/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Show that the rectangular form o... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Show that the rectangular form of the equation \(r=a \sin 3 \theta\) is \(\left(x^{2}+y^{2}\right)^{2}=a y\left(3 x^{2}-y^{2}\right)\)

Short Answer

Expert verified
The rectangular form is \((x^2 + y^2)^2 = ay(3x^2 - y^2)\).

Step by step solution

01

Convert Polar to Rectangular Coordinates

The given equation is in polar coordinates: \( r = a \sin 3\theta \). Start by replacing \( r \) and \( \theta \) with their rectangular counterparts using the identities: \( x = r \cos \theta \), \( y = r \sin \theta \), and \( r = \sqrt{x^2 + y^2} \).
02

Apply Trigonometric Identities

We rewrite \( \sin 3\theta \) using the identity \( \sin 3\theta = 3 \sin \theta - 4 \sin^3 \theta \). This will help in expressing the equation entirely in terms of \( \sin \theta \).
03

Express \(r\sin\theta\) and \(r\cos\theta\)

Since \( y = r \sin\theta \), substituting into the original equation gives \( r = a (3y/r - 4y^3/r^3) \), or \( r^4 = ay (3r^2 - 4y^2) \).
04

Substitute Rectangular Form of \(r\)

Square both sides: since \( r = \sqrt{x^2 + y^2} \), \( r^2 = x^2 + y^2 \) and \( r^4 = (x^2 + y^2)^2 \). Substitute this into the equation: \((x^2 + y^2)^2 = ay(3(x^2 + y^2) - 4y^2)\).
05

Simplify the Equation

Simplify the right side: \(3(x^2 + y^2) - 4y^2 = 3x^2 + 3y^2 - 4y^2 = 3x^2 - y^2\). Substitute back: \((x^2 + y^2)^2 = ay(3x^2 - y^2)\).
06

Conclusion

The equation \((x^2 + y^2)^2 = ay(3x^2 - y^2)\) is the rectangular form of the polar equation \( r = a \sin 3\theta \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar to Rectangular Conversion
Understanding how to convert polar coordinates to rectangular coordinates is crucial in solving various types of equations. In the original exercise, we start with the polar equation \( r = a \sin 3\theta \). Polar coordinates are defined by \( r \) (the radius or distance from the origin) and \( \theta \) (the angle from the positive x-axis). On the other hand, rectangular coordinates, often referred to as Cartesian coordinates, are defined by \( x \) and \( y \).
  • For conversion, remember that \( x = r \cos \theta \).
  • And \( y = r \sin \theta \).
  • Also, \( r = \sqrt{x^2 + y^2} \).
These identities allow us to express any polar coordinate in terms of rectangular coordinates. For our equation, substituting these formulas helps us begin the transformation from polar to rectangular form. This is the foundational step that allows for further manipulation using trigonometric identities.
Trigonometric Identities
Trigonometric identities are mathematical tools that help us relate angles and their functions. They are particularly useful when transforming equations from one form to another, like in this exercise. One specific identity used in the original solution is for \( \sin 3\theta \).
  • The identity is: \( \sin 3\theta = 3 \sin \theta - 4 \sin^3 \theta \).
This identity lets us express functions of \( \theta \) in terms of basic sine functions. By knowing or looking up this identity, we avoid the need for complex derivations every time we encounter such terms. So, after converting \( r \) and \( \theta \) into their respective rectangular components, we apply the identity. It allows us to further simplify the equation and move closer to expressing it entirely with rectangular coordinates.
Rectangular Coordinates
Rectangular coordinates are used to describe a point in a two-dimensional plane using a pair of numbers: \( x \) and \( y \). When we engage in polar to rectangular conversion, our goal is to express our equation using these coordinates. The essential step involves substituting typical components like \( r \) (from polar) with \( \sqrt{x^2 + y^2} \) (in rectangular).
  • The transformation yields values easy to graph on the Cartesian plane.
  • In our case, the result is \((x^2 + y^2)^2 = ay(3x^2 - y^2)\).
This rectangular form is beneficial in analyzing and graphing because it provides a direct relationship between \( x \) and \( y \). Implementing such transformations aids in applications ranging from physics to engineering, where the nature of the Cartesian plane makes interpreting, visualizing, and calculating phenomena more intuitive.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Graph the polar curve $$ r=1.5 \sin \left(\frac{30 \theta}{17}+\frac{\pi}{30}\right)+0.5 $$ Use a viewing rectangle extending from -2 to 2 in both the \(x\) - and \(y\) -directions. Let \(\theta\) run from 0 to \(34 \pi\)

Round each answer to one decimal place. In parallelogram ABCD you are given \(A B=6\) in., \(A D=4\) in., and \(\angle A=40^{\circ} .\) Find the length of each diagonal.

Let \(\theta\) (where \(0 \leq \theta \leq \pi\) ) denote the angle between the two nonzero vectors \(\mathbf{A}\) and \(\mathbf{B}\). Then it can be shown that the cosine of \(\theta\) is given by the formula $$\cos \theta=\frac{\mathbf{A} \cdot \mathbf{B}}{|\mathbf{A}||\mathbf{B}|}$$ (See Exercise 77 for the derivation of this result.) In Exercises \(65-70,\) sketch each pair of vectors as position vectors, then use this formula to find the cosine of the angle between the given pair of vectors. Also, in each case, use a calculator to compute the angle. Express the angle using degrees and using radians. Round the values to two decimal places. $$\mathbf{A}=\langle 3,0\rangle \text { and } \mathbf{B}=\langle 1,4\rangle$$

The polar equation of a line is given. In each case: (a) specify the perpendicular distance from the origin to the line; (b) determine the polar coordinates of the points on the line corresponding to \(\theta=0\) and \(\theta=\pi / 2 ;\) (c) specify the polar coordinates of the foot of the perpendicular from the origin to the line; (d) use the results in parts (a), (b), and (c) to sketch the line; and (e) find a rectangular form for the equation of the line. $$r \cos \left(\theta-\frac{\pi}{6}\right)=2$$

(a) Compute the cosine of the angle between the vectors \langle 2,5\rangle and \langle-5,2\rangle (b) What can you conclude from your answer in part (a)? (c) Draw a sketch to check your conclusion in part (b).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.