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Chapter 1: Problem 94

Let \(f(x)=x^{2}-x+4\) and \(g(x)=3 x-5\). Find \(g(-1)\) and \(f(g(-1))\).

Short Answer

Expert verified
Therefore, \(g(-1)=-8\) and \(f(g(-1))=76\).

Step by step solution

01

Compute g(-1)

We substitute -1 into the function \(g(x)=3 x-5\) to get \(g(-1)\). That is \(g(-1)=3*(-1)-5=-8\).
02

Compute f(g(-1))

Next, we substitute the result from Step 1 (-8) into the function \(f(x)=x^{2}-x+4\) to get \(f(g(-1))\). This implies \(f(-8)=(-8)^{2}-(-8)+4=64+8+4=76\).

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