/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Determine whether the graph of e... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the graph of each equation is symmetric with respect to the \(y\) -axis, the \(x\) -axis, the origin, more than one of these, or none of these. $$y^{5}=x^{4}+2$$

Short Answer

Expert verified
The graph of the given equation is not symmetric with respect to the \(y\)-axis, the \(x\)-axis, or the origin.

Step by step solution

01

Symmetry with respect to the y-axis

Replace \(x\) in the equation with \(-x\). We will get \((-y)^{5} = (-x)^{4} + 2\), which simplifies to \(-y^{5} = x^{4} + 2\). This does not match the original equation, so the graph is not symmetric with respect to the \(y\)-axis.
02

Symmetry with respect to the x-axis

Replace \(y\) in the equation with \(-y\). We get \((-y)^{5} = x^{4} + 2\), which simplifies to \(-y^{5} = x^{4} + 2\). This does not match the original equation, so the graph is not symmetric with respect to the \(x\)-axis.
03

Symmetry with respect to the origin

Replace \(x\) with \(-x\) and \(y\) with \(-y\). We get \((-y)^{5} = (-x)^{4} + 2\), which simplifies to \(-y^{5} = x^{4} + 2\). This does not match the original equation, so the graph is not symmetric with respect to the origin.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Y-Axis Symmetry
Y-axis symmetry in a graph is a fascinating concept. To determine if a graph has this type of symmetry, you need to check whether each point on the graph has a mirror image across the y-axis. This implies if the point \((x, y)\) lies on the graph, then the point \((-x, y)\) should also be on the graph.

In practice, you replace \(x\) with \(-x\) in the equation and simplify. If the resulting equation is equivalent to the original one, the graph is symmetric with respect to the y-axis. For instance, if you have the equation \(y = x^2\), replacing \(x\) with \(-x\) gives you \(y = (-x)^2 = x^2\) again, showing y-axis symmetry.

In the current exercise, replacing \(x\) with \(-x\) in the equation \(y^5 = x^4 + 2\) results in \(-y^5 = x^4 + 2\). This doesn't match the original equation, indicating no y-axis symmetry.
X-Axis Symmetry
With x-axis symmetry, graphs reflect across the x-axis, a concept that can be tricky but straightforward with a systematic approach. To verify x-axis symmetry, the graph should include points such that for every \((x, y)\), its mirror image \((x, -y)\) also lies on the graph.

Checking for x-axis symmetry involves replacing \(y\) with \(-y\) in the original equation. If simplifying this substitution leads back to the initial equation, the graph reflects across the x-axis. Consider the equation \(x = y^2\); when you substitute \(y\) with \(-y\), it becomes \(x = (-y)^2 = y^2\), confirming x-axis symmetry.

In our specific example, substituting \(y\) with \(-y\) in \(y^5 = x^4 + 2\) changes the equation to \(-y^5 = x^4 + 2\). Since this altered equation doesn't revert to the original, the graph won't have x-axis symmetry.
Origin Symmetry
Origin symmetry means that a graph stands unchanged if rotated 180 degrees around the origin. To determine this, each point \((x, y)\) on the graph should have a corresponding point \((-x, -y)\). It might seem complex, but practicing this approach makes it manageable.

To test for origin symmetry, replace both \(x\) with \(-x\) and \(y\) with \(-y\) in the equation. If the new equation matches the original, then origin symmetry is established. For example, in the case of \(y = x^3\), replacing \(x\) with \(-x\) and \(y\) with \(-y\) results in \(-y = (-x)^3 = -x^3\), which simplifies to the same equation, indicating origin symmetry.

When applying this to the equation \(y^5 = x^4 + 2\), substituting \(x\) with \(-x\) and \(y\) with \(-y\) modifies the equation to \(-y^5 = x^4 + 2\). This transformation does not match the original equation, showing that the graph lacks origin symmetry as well.

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