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Find a. \((f \circ g)(x)\) b. \((g \circ f)(x)\) c. \((f \circ g)(2)\) d. \((g \circ f)(2)\) $$f(x)=6 x-3, g(x)=\frac{x+3}{6}$$

Short Answer

Expert verified
(f \circ g)(x) = x, (g \circ f)(x) = x, (f \circ g)(2) = 2, (g \circ f)(2) = 2

Step by step solution

01

Compute \((f \circ g)(x) = f(g(x))\)

Substitute the given function \(g(x) = \frac{x+3}{6}\) into function \(f(x) = 6x - 3\). Hence \((f \circ g)(x) = f(g(x)) = 6 * (\frac{x+3}{6}) - 3 = x+3-3 = x\)
02

Compute \((g \circ f)(x) = g(f(x))\)

Substitute the given function \(f(x) = 6x - 3\) into function \(g(x) = \frac{x+3}{6}\). Hence \((g \circ f)(x) = g(f(x)) = \frac{6x-3+3}{6} = \frac{6x}{6} = x\)
03

Compute \((f \circ g)(2)\)

Substitute the value 2 into the solution for (f \circ g)(x). We get \((f \circ g)(2) = 2\)
04

Compute \((g \circ f)(2)\)

Substitute the value 2 into the solution for (g \circ f)(x). We get \((g \circ f)(2) = 2\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Composite Functions
Understanding composite functions is like discovering a recipe within a recipe. In mathematics, when we blend two functions together, it's as though we're combining ingredients from one recipe into another to create a new dish entirely. This is precisely what we refer to as function composition, symbolized as \(f \circ g\).

To compute this, we take the output of one function and make it the input of another. For example, if we have two functions, \(f(x) = 6x - 3\) and \(g(x) = \frac{x+3}{6}\), and we want to find \(f \circ g\), we simply insert \(g(x)\) into \(f(x)\). So, \(f(g(x))\) becomes \(6 \cdot \frac{x+3}{6} - 3\), which neatly simplifies to just \(x\), showing that the composite function in this case is equivalent to the identity function.
Function Operations
Just as we can add, subtract, multiply, and divide numbers, we can perform operations on functions. Function operations allow us to construct new functions from existing ones, hence expanding our arsenal of mathematical tools.

In our example, aside from composition, we could consider operations such as \(f(x) + g(x)\), \(f(x) - g(x)\), \(f(x) \cdot g(x)\), or even \(\frac{f(x)}{g(x)}\), provided \(g(x) \eq 0\). Each operation has its own set of rules and potential complexities, but through practice, one may master the art of skillfully manipulating functions just as a chef might master combining flavors.
Algebraic Functions
Algebraic functions are the bread and butter of precalculus, serving as the basic building blocks for complex mathematical equations. These functions are made up of algebraic operations—like addition, subtraction, multiplication, division, and root extraction—applied to variables.

For instance, \(f(x) = 6x - 3\) is a linear algebraic function, characterized by its straight-line graph. Similarly, \(g(x) = \frac{x+3}{6}\) represents a rational function since it involves division by a variable. Recognizing the forms and properties of algebraic functions is crucial for solving problems effectively and is a skill honed over time through study and practice.
Precalculus
Precalculus lays the foundation for calculus, much like a robust appetizer sets the stage for an entrancing main course. It's a comprehensive study that involves algebra, geometry, and mathematical analysis. Within precalculus, we delve into various types of functions—such as the ones we've discussed, algebraic functions—and their transformations, combinations, and applications.

Additionally, it introduces the concept of limits, which is a cornerstone of calculus. Precalculus problems, like the one involving the calculation of composite functions, give students a taste of higher-level mathematics and serve to sharpen their problem-solving abilities before they advance onto the main spectacle: calculus.

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Most popular questions from this chapter

In Exercises \(67-70,\) graph both equations in the same rectangular coordinate system and find all points of intersection. Then show that these ordered pairs satisfy the equations. $$\begin{aligned} (x-3)^{2}+(y+1)^{2} &=9 \\ y &=x-1 \end{aligned}$$

The toll to a bridge costs \(\$ 6.00 .\) Commuters who frequently use the bridge have the option of purchasing a monthly discount pass for \(\$ 30.00 .\) With the discount pass, the toll is reduced to \(\$ 4.00 .\) For how many bridge crossings per month will the cost without the discount pass be the same as the cost with the discount pass? What will be the monthly cost for each option? \((\text { Section } \mathrm{P} .8, \text { Example } 3)\)

For people filing a single return, federal income tax is a function of adjusted gross income because for each value of adjusted gross income there is a specific tax to be paid. By contrast, the price of a house is not a function of the lot size on which the house sits because houses on same-sized lots can sell for many different prices. a. Describe an everyday situation between variables that is a function. b. Describe an everyday situation between variables that is not a function.

In your own words, describe how to find the midpoint of a line segment if its endpoints are known.

The size of a television screen refers to the length of its diagonal. If the length of an HDTV screen is 28 inches and its width is 15.7 inches, what is the size of the screen to the nearest inch? (Section P.8, Example 8)

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