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Determine whether each statement makes sense or does not make sense, and explain your reasoning. It's important for me to check that the proposed solution of an equation with logarithms gives only logarithms of positive numbers in the original equation.

Short Answer

Expert verified
The statement does make sense, because we can only take logarithms of positive numbers. Any proposed solution to a logarithmic equation therefore has to be checked so that it doesn't result in the logarithm of a non-positive number in the original equation.

Step by step solution

01

Understanding the statement

The statement talks about an equation containing logarithms. It's mentioned that the solution must only give logarithms of positive numbers in the original equation.
02

Applying the properties of logarithms

According to the properties of logarithms, taking a logarithm of a negative number or zero is undefined. Thus, the logarithm function is only defined for positive real numbers.
03

Evaluating the statement

Considering these log properties, the statement does make sense. In order to prevent undefined solutions or error states when solving logarithmic equations, it's important to ensure that any proposed solution only results in the logarithms of positive numbers being used in the original equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Logarithms
Logarithms have specific properties that govern how they can be used and manipulated. One key property is that the logarithm of a negative number or zero is undefined. This is because logarithms are the inverse operations of exponentiation. For example, in the equation \( \log_b(x) \), \( x \) has to be a positive number since there is no power you can raise a positive base \( b \) to get a negative number or zero.

Other important properties include:
  • Product Rule: \( \log_b(MN) = \log_b(M) + \log_b(N) \), which lets you split the logarithm of a product into the sum of two logarithms.
  • Quotient Rule: \( \log_b\left(\frac{M}{N}\right) = \log_b(M) - \log_b(N) \), useful for breaking down the logarithm of a quotient into a difference.
  • Power Rule: \( \log_b(M^k) = k\log_b(M) \), allowing you to move the exponent to a coefficient in front of the logarithm.
Each of these properties helps in simplifying complex logarithmic expressions, making them easier to work with when solving equations.
Solving Logarithmic Equations
Solving logarithmic equations often involves using the properties of logarithms to simplify the equation. The goal is usually to isolate the logarithms on one side of the equation so that you can eliminate the logarithms by exponentiating both sides. For instance, consider the equation \( \log_b(x) = y \). You need to rewrite this in its exponential form as \( x = b^y \).

A good strategy when solving these equations is to first use the properties of logarithms to condense multiple logarithmic terms into a single expression. For example, if you have \( \log_b(x) + \log_b(y) \), you can combine them into \( \log_b(xy) \).

Always check the domain of the problem to ensure your solutions are valid. This involves making sure the arguments of all logarithmic terms are positive numbers, otherwise those solutions might be undefined.
Undefined Solutions
In the context of logarithmic equations, undefined solutions occur when the operation involves taking a logarithm of a negative number or zero. Such scenarios are not valid because the logarithmic function is not defined for these values.

When you solve a logarithmic equation, it's necessary to backtrack and check that each solution results in positive arguments for all of the logarithms in the original equation. This step is crucial to avoid any mathematical errors commonly referred to as 'undefined solutions'.

Practically, after solving the equation, substitute the solution back into the equation to ensure all log terms are valid. If any term has a negative input, discard that solution as it's not within the domain of the logarithmic function.
These checks prevent miscalculations and ensure that your answers are correct and enforce the logic inherent in logarithmic properties.

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Most popular questions from this chapter

Determine whether each statement makes sense or does not make sense, and explain your reasoning. Because logarithms are exponents, the product, quotient, and power rules remind me of properties for operations with exponents.

Solve each logarithmic equation. Be sure to reject any value of \(x\) that is not in the domain of the original logarithmic expressions. Give the exact answer. Then, where necessary, use a calculator to obtain a decimal approximation, correct to two decimal places, for the solution. $$\ln (x-2)-\ln (x+3)=\ln (x-1)-\ln (x+7)$$

Solve each exponential equation. Express the solution set in terms of natural logarithms or common logarithms. Then use a calculator to obtain a decimal approximation, correct to two decimal places, for the solution. $$9 e^{x}=107$$

Use Newton's Law of Cooling, \(T=C+\left(T_{0}-C\right) e^{k t},\) to solve Exercises \(47-50\). A frozen steak initially has a temperature of \(28^{\circ} \mathrm{F}\). It is left to thaw in a room that has a temperature of \(75^{\circ} \mathrm{F}\). After 10 minutes, the temperature of the steak has risen to \(38^{\circ} \mathrm{F}\). After how many minutes will the temperature of the steak be \(50^{\circ} \mathrm{F} ?\)

Students in a psychology class took a final examination. As part of an experiment to see how much of the course content they remembered over time, they took equivalent forms of the exam in monthly intervals thereafter. The average score for the group, \(f(t),\) after \(t\) months was modeled by the function $$ f(t)=88-15 \ln (t+1), \quad 0 \leq t \leq 12 $$ a. What was the average score on the original exam? b. What was the average score after 2 months? 4 months? 6 months? 8 months? 10 months? one year? c. Sketch the graph of \(f\) (either by hand or with a graphing utility). Describe what the graph indicates in terms of the material retained by the students.

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