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91Ó°ÊÓ

Write an equation in standard form of the parabola that has the same shape as the graph of \(f(x)=3 x^{2}\) or \(g(x)=-3 x^{2},\) but with the given maximum or minimum. Write an equation in standard form of the parabola that has the same shape as the graph of \(f(x)=3 x^{2}\) or \(g(x)=-3 x^{2},\) but with the given maximum or minimum. Maximum \(=4\) at \(x=-2\)

Short Answer

Expert verified
The equation of the parabola that has the same shape as \(f(x)=3 x^{2}\) or \(g(x)=-3 x^{2},\) with maximum \(=4\) at \(x=-2\) is \(y = -3(x+2)^2 + 4\).

Step by step solution

01

identify the given parameters

Here the given parameters are: vertex values \(h = -2\), \(k = 4\) and \(a = -3\).
02

apply these parameters to the standard form

In the standard form of the parabola equation \(y=a(x-h)^2+k\), replace \(a\), \(h\), and \(k\) with the values identified in the previous step. Which gives us: \(y = -3(x - (-2))^2 + 4\).
03

simplify the equation

Simplify the equation from the last step: \(y = -3(x+2)^2 + 4\). This is the required equation of the parabola which has a maximum of 4 at x=-2 and the same shape as \(y=-3x^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parabola Maximum and Minimum
Understanding the maximum and minimum values of a parabola is crucial when analyzing the graph of a quadratic function. A parabola is a U-shaped curve that can either open upwards, displaying a minimum point at its vertex, or downwards, showing a maximum point at its vertex. These points are significant as they represent the extreme values of the parabola.

When the coefficient of the squared term in the parabola's equation is positive, it opens upwards and has a minimum point. Conversely, a negative coefficient results in the parabola opening downwards, with the vertex representing a maximum point. In the exercise provided, the coefficient \(a = -3\) indicates that the parabola opens downward, and thus the point with the maximum value is specified as \(k = 4\) at \(x = -2\).

To find a parabola's maximum or minimum value, we can use the vertex formula or complete the square to transform the equation into vertex form, which directly gives the vertex coordinates. This makes it easier to identify these extreme values at a glance.
Vertex Form of a Parabola
The vertex form of a parabola's equation is an insightful representation that makes it easy to identify the vertex's coordinates and understand the graph's properties. This form is expressed as \(y = a(x - h)^2 + k\), where \(h\) and \(k\) are the x and y coordinates of the vertex, respectively, and \(a\) indicates how wide or narrow the parabola is, as well as its direction of opening.

For example, in the exercise, the parabola's equation has the vertex form \(y = -3(x + 2)^2 + 4\) after substituting the given vertex values of \(h = -2\) and \(k = 4\), and the stretch factor \(a = -3\). The negative value of \(a\) conveys that the parabola opens downwards, revealing that the vertex \(h, k\) corresponds to the maximum point of the curve. This form is incredibly valuable when graphing parabolas since knowing the vertex and the direction of opening simplifies plotting the curve.
Parabola Transformations
Parabola transformations involve shifting, reflecting, stretching, and compressing the basic \(y = x^2\) parabola to alter its appearance on a graph. These transformations correspond to changes in the equation's parameters. A vertical shift is determined by the \(k\) value in the vertex form; positive \(k\) shifts the parabola up, while negative shifts it down. Horizontally, the parabola is shifted by the \(h\) value; positive \(h\) shifts it to the right, negative to the left.

Reflections are dictated by the coefficient \(a\); a negative \(a\) reflects the parabola across the x-axis. The absolute value of \(a\) affects the parabola's width: values greater than 1 stretch the parabola vertically, making it narrower, while values between 0 and 1 compress it, making it wider. In the given exercise, the transformation includes a horizontal shift left by 2 units (because \(h = -2\)), a vertical shift up by 4 units (since \(k = 4\)), and a reflection across the x-axis with a vertical stretch (as \(a = -3\)). These transformations shape the new parabola allowing us to form the desired graph with the specified maximum.

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