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Use the Binomial Theorem to expand each binomial and express the result in simplified form. $$(c+2)^{5}$$

Short Answer

Expert verified
The simplified form of \((c+2)^{5}\) is \(32c^5 + 320c^4 + 1280c^3 + 2560c^2 + 2560c + 1024\).

Step by step solution

01

Understand the Binomial Theorem

The Binomial Theorem states that: \( (a + b)^n = a^n + C(n, 1)a^{n-1}b + C(n, 2)a^{n-2}b^2 +…+C(n, n)b^n \)Where \(\) is a combination. 'n' is the power of the binomial and C(n, k) represents the number of combinations of 'n' items taken 'k' at a time.
02

Apply the Binomial Theorem

We apply it to \((c+2)^5\) . For this, we substitute 'a' with 'c', 'b' with '2' and 'n' with '5'. Always be sure to simplify each individual term and then sum up at the end.
03

Simplify the Expression

After applying the theorem and simplifying the result, the final expression gives us \(32c^5 + 320c^4 + 1280c^3 + 2560c^2 + 2560c + 1024\) .

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Expansion
The Binomial Theorem is a cornerstone of algebra that allows us to expand expressions that are raised to a power. Think of it as a shortcut for distribution when multiplying binomials multiple times. For the binomial expression \( (a+b)^n \), where \( a \) and \( b \) are any numbers, and \( n \) is a positive integer, the theorem provides us with a formula involving combinations.

To expand \( (a+b)^n \), the theorem tells us we'll have terms beginning from \( a^n \) all the way to \( b^n \) with coefficients determined by combinations. These coefficients are represented by \( C(n, k) \), which denote the number of ways to choose \( k \) elements out of a pool of \( n \) without regard to order. This is where our understanding of combinations comes into play.

Each term in the expanded formula has the general form \( C(n, k)a^{n-k}b^k \). The exponent of \( a \) decreases while the exponent of \( b \) increases in each subsequent term. By applying this iterative process from \( k = 0 \) to \( k = n \) and simplifying, we can fully expand the binomial without having to perform the multiplication step by step.
Combinations in Algebra
In the context of algebra, combinations are used to determine the coefficients in binomial expansion, as discussed earlier. They are expressed as \( C(n, k) \), also known as \( n \) choose \( k \), and are found in Pascal's Triangle or calculated using the formula \( C(n, k) = \frac{n!}{k!(n-k)!} \), where \( ! \) denotes factorial—a product of all positive integers up to that number.

Understanding combinations is crucial for binomial expansion as each term's coefficient in the expansion is essentially a combination value. These coefficients tell us how many ways we can select items and apply to our polynomial terms. To expand a binomial like \( (c+2)^5 \) correctly, you need to be comfortable with computing these combination numbers, as they directly affect the magnitude of each term in the expansion.
Polynomial Simplification
The simplification of polynomials is the final stage after applying the Binomial Theorem. Once we expand the expression using the binomial coefficients and the general term structure, we arrive at an expression made up of multiple terms involving powers of the binomial's parts. The aim of simplification is to combine like terms and present the polynomial in its standard form, where terms are ordered by decreasing powers.

In our example, after expanding and applying the coefficients, we reached \( 32c^5 + 320c^4 + 1280c^3 + 2560c^2 + 2560c + 1024 \). Here, simplification doesn't involve combining terms because the binomial expansion results in distinct terms with different powers of \( c \). The simplification here is to make sure all the necessary multiplication is carried out and that we write down our final result cleanly and in correct descending order. This process makes the polynomial ready for further analysis or application, such as graphing or solving equations.

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