/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Solve each linear equation. $$... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each linear equation. $$2(x-1)+3=x-3(x+1)$$

Short Answer

Expert verified
The solution to the equation is \(x = -0.5\).

Step by step solution

01

Removing brackets

On the left-hand side of the equation, distribute 2 to both \(x\) and -1. Do the same for -3 on the right-hand side of the equation. The equation then becomes \(2x - 2 + 3 = x - 3x -3\).
02

Simplifying expressions

Combine like terms on both sides of the equation. This gives \(2x + 1 = -2x - 3\).
03

Moving variables to one side and constants to the other side

We aim to isolate \(x\) and to do that, add 2x to both sides and add 3 to both sides to get rid of the constant on the right side. This leads to \(4x = -3+1.\)
04

Solving the equation

Divide both sides by 4 to solve for \(x\). Hence, the solution to the equation is \(x = -2/4 = -0.5\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distributive Property
The distributive property is a handy tool in algebra that allows you to break down expressions with parentheses. It simplifies them by multiplying each term inside the parentheses by a number or variable outside. This technique ensures solving equations is more straightforward.
To illustrate, consider the expression \(2(x - 1)\). Apply the distributive property by multiplying \(2\) with each term inside the parentheses. This leads to \(2 \times x\) and \(2 \times (-1)\), resulting in \(2x - 2\). Similarly, the expression \(-3(x + 1)\) becomes \(-3x - 3\) after applying this property.
In essence, the distributive property involves:
  • Identifying the terms inside and outside the parentheses.
  • Multiplying each inside term by the outside term.
  • Simplifying the expression accordingly.
Mastering the distributive property will greatly enhance your ability to tackle linear equations with ease.
Combining Like Terms
Once you have applied the distributive property, it’s time to tidy things up by combining like terms. Like terms in algebraic expressions share the same variable raised to the same power. For instance, \(2x\) and \(-3x\) are like terms because both involve the variable \(x\).
In the equation \(2x - 2 + 3 = x - 3x - 3\), combine the like terms:
  • On the left, combine constants \(-2 + 3\) to yield \(+1\).
  • On the right, \(x - 3x\) simplifies to \(-2x\).
Now the equation looks much neater: \(2x + 1 = -2x - 3\).
Remember, the key here is:
  • Identify terms with the same variable and power.
  • Add or subtract their coefficients.
  • Rewrite the expression, continuing toward a simpler form.
This step prepares your equation for easier manipulation in the subsequent stages.
Isolating Variables
Isolating the variable is crucial for pinning down the equation's solution. The goal is to rearrange the equation so that the variable \(x\) appears by itself on one side. This is a multi-step process requiring some strategic moves.
In the equation \(2x + 1 = -2x - 3\), focus on getting all \(x\)-related terms on one side. Achieve this by:
  • Adding \(2x\) to both sides, which shifts terms into balance, resulting in \(4x + 1 = -3\).
  • Next, subtract \(1\) from both sides to shift constants, leading to \(4x = -4\).
Reorganizing terms this way allows for separation of variables and constants, guiding you toward solving for \(x\).
Throughout this process, aim to:
  • Move all terms involving the variable to one side.
  • Transfer constants to the opposite side for clarity.
By carefully balancing actions on both sides of the equation, you simplify to a point where finding \(x\) becomes straightforward.
Simplification in Algebra
Simplification refers to making expressions as neat and concise as possible. It's a recurring theme in algebra, streamlining your work and reducing potential errors.
After isolating variables, move on to simplifying the solution. In the equation \(4x = -4\), divide through by \(4\) on both sides. This shrinks the equation to \(x = -1\).
Here are the steps in this simplification:
  • Perform arithmetic operations consistently on both sides.
  • Transform complex expressions into simpler ones.
Simplification encourages clarity and prevents mistakes. Additionally, it prepares the equation for future operations and interpretations. In sum, it's a crucial skill not only in solving equations but also throughout algebra.

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Most popular questions from this chapter

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. What's wrong with this argument? Suppose \(x\) and \(y\) represent two real numbers, where \(x>y .\) $$\begin{aligned}2 &>1 \\\2(y-x) &>1(y-x) \\\2 y-2 x &>y-x \\\y-2 x &>-x \\\y &>x\end{aligned}$$ This is a true statement. Multiply both sides by \(y-x\) Use the distributive property. Subtract \(y\) from both sides. Add \(2 x\) to both sides. The final inequality, \(y>x,\) is impossible because we were initially given \(x>y\)

If you are given a quadratic equation, how do you determine which method to use to solve it?

In more U.S. marriages, spouses have different faiths. The bar graph shows the percentage of households with an interfaith marriage in 1988 and \(2012 .\) Also shown is the percentage of households in which a person of faith is married to someone with no religion. GRAPH CAN'T COPY. The formula $$I=\frac{1}{4} x+26$$ models the percentage of U.S. households with an interfaith marriage, \(I, x\) years after \(1988 .\) The formula $$N=\frac{1}{4} x+6$$ models the percentage of U.S. households in which a person of faith is married to someone with no religion, \(N, x\) years after \(1988 .\) Use these models to solve Exercises \(107-108\). a. In which years will more than \(33 \%\) of U.S. households have an interfaith marriage? b. In which years will more than \(14 \%\) of U.S. households have a person of faith married to someone with no religion? c. Based on your answers to parts (a) and (b), in which years will more than \(33 \%\) of households have an interfaith marriage and more than \(14 \%\) have a faith/no religion marriage? d. Based on your answers to parts (a) and (b), in which years will more than \(33 \%\) of households have an interfaith marriage or more than \(14 \%\) have a faith/no religion marriage?

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