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Factor completely. $$2 x^{2}-7 x y^{2}+3 y^{4}$$

Short Answer

Expert verified
The complete factorization of the polynomial \(2 x^{2}-7 x y^{2}+3 y^{4}\) is \( (x - 3y^2)(2x - y^2) \).

Step by step solution

01

Identify common factors

In this equation \(2 x^{2}-7 x y^{2}+3 y^{4}\), there are no common factors in all three terms.
02

Identify factorable trinomial

After finding no common factors, next step is to see if the trinomial can be factored to the product of two binomials. In this case, we must find two numbers that multiply to \(2*3 = 6 \) (product of the coefficient of \(x^2\) and \(y^4\)) and add up to -7 (coefficient of \(xy^2\)). These numbers are -1 and -6. So, we split the middle term, \(-7\x y^2\) as \(-xy^2 -6xy^2 \). This give us a new polynomial, \(2x^2 - xy^2 - 6y^2 + 3y^4 \).
03

Factor by grouping

Group two terms together from the polynomial derived from step 2 to enable us factor by grouping. Let's write as: \( (2x^2 - xy^2) + (- 6y^2 + 3y^4) \). We can now factor out the common term from each group, which results in \( x(2x - y^2) - 3y^2(2x - y^2) \).
04

Combine common terms

As we can observe, both terms of the equation have a common factor \( (2x - y^2) \). Factor out this common polynomial to obtain the final factored form. This yields: \( (x - 3y^2)(2x - y^2) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trinomial Factoring
Trinomial factoring is a technique used to simplify expressions involving three terms. The goal is to rewrite a trinomial as a product of two or more simpler expressions. In our example, the trinomial is given by the expression \(2x^2 - 7xy^2 + 3y^4\). Transforming this into simpler components allows easier manipulation and further calculations.When factoring a trinomial, the initial step is to check if it can be expressed as a product of two binomials. This involves finding specific values that satisfy conditions such as multiplying to the product of the leading coefficient and the constant term. In essence, you're breaking down the original trinomial into smaller parts that are easier to handle.
Polynomial Expressions
Polynomial expressions are sums of terms, consisting of variables raised to different powers and coefficients. These expressions are pivotal in algebra and take forms like \(ax^n + bx^{n-1} + ... + c\), where \(a, b,\) and \(c\) are coefficients, and \(n\) signifies the degree of the polynomial.In the given exercise, the polynomial expression is \(2x^2 - 7xy^2 + 3y^4\). Here, it includes terms with the variables \(x\) and \(y\) combined in varying degrees. Understanding the structure of these expressions is fundamental to mastering factoring techniques. By identifying the components accurately, one can approach problems with a clear strategy for simplification or solution.
Factoring by Grouping
Factoring by grouping is a practical method for simplifying complex expressions by rearranging and dividing terms into manageable groups. This approach is beneficial when dealing with expressions where a straightforward factorization is not immediately apparent.In our example, after rewriting \(-7xy^2\) as \(-xy^2 - 6xy^2\), we proceeded to group the polynomial as \((2x^2 - xy^2) + (-6y^2 + 3y^4)\). This setup makes it easier to identify common factors within each group. Once grouped, we factor each subset to obtain \(x(2x - y^2) - 3y^2(2x - y^2)\). Notice how both groups share a common factor, \((2x - y^2)\), which is then factored out to achieve the final expression: \((x - 3y^2)(2x - y^2)\).The strength of factoring by grouping lies in its ability to simplify polynomials step-by-step, making it a powerful tool in algebraic manipulation.

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Factor completely. $$-x^{2}-4 x+5$$

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