/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Write the first six terms of eac... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write the first six terms of each arithmetic sequence. $$a_{1}=-8, d=5$$

Short Answer

Expert verified
The first six terms of the arithmetic sequence are -8, -3, 2, 7, 12, 17.

Step by step solution

01

Calculate the first term

The first term is given as \(a_{1} = -8\). So, there's no need of calculation for this term.
02

Calculate the second term

Using the formula \(a_n = a_{1} + (n - 1) \cdot d\), the second term will be \(a_{2} = a_{1} + (2 - 1) \cdot 5 = -8 + 1 \cdot 5 = -3\).
03

Calculate the third term

Using the formula \(a_n = a_{1} + (n - 1) \cdot d\), the third term will be \(a_{3} = a_{1} + (3 - 1) \cdot 5 = -8 + 2 \cdot 5 = 2\).
04

Calculate the fourth term

Using the formula \(a_n = a_{1} + (n - 1) \cdot d\), the fourth term will be \(a_{4} = a_{1} + (4-1) \cdot 5 = -8 + 3 \cdot 5 = 7\).
05

Calculate the fifth term

Using the formula \(a_n = a_{1} + (n - 1) \cdot d\), the fifth term will be \(a_{5} = a_{1} + (5 - 1) \cdot 5 = -8 + 4 \cdot 5 = 12\).
06

Calculate the sixth term

Using the formula \(a_n = a_{1} + (n - 1) \cdot d\), the sixth term will be \(a_{6} = a_{1} + (6 - 1) \cdot 5 = -8 + 5 \cdot 5 = 17\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sequence Terms Calculation
Understanding how to calculate the terms in a sequence is a foundational skill in arithmetic. An arithmetic sequence is a list of numbers with a specific pattern, where each term is derived from the previous one by adding a constant value, known as the common difference. When we say term, we refer to each number in the sequence.

For calculating terms in an arithmetic sequence, we use a straightforward formula: \(a_n = a_1 + (n - 1) \times d\). In this formula, \(a_n\) represents the n-th term of the sequence, \(a_1\) is the first term, \(n\) is the number of terms, and \(d\) is the common difference. The formula allows us to find any term within the sequence without always having to calculate all previous terms.

For instance, if we're given the first term of a sequence as \(-8\) and the common difference as \(5\), calculating the next terms involves simply plugging these values into the formula. This approach offers a methodical and efficient way to discover the progression of numbers within arithmetic sequences.
Common Difference
The common difference is the heart of an arithmetic sequence. It's the consistent interval or difference between successive terms of the sequence. To identify it, you subtract any term in the sequence (except the first one) by the preceding term. In our example, every term after \(a_1\) is always \(5\) more than the term before it, hence, \(d=5\).

This common difference can be thought of as the 'step size' from one term to the next and determines the sequence's growth rate. A positive common difference means the sequence increments, while a negative one indicates it decrements. If the common difference is zero, all terms are constant. Recognizing the common difference is paramount for the continuation and prediction of terms in arithmetic progressions and it simplifies calculations, allowing students to focus more on the application and less on repetitive computation.
Arithmetic Progression
An arithmetic progression (AP) is a sequence where each term after the first is obtained by adding the common difference to the preceding term. The significance of an AP is not just in the pattern of numbers it exhibits, but also in its broad use in various fields such as finance, computer science, and physics.

One real-world example is calculating the payment amounts for a loan which are fixed and spaced at regular intervals - an arithmetic progression.

To visualize an AP, imagine stepping uniformly up a flight of stairs; each step up is akin to adding the common difference to get to the next term. This concept is practical for linear predictions, compute sums quickly, and solving real-life problems that follow a linear growth or decay pattern.

The arithmetic progression is also the foundation for understanding more complex series and patterns in mathematics. The ease of determining any term in the sequence, due to the consistent addition of the common difference, makes arithmetic progression a simple yet powerful tool in number theory.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Fermat's most notorious theorem, described in the section opener on page 1078 , baffled the greatest minds for more than three centuries. In 1994 , after ten years of work, Princeton University's Andrew Wiles proved Fermat's Last Theorem. People magazine put him on its list of "the 25 most intriguing people of the year," the Gap asked him to model jeans, and Barbara Walters chased him for an interview." Who's Barbara Walters?" asked the bookish Wiles, who had somehow gone through life without a television. Using the 1993 PBS documentary "Solving Fermat: Andrew Wiles" or information about Andrew Wiles on the Internet, research and present a group seminar on what Wiles did to prove Fermat's Last Theorem, problems along the way, and the role of mathematical induction in the proof.

Show that \(B\) is the multiplicative inverse of \(A,\) where $$ A=\left[\begin{array}{ll} 2 & 3 \\ 1 & 2 \end{array}\right] \text { and } B=\left[\begin{array}{rr} 2 & -3 \\ -1 & 2 \end{array}\right] $$

Explain how to find the probability of an event not occurring. Give an example.

Will help you prepare for the material covered in the next section. Each exercise involves observing a pattern in the expanded form of the binomial expression \((a+b)^{n}\). $$\begin{array}{l} (a+b)^{1}=a+b \\ (a+b)^{2}=a^{2}+2 a b+b^{2} \\ (a+b)^{3}=a^{3}+3 a^{2} b+3 a b^{2}+b^{3} \\ (a+b)^{4}=a^{4}+4 a^{3} b+6 a^{2} b^{2}+4 a b^{3}+b^{4} \\ (a+b)^{5}=a^{5}+5 a^{4} b+10 a^{3} b^{2}+10 a^{2} b^{3}+5 a b^{4}+b^{5} \end{array}$$ Describe the pattern for the exponents on \(a\).

Make Sense? In Exercises \(66-69\), determine whether each statement makes sense or does not make sense, and explain your reasoning. When I toss a coin, the probability of getting heads or tails is 1 but the probability of getting heads and tails is 0.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.