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Solve each quadratic equation using the quadratic formula. Express solutions in standard form. $$x^{2}-6 x+10=0$$

Short Answer

Expert verified
The solutions of the quadratic equation \(x^{2}-6 x+10=0\) are \(x = 3+i\) and \(x = 3-i\).

Step by step solution

01

Identify a, b, and c

In the equation \(x^{2}-6 x+10=0\), the coefficient of \(x^{2}\) is the value for 'a', the coefficient of 'x' is the value for 'b', and the constant term is the value for 'c'. So \(a=1\), \(b=-6\), \(c=10\).
02

Substitute into the Quadratic Formula

We substitute \(a=1\), \(b=-6\), and \(c=10\) into the quadratic formula \( \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). This becomes \( \frac{-(-6) \pm \sqrt{(-6)^2 - 4*1*10}}{2*1} \).
03

Simplify

Simplify the expression to get the solution. \( \frac{6 \pm \sqrt{36 - 40}}{2} \), simplifies to \( \frac{6 \pm \sqrt{-4}}{2} \). Since the square root of a negative number is an imaginary number, we express \(\sqrt{-4}\) as \(2i\).
04

Final Simplification

We continue simplifying \(\frac{6 \pm 2i}{2}\) to get \(3 \pm i\). So the solutions of the quadratic equation \(x^{2}-6 x+10=0\) are \(x = 3+i\) and \(x = 3-i\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Quadratic Equations
Understanding how to solve quadratic equations is an essential skill in algebra. The process involves finding the values of the variable (usually 'x') that make the equation true. When it comes to quadratic equations like the one we have, which is of the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants, one effective method to find solutions is using the quadratic formula. This formula is \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), and it provides a straightforward way to solve for \(x\) even when the equation cannot be factored easily.

Applying the quadratic formula involves several steps. First, you’ll identify the coefficients \(a\), \(b\), and \(c\) from the quadratic equation. Then, substitute these values into the formula. Afterward, you need to simplify the expression within the square root, known as the discriminant. The discriminant \(b^2 - 4ac\) determines the nature of the roots—whether they are real or complex. In our example, the discriminant is negative, leading us to encounter complex numbers in the solution. Lastly, you'll simplify the result to obtain the standard form of the roots of the equation.
Complex Numbers
Often, when solving quadratic equations, you'll stumble upon a negative discriminant which can't be simplified within the realm of real numbers. This is when complex numbers come into play. A complex number is a combination of a real number and an imaginary number, usually represented as \(a + bi\), where \(i\) is the imaginary unit (the square root of -1).

In the course of our problem-solving, we encounter a negative under the square root, which signals the presence of the imaginary number. For instance, \(\sqrt{-4}\) is expressed as \(2i\) because \(i\) is defined to be \sqrt{-1}. As such, the concept of complex numbers expands the number system and allows us to solve quadratic equations with negative discriminants. In our quadratic formula solution, we end up with two complex roots: \(3 + i\) and \(3 - i\). Both solutions are valid in the complex plane, even though they aren't real numbers in the traditional sense.
Quadratic Equation Standard Form
The standard form of a quadratic equation is given by \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants and the highest exponent of \('x'\) is 2. In this arrangement, the equation clearly displays the squared term, the linear term, and the constant term. This form is not just for presentation; it's essential for identifying the coefficients needed to apply the quadratic formula effectively.

Our example equation, \(x^2 - 6x + 10 = 0\), is already in standard form, with \(a\) equal to 1, \(b\) equal to -6, and \(c\) equal to 10. Keeping the quadratic equation in standard form ensures a clear path to employ the quadratic formula, which ultimately allows us to find the solutions quickly. Whether the roots are real numbers or complex numbers, the standard form serves as the starting block for the solution process.

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