants of the unit circle. This is because of the position and symmetry of the unit circle relative to the axes.To find angles with a specific negative sine value, we first identify the equivalent positive sine value in the first or second quadrant. After finding that reference angle, we use it to determine the corresponding negative sine angles:
  • In Quadrant III, add \(\pi\) to the reference angle since \( \sin(\pi + \theta) = -\sin \theta \).
  • In Quadrant IV, subtract the reference angle from \(\frac{3\pi}{2}\) because of symmetry, resulting in \(\sin(\frac{3\pi}{2} - \theta) = -\sin \theta \).
By following these principles, we can identify angles such as \(\theta = 5\pi/4\) and \(\theta = 7\pi/4\), which have a sine of \(-\frac{\sqrt{2}}{2}\), verifying our steps in solving trigonometric equations.

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Most popular questions from this chapter

a. Graph \(y=\tan x\) for \(-\frac{\pi}{2}

The number of hours of daylight, \(H,\) on day \(t\) of any given year (on January \(1, t=1\) ) in Fairbanks, Alaska, can be modeled by the function $$H(t)=12+8.3 \sin \left[\frac{2 \pi}{365}(t-80)\right]$$ a. March \(21,\) the 80 th day of the year, is the spring equinox. Find the number of hours of daylight in Fairbanks on this day. b. June \(21,\) the 172 nd day of the year, is the summer solstice, the day with the maximum number of hours of daylight. To the nearest tenth of an hour, find the number of hours of daylight in Fairbanks on this day. c. December \(21,\) the 355 th day of the year, is the winter solstice, the day with the minimum number of hours of daylight. Find, to the nearest tenth of an hour, the number of hours of daylight in Fairbanks on this day.

Explain how to convert an angle in radians to degrees.

Let $$\sin t=a, \cos t=b, \text { and } \tan t=c$$ Write each expression in terms of \(a, b,\) and \(c .\) $$\begin{array}{r}-\cos t+7 \cos (t+1000 \pi)+\tan t+\tan (t+999 \pi)+ \sin t+\sin (t-1000 \pi)\end{array}$$

Will help you prepare for the material covered in the first section of the next chapter. The exercises use identities, introduced in Section \(4.2,\) that enable you to rewrite trigonometric expressions so that they contain only sines and cosines: $$\begin{array}{ll} \csc x=\frac{1}{\sin x} & \sec x=\frac{1}{\cos x} \\ \tan x=\frac{\sin x}{\cos x} & \cot x=\frac{\cos x}{\sin x} \end{array}$$ Rewrite each expression by changing to sines and cosines. Then simplify the resulting expression. $$\tan x \csc x \cos x$$

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