/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 115 Use a right triangle to write \(... [FREE SOLUTION] | 91Ó°ÊÓ

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Use a right triangle to write \(\cos \left(\tan ^{-1} x\right)\) as an algebraic expression. Assume that \(x\) is positive and that the given inverse trigonometric function is defined for the expression in \(x . \quad\) (Section 4.7, Example 9).

Short Answer

Expert verified
The algebraic expression for \(\cos(\tan^{-1}(x))\) is \(1/\sqrt{x^2 + 1}\).

Step by step solution

01

Draw a Right Triangle and Apply Inverse Tan

Start by drawing a right triangle. By definition, \(\tan ^{-1}(x)\) represents an angle whose tangent is \(x\). In a right triangle, the tangent of an angle is the ratio of the side opposite to the side adjacent to the angle. So, let's assume the length of the side adjacent to the angle be 1 and the length of the side opposite to the angle be \(x\). We'll label these on the triangle.
02

Use Pythagorean Theorem to Compute Hypotenuse

Next, compute the length of the hypotenuse using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides. Therefore, the length of the hypotenuse \(r\) is \(\sqrt{x^2 + 1}\). Label this on the triangle.
03

Use Cos Definition to Write Algebraic Expression

Finally, recall that by definition, the cosine of an angle in a right triangle is the ratio of the side adjacent to the angle to the hypotenuse. Therefore, \(\cos(\tan^{-1}(x))\) is the ratio of the adjacent side (length 1) to the hypotenuse (\(\sqrt{x^2+1}\)). This simplifies to \(1/\sqrt{x^2 + 1}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Trigonometric Functions
Inverse trigonometric functions allow us to find angles when given a trigonometric ratio. They are the reverse operations of regular trigonometric functions. For instance,
  • the inverse of the sine function is denoted as \ \(\sin^{-1}(x)\ \) and is often called arcsin,
  • while the inverse of the cosine function is \ \(\cos^{-1}(x)\ \) (also known as arccos),
  • and similarly, \ \(\tan^{-1}(x)\ \) or arctan is the inverse of the tangent function.
These functions are crucial in determining angles, especially in geometric and trigonometric calculations.
In the original exercise, \ \(\tan^{-1}(x)\ \) indicates the angle whose tangent is \ \(x\ \). This angle helps us easily relate the tangent ratio back to a specific angle's measure in a right triangle.
Right Triangles
Right triangles are fundamental in trigonometry and geometry. A right triangle is defined as a triangle with one 90-degree angle. The remaining two angles are acute and must sum up to 90 degrees.
In a right triangle:
  • the longest side is called the hypotenuse,
  • one side is called the opposite (the side opposite the angle of interest),
  • and the other is the adjacent side (next to the angle of interest).
The trigonometric functions sine, cosine, and tangent are defined based on the ratios of these sides.
When you encounter expressions like \ \(\tan^{-1}(x)\ \), it's your cue to visualize or draw a right triangle where tangent (opposite over adjacent) equals \ \(x\ \). This exercise uses a triangle where one side adjacent to the angle is set to 1, and the opposite side is \ \(x\ \).
Pythagorean Theorem
The Pythagorean theorem is a cornerstone principle in geometry that applies to right triangles. Named after the ancient Greek mathematician Pythagoras, the theorem states: In a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
This can be expressed as:
  • \ \(a^2 + b^2 = c^2\ \), where \ \(c\ \) represents the hypotenuse,
  • and \ \(a\ \) and \ \(b\ \) are the other two sides.
In our exercise, after identifying the sides of the right triangle as \ \(x\ \) and 1, we apply the Pythagorean theorem to find the hypotenuse: \ \(\sqrt{x^2 + 1}\ \).
With this, we can determine other trigonometric ratios like cosine using these side lengths, such as \ \(\cos(\tan^{-1}(x)) = \frac{1}{\sqrt{x^2 + 1}}\ \), as derived in the exercise.

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