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a. Use the Leading Coefficient Test to determine the graph's end behavior. b. Find the \(x\) -intercepts. State whether the graph crosses the \(x\) -axis, or touches the \(x\) -axis and turns around, at each intercept. c. Find the \(y\) -intercept. d. Determine whether the graph has \(y\) -axis symmetry, origin symmetry, or neither. e. If necessary, find a few additional points and graph the function. Use the maximum number of turning points to check whether it is drawn correctly. $$f(x)=-3(x-1)^{2}\left(x^{2}-4\right)$$

Short Answer

Expert verified
The graph of \(f(x)=-3(x-1)^{2}\left(x^{2}-4\right)\) has both ends pointing downwards, x-intercepts at -2, 1, 2, y-intercept at (0,12), shows no form of symmetry, and has 3 turning points. Its end behavior, intercepts and turning points guide its sketching

Step by step solution

01

Apply the Leading Coefficient Test

The leading coefficient test can determine the end behavior of the graph. The degree of the function \(f(x)=-3(x-1)^{2}\left(x^{2}-4\right)\) is 2+2=4, which is even. The leading coefficient -3 is negative. Thus, according to the Leading Coefficient Test, both ends of the graph are down.
02

Solve for x-intercepts

The x-intercepts are found by setting the function equal to zero and solving for x. \(f(x)=0\) gives \(x=1\) and \(x=±2\). The function crosses the x-axis at \(x=-2\) and \(x=2\) (because the multiplicity of the zeros are 1, odd multiplicities) and touches the x-axis at \(x=1\) and turns around (because the multiplicity of the zero is 2, even multiplicity ). So, the x-intercepts are \(-2, 1\), and \(2\).
03

Find the y-intercept

The y-intercept is found by plugging x=0 into the function. So, \(f(0)=-3(0-1)^{2}\left((0)^{2}-4\right)=-3(-1)^{2}\cdot(-4)=12\). Thus the y-intercept is (0,12)
04

Determine the symmetry

To have a y-axis symmetry, for every point (x,y) there must be a corresponding point (-x,y). For origin symmetry, for every point (x,y), there must be a corresponding point (-x,-y). Substituting x with -x in the equation to check, it's observed that it won't result in the original equation, so the function has neither y-axis nor origin symmetry.
05

Sketch the graph

Plot the intercepts and symmetry, and sketch smoothly through all the points. You should get a curve that touches the \(x\)-axis at \(x= 1\) and crosses the \(x\)-axis at \(x= -2\) and \(x= 2\). Both ends of the plot should point downwards since the leading coefficient is negative and the degree is even. The maximum number of turning points for a polynomial of degree 4 is 4-1=3. So, must check if the drawn graph has 3 turning points.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

end behavior
When discussing polynomial functions, end behavior is an important concept to understand. It describes how the function behaves as the input values become very large or very small. To determine end behavior, the Leading Coefficient Test is used. In our example, the polynomial is given by \(f(x)=-3(x-1)^2(x^2-4)\). The degree of the polynomial is calculated by adding the powers of all factors, resulting in a degree of 4, which is even. Because the degree is even, both ends of the polynomial graph will tend in the same direction.
The leading coefficient is the coefficient of the term with the highest degree, which here is -3. Since this coefficient is negative, both ends of the graph of the polynomial will point downwards. As a result, as \(x\) approaches positive infinity, and as it approaches negative infinity, \(f(x)\) decreases without bound. This pattern of both ends of the graph pointing downwards is a crucial aspect of visualizing high-degree polynomials visually.
x-intercepts
The x-intercepts of a polynomial function are the points where the graph crosses or touches the x-axis. For the function\(f(x)=-3(x-1)^2(x^2-4)\), we find the x-intercepts by solving \(f(x)=0\). This leads us to the intercepts at \(x=1\), \(x=-2\), and \(x=2\). Understanding the multiplicity of these roots helps us determine how the graph interacts with the x-axis.
  • If the root has an odd multiplicity, the graph crosses the x-axis at that point. This can be observed at \(x=-2\) and \(x=2\) in our function, as they have a multiplicity of 1.
  • If the root has an even multiplicity, the graph touches and bounces off the x-axis instead of crossing it. This happens at \(x=1\) because the multiplicity is 2.
X-intercepts are crucial for understanding the positions where the graph has potential changes in direction or showcases symmetries.
y-intercepts
Y-intercepts represent the point where the graph of the polynomial intersects the y-axis. To find the y-intercept of a polynomial, set \(x\) equal to zero and solve for \(f(x)\). For the polynomial \( f(x) = -3(x-1)^2(x^2-4) \), substituting 0 for \( x \) gives \( f(0) = -3(0-1)^2(0^2-4) = 12 \). Therefore, the y-intercept occurs at the point (0, 12).

The y-intercept provides essential information for graph sketching, setting one of the fixed points that guide the graph's trajectory in the early stages. It's a straightforward calculation but crucial for ensuring the graph aligns with the actual shape of the polynomial.
symmetry
Symmetry in polynomial functions helps simplify the graphing process, making predictions about the graph's appearance possible. Testing symmetry involves substituting \( x \) with \( -x \) in the function and observing the outputs:
  • If \( f(-x) = f(x) \), the function has y-axis symmetry. This means the graph is a mirror image about the y-axis.
  • If \( f(-x) = -f(x) \), the function is symmetric about the origin and exhibits a point reflection through the origin.
  • If neither of these conditions holds, the function has no symmetry.
For the function \( f(x) = -3(x-1)^2(x^2-4) \), neither condition is fulfilled, indicating no symmetry. Understanding symmetry, or the lack thereof, in polynomial functions can guide the sketching of detailed and accurate graphs.
graphing polynomial functions
Graphing polynomial functions involves combining all the insights from end behavior, intercepts, symmetry, and more. Here, begin with plotting the intercepts found earlier: the x-intercepts at \(x=-2\), \(x=1\), and \(x=2\), and the y-intercept at (0, 12). Understanding the end behavior from the Leading Coefficient Test, recognize that both ends of the graph should approach negative infinity.
Using our knowledge of turning points is also crucial. For a polynomial of degree 4, the maximum number of turning points is three. After plotting the intercepts and using the information about where the graph crosses versus touches the x-axis, create a smooth curve connecting these points.

Ensure that the graph accurately reflects all aspects of the function's behavior, and if necessary, calculate additional points to make sure the graph transitions smoothly between intercepts. Practice and visualization tools can help solidify these concepts, allowing one to graph polynomial functions accurately.

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