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The initial point for each vector is the origin, and \(\theta\) denotes the angle (measured counterclockwise) from the x-axis to the vector. In each case, compute the horizontal and vertical components of the given vector. (Round your answers to two decimal places.) The magnitude of \(\mathbf{F}\) is \(14 \mathrm{N},\) and \(\theta=75^{\circ}\)

Short Answer

Expert verified
Horizontal: 3.62 N, Vertical: 13.52 N.

Step by step solution

01

Understanding the vector components

A vector can be broken down into two components: horizontal and vertical. The horizontal component represents the vector’s effect along the x-axis, and the vertical component represents the vector's effect along the y-axis. For any vector \(\mathbf{F}\) with magnitude \(F\) and angle \(\theta\), the horizontal component is computed as \(F \cdot \cos(\theta)\) and the vertical component as \(F \cdot \sin(\theta)\).
02

Converting angle from degrees to radians

In calculations involving trigonometric functions such as sine and cosine in mathematical contexts, angles are often converted to radians. However, many calculators and computation tools directly accept degree measures. Here, using degrees is acceptable, as calculators can compute trigonometric functions of degree measures.
03

Calculate the horizontal component

Using the formula for the horizontal component: \(F_{x} = F \cdot \cos(\theta)\). \[ F_{x} = 14 \cdot \cos(75^{\circ}) \] Calculate \(\cos(75^{\circ})\) and then multiply by the magnitude (14 N).
04

Calculate the vertical component

Using the formula for the vertical component: \(F_{y} = F \cdot \sin(\theta)\). \[ F_{y} = 14 \cdot \sin(75^{\circ}) \] Calculate \(\sin(75^{\circ})\) and then multiply by the magnitude (14 N).
05

Compute the values and rounding

Calculate \(\cos(75^{\circ}) = 0.2588\) and \(\sin(75^{\circ}) = 0.9659\). Compute the horizontal and vertical components: \[ F_{x} = 14 \cdot 0.2588 = 3.62 \] \[ F_{y} = 14 \cdot 0.9659 = 13.52 \] Round each result to two decimal places.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnitude of a Vector
Vectors are fundamental in physics and mathematics to represent quantities that have both a magnitude and a direction. The magnitude is the size or length of the vector and is often denoted as \( |\mathbf{F}| \) or \( F \). Think of it as how strong or intense the vector is. For example:
  • The speed of a car can be a vector, where the magnitude is the speed itself.
  • Force is another example, where the size of the force (in Newtons) is the magnitude.
In our exercise, the magnitude of vector \( \mathbf{F} \) is \( 14 \mathrm{N} \). This tells us the strength of the force applied, without initially considering its direction. Calculating the components of a vector requires breaking down its magnitude using trigonometric functions, provided the angle is known.
Trigonometric Functions
Trigonometric functions, namely sine (\( \sin \)) and cosine (\( \cos \)), are crucial in vector mathematics. They help decompose a vector into its horizontal and vertical components.- **Cosine Function**: It helps in finding the horizontal component of a vector. For a vector with magnitude \( F \) and an angle \( \theta \) from the x-axis, the horizontal component is given by: \[ F_{x} = F \cdot \cos(\theta) \]- **Sine Function**: It helps in finding the vertical component. The vertical component is given by: \[ F_{y} = F \cdot \sin(\theta) \]Let's put this into perspective:- In our exercise, \( \theta = 75^{\circ} \) and \( F = 14 \mathrm{N} \).- For the horizontal component, \( \cos(75^{\circ}) \approx 0.2588 \) which results in a component of \( 3.62 \mathrm{N} \) after multiplying with the magnitude.- For the vertical component, \( \sin(75^{\circ}) \approx 0.9659 \) resulting in a component of \( 13.52 \mathrm{N} \). These trigonometric functions here use the angle \( \theta \) to project the magnitude correctly along the axes.
Angle Measurement
Angle measurement is essential for accurately determining the direction of vectors and their components. Angles can be measured in different units, the most common being degrees and radians. Here's a simple breakdown:
  • **Degrees**: A full circle is divided into 360 degrees. In our exercise, \( \theta = 75^{\circ} \). It's straightforward and widely used but not always the preferred unit in higher mathematics.
  • **Radians**: Another way to measure angles, where a full circle is \( 2\pi \) radians. Many mathematical functions, especially in calculus, are in radians.
For calculations like ours, as long as your calculator or software can interpret degrees, it's fine to use them directly without converting to radians. With an angle given in degrees, trigonometric functions like \( \sin \) and \( \cos \) can be applied directly, as most scientific calculators allow direct computation with degrees. Always double-check your calculator settings to ensure you're using the correct angle measurement unit. Understanding angle measurement helps set the proper alignment for breaking down the vector into its respective components using trigonometric functions.

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