/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Assume that the vectors \(\mathb... [FREE SOLUTION] | 91Ó°ÊÓ

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Assume that the vectors \(\mathbf{a}, \mathbf{b}, \mathbf{c},\) and \(\mathbf{d}\) are defined as follows: $$\mathbf{a}=\langle 2,3\rangle \quad \mathbf{b}=\langle 5,4\rangle \quad \mathbf{c}=\langle 6,-1\rangle \quad \mathbf{d}=\langle-2,0\rangle$$ Compute each of the indicated quantities. $$|\mathbf{a}+\mathbf{c}|-|\mathbf{a}|-|\mathbf{c}|$$

Short Answer

Expert verified
The result is \( \sqrt{68} - \sqrt{13} - \sqrt{37} \).

Step by step solution

01

Find \( \mathbf{a} + \mathbf{c} \)

First, add the corresponding components of vectors \(\mathbf{a}\) and \(\mathbf{c}\). \(\mathbf{a} = \langle 2, 3 \rangle\) and \(\mathbf{c} = \langle 6, -1 \rangle\). Adding them gives:\[\mathbf{a} + \mathbf{c} = \langle 2 + 6, 3 + (-1) \rangle = \langle 8, 2 \rangle\]
02

Compute \( |\mathbf{a} + \mathbf{c}| \)

Find the magnitude of \( \mathbf{a} + \mathbf{c} = \langle 8, 2 \rangle \). The magnitude is given by the formula:\[|\mathbf{a} + \mathbf{c}| = \sqrt{8^2 + 2^2} = \sqrt{64 + 4} = \sqrt{68}\]
03

Compute \( |\mathbf{a}| \)

Find the magnitude of vector \( \mathbf{a} = \langle 2, 3 \rangle \) using the magnitude formula:\[|\mathbf{a}| = \sqrt{2^2 + 3^2} = \sqrt{4 + 9} = \sqrt{13}\]
04

Compute \( |\mathbf{c}| \)

Find the magnitude of vector \( \mathbf{c} = \langle 6, -1 \rangle \) using the magnitude formula:\[|\mathbf{c}| = \sqrt{6^2 + (-1)^2} = \sqrt{36 + 1} = \sqrt{37}\]
05

Compute \( |\mathbf{a} + \mathbf{c}| - |\mathbf{a}| - |\mathbf{c}| \)

Calculate the expression using the magnitudes found in the previous steps:\[|\mathbf{a} + \mathbf{c}| - |\mathbf{a}| - |\mathbf{c}| = \sqrt{68} - \sqrt{13} - \sqrt{37}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnitude of a Vector
The magnitude of a vector is like finding the length of a line segment in geometry. It gives us an idea of how long the vector is from start to finish. To calculate the magnitude of a vector, you apply the Pythagorean theorem, adjusted for vectors. Let's break it down for better understanding. Given a vector \( \mathbf{v} = \langle x, y \rangle \), the magnitude is calculated using the formula: \[|\mathbf{v}| = \sqrt{x^2 + y^2}\]
  • Take each component of the vector, square it, and add them together.
  • Find the square root of the sum to obtain the magnitude.
Let's consider the vector \( \mathbf{a} = \langle 2, 3 \rangle \). The magnitude is found as follows: \[|\mathbf{a}| = \sqrt{2^2 + 3^2} = \sqrt{4 + 9} = \sqrt{13}\] This process is a straightforward application of the Pythagorean theorem, applied to the components of the vector.
Vector Addition
Vector addition is essential for understanding how to combine two or more vectors into a single vector. This operation involves summing up the corresponding components of each vector. Importantly, the addition maintains the nature of the vector. Here's what you need to know:
  • Each vector component gets added to the corresponding component of the other vector.
  • The result is a new vector.
For example, with our vectors \( \mathbf{a} = \langle 2, 3 \rangle \) and \( \mathbf{c} = \langle 6, -1 \rangle \), their sum \( \mathbf{a} + \mathbf{c} \) is given by: \[\mathbf{a} + \mathbf{c} = \langle 2+6, 3+(-1) \rangle = \langle 8, 2 \rangle\] Think of vector addition as moving a point in the 2D space by the amounts specified in the vectors. This helps determine how different movements (vectors) combine to reach a new position.
Algebra of Vectors
The algebra of vectors incorporates rules and operations that allow us to manipulate vectors mathematically. It's a part of linear algebra, focusing on vector-related operations such as addition, subtraction, and finding magnitudes. Here's what's important to note:
  • Vectors are added by combining their respective components.
  • Subtraction involves adding a negative vector.
  • Scalar multiplication scales a vector by a constant, affecting its magnitude but not its direction unless it's negative.
In our problem, we utilized vector addition and calculation of magnitudes in parts:
  • First, vectors \( \mathbf{a} \) and \( \mathbf{c} \) were added.
  • Then, we found the magnitudes of the resulting vector, and the individual vectors \( \mathbf{a} \) and \( \mathbf{c} \).
  • The expression \(|\mathbf{a} + \mathbf{c}| - |\mathbf{a}| - |\mathbf{c}| \) required us to apply both algebraic and geometric reasoning.
Understanding the algebra of vectors forms the basis for tackling more complex vector operations in mathematics and applied sciences.

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Most popular questions from this chapter

The polar equation of a line is given. In each case: (a) specify the perpendicular distance from the origin to the line; (b) determine the polar coordinates of the points on the line corresponding to \(\theta=0\) and \(\theta=\pi / 2 ;\) (c) specify the polar coordinates of the foot of the perpendicular from the origin to the line; (d) use the results in parts (a), (b), and (c) to sketch the line; and (e) find a rectangular form for the equation of the line. $$r \cos \left(\theta-\frac{\pi}{4}\right)=1$$

Use the given information to find the cosine of each angle in \(\triangle \overline{A B C}\) \(a=17 \mathrm{cm}, b=8 \mathrm{cm}, c=15 \mathrm{cm}\) (For this particular tri- angle, you can check your answers, because there is an alternative method of solution that does not require the law of cosines.)

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The following problem is taken from An Elementary Treatise on Plane Trigonometry, 8 th ed., by \(\mathrm{R}\). D. Beasley (London: Macmillan and Co.; first published in 1884 ): The [angle of] elevation of a tower standing on a horizontal plane is observed; \(a\) feet nearer it is found to be \(45^{\circ}\) b feet nearer still it is the complement of what it was at the first station; shew that the height of the tower is \(a b /(a-b)\) feet.

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