/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Graph the polar equations. $$r... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graph the polar equations. $$r=2 \sin 2 \theta(\text {four-leafed rose})$$

Short Answer

Expert verified
The graph is a four-leaf rose centered at the origin.

Step by step solution

01

Understand the Polar Equation

The given polar equation is \( r = 2 \sin 2\theta \). This is a type of polar graph known as a 'rose curve'. The coefficient in front of \( \theta \) (which is 2) tells us the rose will have \(2n\) leaves if \(n\) is even and \(n\) leaves if \(n\) is odd. Here, \(n = 2\), so the graph will have 4 leaves.
02

Identify Symmetry

Since the equation involves a sine function, which is symmetric about the origin, and \( \sin 2\theta \) specifically shows symmetry about the line \( \theta = \frac{\pi}{4} \), it implies the graph will be symmetric about the origin, dividing it equally into four quadrants.
03

Determine the Key Angles

Evaluate \( r = 2 \sin 2\theta \) at key angles to understand how the graph behaves and locate important points. For example, at \( \theta = 0, \frac{\pi}{4}, \frac{\pi}{2}, \) and \( \pi \). When \(\theta = 0, r = 0; \theta = \frac{\pi}{4}, r = 2; \theta = \frac{\pi}{2}, r = 0; \theta = \pi, r = 0 \). This will help plot significant points.
04

Sketch the Graph

Start plotting the points and sketch the graph. Begin at the origin at \( \theta = 0 \) where \( r = 0 \). As \( \theta \) increases to \( \frac{\pi}{4} \), \( r \) reaches its maximum value of 2, forming the tip of one leaf. Continue this behavior as \( \theta \) progresses through each quadrant, reflecting the four symmetrical leaves across the axes. The graph will repeat this symmetrical pattern four times around the origin.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rose Curve
A rose curve is one of the fascinating types of polar curves. It gets its name because the graph resembles a petal-like pattern, much like a rose. This type of curve is defined by equations of the form \( r = a \sin(n\theta) \) or \( r = a \cos(n\theta) \).

In these equations:
  • \( a \) determines the length of each petal.
  • \( n \) determines the number and formation of leaves.
A rose curve with \( n \) being an even integer will have \( 2n \) petals, while when \( n \) is odd, the curve will have \( n \) petals.

For the given equation, \( r = 2 \sin 2\theta \), \( n \) is even, hence it forms a four-leafed rose curve. The value of \( a = 2 \), specifying the extent to which each leaf extends from the origin.
Symmetry
In polar coordinates, symmetry is an important characteristic to identify. A polar graph can have symmetry about the line \( \theta = 0 \) (the polar axis), \( \theta = \frac{\pi}{2} \) (vertical line symmetry), or the origin itself (center symmetry).

The function \( r = \sin(n\theta) \) impacts symmetry based on its multiples and trigonometric properties. For \( r = 2\sin 2\theta \), the curve has symmetry about the origin. That's because the sine function is an odd function and \( \sin 2\theta \) introduces additional symmetry lines due to its periodicity.

In this graph, the symmetry is evident because the pattern is evenly distributed around the origin, creating equal quadrants with each 90-degree turn.
Graphing Polar Equations
Graphing polar equations is an intriguing task, as it requires understanding of both the angle \( \theta \) and the radius \( r \). Start by analyzing the behavior of \( r \) at critical angles to build a coherent picture of the curve.

1. **Identify Angles:** Check key angles like \( \theta = 0, \frac{\pi}{4}, \frac{\pi}{2}, \) and \( \pi \) to see how \( r \) behaves.2. **Evaluate \( r \):** At \( \theta = 0 \), \( r = 0 \), which means the curve starts at the origin.
At \( \theta = \frac{\pi}{4} \), \( r = 2 \), reaching the maximum petal length.3. **Plot Points:** Plot these and other intermediary points to ensure the curve's accuracy as \( \theta \) changes.4. **Draw the Curve:** Connect the points in a natural flow, paying close attention to the apparent symmetry and periodicity, repeating the pattern each \( \frac{\pi}{2} \) radians.
Polar Graphs
Polar graphs are unique graph plots where each point is determined by a distance (radius) and angle (\( \theta \)). This differs from Cartesian graphs that use traditional coordinate pairs (x, y).

To visualize a polar graph like \( r = 2 \sin 2\theta \), it's helpful to start at the pole (origin) and extend outward based on the angle \( \theta \). These graphs are typically circular and offer insights into periodic functions.- **Dynamic Construction:** By varying \( \theta \), r can grow larger, smaller, or revert to zero, creating circular patterns or loops.- **Complex Patterns:** Polar equations can create intricate graphs like roses, lemniscates, and spirals.- **Uses in Various Fields:** Employed in physics and engineering, polar graphs help in analyzing waves or forces affecting a center point.

Practicing with different curves sharpens the understanding of their distinctive features, preparing one to tackle more complex equations visually and analytically.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the given information to find the cosine of each angle in \(\triangle \overline{A B C}\) \(a=17 \mathrm{cm}, b=8 \mathrm{cm}, c=15 \mathrm{cm}\) (For this particular tri- angle, you can check your answers, because there is an alternative method of solution that does not require the law of cosines.)

Graph the parametric equations using the given range for the parameter t. In each case, begin with the standard viewing rectangle and then make adjustments, as necessary, so that the graph utilizes as much of the viewing screen as possible. For example, in graphing the circle given by \(x=\cos t\) and \(y=\sin t,\)it would be natural to choose a viewing rectangle extending from -1 to 1 in both the \(x\) - and \(y\) -directions. \(x=4 \cos t, y=3 \sin t, 0 \leq t \leq \pi / 2\) (one-quarter of an ellipse)

(a) \(r \cos \theta=3\) (b) \(r \sin \theta=3\)

Let \(\theta\) (where \(0 \leq \theta \leq \pi\) ) denote the angle between the two nonzero vectors \(\mathbf{A}\) and \(\mathbf{B}\). Then it can be shown that the cosine of \(\theta\) is given by the formula $$\cos \theta=\frac{\mathbf{A} \cdot \mathbf{B}}{|\mathbf{A}||\mathbf{B}|}$$ (See Exercise 77 for the derivation of this result.) In Exercises \(65-70,\) sketch each pair of vectors as position vectors, then use this formula to find the cosine of the angle between the given pair of vectors. Also, in each case, use a calculator to compute the angle. Express the angle using degrees and using radians. Round the values to two decimal places. $$\mathbf{A}=\langle 4,1\rangle \text { and } \mathbf{B}=\langle 2,6\rangle$$

Determine a polar equation for the circle satisfying the given conditions. The radius is \(\sqrt{6},\) and the polar coordinates of the center are: (a) \((2, \pi)\) (b) \(\left(2, \frac{3 \pi}{4}\right)\) (c) (0,0)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.