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Add or subtract terms whenever possible. $$\sqrt{20}+6 \sqrt{5}$$

Short Answer

Expert verified
The simplified form of \( \sqrt{20} + 6 \sqrt{5} \) is \( 8 \sqrt{5} \)

Step by step solution

01

Simplify The Square Root

The first part of this problem involves simplifying the square root of 20. This can be achieved by finding two numbers that multiply to 20, one of which should be a perfect square. The perfect squares less than 20 are 1, 4, 9 and 16. Among these, 4 is a factor of 20 (since 4*5 =20). So, we can write \( \sqrt{20} \) as \( \sqrt{4 * 5} \) which simplifies to \( 2 \sqrt{5} \)
02

Add Like Terms

Now we can add the numbers containing like radicals. The simplified expression for \( \sqrt{20} \) is \( 2 \sqrt{5} \) and we're adding this to \( 6 \sqrt{5} \). So, \( 2 \sqrt{5} + 6 \sqrt{5} = 8 \sqrt{5} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Perfect Squares
A perfect square is a number that can be expressed as the product of an integer with itself, meaning a number like 4, 9, or 16. These numbers have whole numbers as their square roots (e.g., \( \sqrt{4} = 2\), which makes them easy to work with in mathematical problems.

In the context of simplifying square roots, identifying perfect squares is essential. For instance, when simplifying \( \sqrt{20} \), we search for a perfect square that can multiply alongside another number to result in 20. Here, the perfect square is 4, since \( 4 \times 5 = 20 \).
This breakdown allows us to rewrite \( \sqrt{20} \) as \( \sqrt{4 \times 5} = \sqrt{4}\sqrt{5} = 2\sqrt{5} \). Simplicity like this makes calculations easier by converting complex numerical expressions into more manageable forms that can be combined or compared with other terms.
Adding Radicals
Adding radicals follows the same principles as adding any algebraic expressions - you only combine like terms. "Like radicals" means radicals that have the same radicand (the number inside the square root). Thus, \( 2 \sqrt{5} \) and \( 6 \sqrt{5} \) are like radicals because both share the \( \sqrt{5} \) factor.
  • To add them, simply add the coefficients (the numbers in front of the radicals): \( 2 + 6 = 8 \).
The result is \( 8 \sqrt{5} \). Remember:
  • Like terms must have the same radical part.
  • If radicals are different, they cannot be directly added.
Practicing adding radicals helps reinforce understanding of combining similar elements in algebraic expressions, making future problems easier to tackle.
Like Terms
Like terms in algebra are terms that share the same variables and corresponding exponents, including their coefficients. When dealing with radicals, like terms refer to those with identical radical parts.

Consider the example of combining \( 2 \sqrt{5} \) and \( 6 \sqrt{5} \). These are like terms because both involve \( \sqrt{5} \). Therefore, despite any differences in their coefficients, they can be added or subtracted.
  • Example: \( 3 \sqrt{2} + 4 \sqrt{2} = (3 + 4) \sqrt{2} = 7 \sqrt{2} \).
  • Non-example: \( 3 \sqrt{2} + 4 \sqrt{3} \) cannot be added directly because their radicals differ (\( \sqrt{2} \) vs. \( \sqrt{3} \)).
Mastering the identification and operation of like terms aids in simplifying expressions reliably and efficiently, which is vital in complex algebraic problem-solving.

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Most popular questions from this chapter

The formula for converting Fahrenheit temperature, \(F,\) to Celsius temperature, \(C\), is $$C=\frac{5}{9}(F-32)$$ If Celsius temperature ranges from \(15^{\circ}\) to \(35^{\circ},\) inclusive, what is the range for the Fahrenheit temperature? Use interval notation to express this range.

Use the strategy for solving word problems, modeling the verbal conditions of the problem with a linear inequality. On two examinations, you have grades of 86 and \(88 .\) There is an optional final examination, which counts as one grade. You decide to take the final in order to get a course grade of \(\mathrm{A},\) meaning a final average of at least 90 a. What must you get on the final to earn an A in the course? b. By taking the final, if you do poorly, you might risk the B that you have in the course based on the first two exam grades. If your final average is less than \(80,\) you will lose your \(\mathrm{B}\) in the course. Describe the grades on the final that will cause this to happen.

Will help you prepare for the material covered in the next section. A telephone texting plan has a monthly fee of 20 dollar with a charge of 0.05 dollar per text. Write an algebraic expression that models the plan's monthly cost for \(x\) text messages.

Determine whether each statement makes sense or does not make sense, and explain your reasoning. Although I can solve \(3 x+\frac{1}{5}=\frac{1}{4}\) by first subtracting \(\frac{1}{5}\) from both sides, I find it easier to begin by multiplying both sides by \(20,\) the least common denominator.

Solve each equation. $$\sqrt{x+5}-\sqrt{x-3}=2$$

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