/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Solve each polynomial inequality... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each polynomial inequality and graph the solution set on a real number line. Express each solution set in interval notation. $$x^{2}-2 x+1>0$$

Short Answer

Expert verified
The solution set is \((1, +\infty)\). The inequality is only satisfied for \(x>1\).

Step by step solution

01

Determine the Critical Points

To find the critical points, set the inequality \(x^2-2x+1>0\) equal to zero, i.e., solve the equation \(x^2-2x+1=0\). This can be done by factoring, completing the square, or using the quadratic formula. In this case, this equation is a perfect-square trinomial and can be factored as \((x-1)^2=0\). Therefore, the only critical point is \(x=1\).
02

Test the Intervals

Next, divide the number line into intervals based on the critical points to determine where the inequality is satisfied. In this case, the partitions are \(-\infty < x < 1\) and \(1 < x < +\infty\). Pick a test point in each interval and substitute it back into the inequality. For example, use \(x=0\) for the first interval and \(x=2\) for the second interval.
03

Determine Sign of Each Interval

When \(x=0\), the inequality \(x^2-2x+1 > 0\) is satisfied as \(-1 > 0\) is false. When \(x=2\), the inequality is also not satisfied as \(1 > 0\) is true. Therefore, the inequality is only true for \(x>1\).
04

Draw the Number Line and Express in Interval Notation

Draw a number line, plot the critical point, shade the interval where the inequality is true. Since the inequality is strictly 'greater than (>)', do not include the critical point in the solution set. Using interval notation, the solution set is \((1, +\infty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Points
Critical points are pivotal in understanding polynomial inequalities. Essentially, a critical point is a value of the variable where the polynomial changes its behavior. In practice, to find critical points for a polynomial inequality, we set the polynomial equal to zero. This is because these points usually signify where the polynomial crosses the x-axis or where a change in the inequality sign might occur.
In our exercise, the polynomial is \(x^2 - 2x + 1 > 0\), and we set it to zero differently by finding solutions to \((x-1)^2 = 0\). Solving this equation yields the critical point \(x=1\).
These critical points are essential in dividing the number line into different intervals, which helps us analyze where the inequality holds true. Specific to this inequality, it indicates testing zones around the critical point, such as \((-\infty, 1)\) and \((1, +\infty)\), forming the foundation for further checking.
Interval Notation
Interval notation is a concise way to represent the set of solutions for inequalities. In math, it helps to depict parts of the number line that satisfy the given inequality, avoiding the use of lengthy sentences or cumbersome descriptions.
Intervals are denoted by brackets and parentheses, with specific meanings:
  • Round brackets \(()\) indicate that the endpoint is not included in the interval, marking a strict inequality.
  • Square brackets \([]\) indicate that the endpoint is included, marking an equality.
For example, in \((1, +\infty)\), the round bracket at \(1\) shows the number 1 is not part of the solutions.
In our situation, we determined that the inequality \(x^2 - 2x + 1 > 0\) is true for the numbers greater than 1. Therefore, we use interval notation \((1, +\infty)\) to succinctly express this solution set. This approach is not only efficient but also visually meaningful when plotting these intervals on the number line.
Number Line
A number line is a visual representation that helps us understand and solve inequalities in a simple and intuitive manner. When dealing with polynomial inequalities, like \(x^{2} - 2x + 1 > 0\), the number line is instrumental to see where the inequality holds.
We start by plotting the critical points determined earlier on the number line. For \(x=1\), which is a critical point, we mark it and test intervals around it by substituting sample points from each interval back into the polynomial inequality.
This specific exercise involves examining intervals such as \((-\infty, 1)\) and \((1, +\infty)\). By evaluating points like \(x=0\) and \(x=2\), you see which intervals satisfy the condition \(x^2 - 2x + 1 > 0\). In this example, shading the number line for \((1, +\infty)\) and excluding \(1\) with an open circle highlights the solution graphically. Thus, using these techniques makes the results more understandable and tangible.

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