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Use the vertex and intercepts to sketch the graph of each quadratic function. Give the equation of the parabola's axis of symmetry. Use the graph to determine the function's domain and range. $$f(x)=(x-1)^{2}-2$$

Short Answer

Expert verified
The vertex of the function is at point (1, -2). The axis of symmetry is \(x = 1\). The x-intercepts are \(x = \sqrt{2} + 1\) and \(x = 1 - \sqrt{2}\), the y-intercept is \(f(0) = -1\). The domain is all real numbers and the range is \(y ≥ -2\).

Step by step solution

01

Determine the Vertex

The given equation is already in vertex form, \(f(x) = a(x - h)^2 + k\), where the vertex (h, k) is (1, -2). So, the vertex of this quadratic function is at point (1, -2).
02

Determine the Axis of Symmetry

In a parabola, the axis of symmetry is a vertical line that passes through the vertex. Therefore, the equation is \(x = h\), where h = vertex's x-coordinate = 1. So the axis of symmetry is \(x = 1\).
03

Determine the Intercepts

The x-intercepts are found by setting \(f(x) = 0\). Solving \(0 = (x - 1)^2 - 2\), we get \(x = \sqrt{2} + 1\) and \(x = 1 - \sqrt{2}\). The y-intercept is found by setting \(x = 0\), which gives \(y = f(0) = -1\).
04

Sketch the Graph

Plot the vertex, y-intercept and x-intercepts on the graph. Use the axis of symmetry to ensure the balance of the parabola on both sides. Draw a smooth curve through these points.
05

Determine the Domain and Range

For any quadratic function, the domain (possible x-values) is all real numbers. The range (possible y-values), for a parabola opening upwards or downwards corresponds to \(y ≤ k\) or \(y ≥ k\). Since this parabola opens upwards, the range is \(y ≥ -2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertex Form
The vertex form of a quadratic function is a precise way to express the function, making it simple to identify important features like the vertex. It is given by the formula \(f(x) = a(x - h)^2 + k\). Here, \(a\) affects the "width" and "direction" of the parabola, \(h\) indicates the x-coordinate and \(k\) the y-coordinate of the vertex. Thus, the vertex of the parabola can be directly identified from the equation. In our example with the function \(f(x) = (x - 1)^2 - 2\), the vertex is \( (1, -2) \). Understanding the vertex form allows us to quickly locate the highest or lowest point of the parabola, which is quite helpful when sketching the graph accurately.
Axis of Symmetry
The axis of symmetry in a quadratic function is a vertical line that divides the parabola into two mirror-image halves. This geometric property helps in sketching and understanding the graph better, since the parabola is symmetrical with respect to this line. The equation of the axis of symmetry is derived from the x-coordinate of the vertex, given by \(x = h\). In our function \(f(x) = (x - 1)^2 - 2\), we find \(h = 1\). Therefore, the axis of symmetry is the vertical line \(x = 1\). This line guides us in ensuring the correct positioning and balance of the parabola on the graph.
Parabola Graph
Graphing a parabola effectively involves plotting several key points: the vertex, the x-intercepts, and the y-intercept. First, the vertex \((1, -2)\) is drawn, which is the turning point of the parabola. Then, find the x-intercepts by solving \((x - 1)^2 - 2 = 0\), which gives solutions \(x = 1 + \sqrt{2}\) and \(x = 1 - \sqrt{2}\). Also, calculate the y-intercept by finding \(f(0) = -1\), the value of the function when \(x = 0\). Plot all these points accurately. Using the axis of symmetry \(x = 1\), ensure that the drawn parabola is symmetrical around this line, forming a smooth curve that opens upwards.
Domain and Range
The domain and range are crucial in understanding the extent of the parabola on the graph. For quadratic functions like \(f(x) = (x - 1)^2 - 2\), the domain is always all real numbers because any real value of \(x\) can be inputted into the function without constraint. Hence, the domain is \((-\infty, \infty)\). The range, however, defines the possible output values \(y\). Since the parabola opens upwards, the lowest point is the y-coordinate of the vertex. Hence, the range is \(y \geq -2\). This tells us that \(f(x)\) will reach all y-values greater than or equal to \(-2\), emphasizing that the vertex provides the minimum value for the y-coordinate in this upward-opening parabola.

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