Chapter 3: Problem 41
evaluate each expression $$8^{\log _{8} 19}$$
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Chapter 3: Problem 41
evaluate each expression $$8^{\log _{8} 19}$$
These are the key concepts you need to understand to accurately answer the question.
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The loudness level of a sound can be expressed by comparing the sound's intensity to the intensity of a sound barely audible to the human ear. The formula $$D=10\left(\log I-\log I_{0}\right)$$ describes the loudness level of a sound, \(D\), in decibels, where \(I\) is the intensity of the sound, in watts per meter \(^{2},\) and \(I_{0}\) is the intensity of a sound barely audible to the human ear. a. Express the formula so that the expression in parentheses is written as a single logarithm. b. Use the form of the formula from part (a) to answer this question: If a sound has an intensity 100 times the intensity of a softer sound, how much larger on the decibel scale is the loudness level of the more intense sound?
determine whether each statement makes sense or does not make sense, and explain your reasoning. I estimate that \(\log _{8} 16\) lies between 1 and 2 because \(8^{1}=8\) and \(8^{2}=64\)
Determine whether each equation is true or false. Where possible, show work to support your conclusion. If the statement is false, make the necessary change(s) to produce a true statement. $$\log _{6}[4(x+1)]=\log _{6} 4+\log _{6}(x+1)$$
Find the inverse of \(f(x)=x^{2}+4, x \geq 0\)
Will help you prepare for the material covered in the next section. Solve for \(x: a(x-2)=b(2 x+3)\)
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