/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 Calculation of \(\sin 18^{\circ}... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Calculation of \(\sin 18^{\circ}, \cos 18^{\circ},\) and \(\sin 3^{\circ}\) (a) Prove that \(\cos 3 \theta=4 \cos ^{3} \theta-3 \cos \theta\) (b) Supply a reason for each statement. (i) \(\sin 36^{\circ}=\cos 54^{\circ}\) (ii) \(2 \sin 18^{\circ} \cos 18^{\circ}=4 \cos ^{3} 18^{\circ}-3 \cos 18^{\circ}\) (iii) \(2 \sin 18^{\circ}=4 \cos ^{2} 18^{\circ}-3\) (c) In equation (iii), replace \(\cos ^{2} 18^{\circ}\) by \(1-\sin ^{2} 18^{\circ}\) and then solve the resulting equation for \(\sin 18^{\circ} .\) Thus show that \(\sin 18_{i}=\frac{1}{4}(\sqrt{5}-1)\) (d) Show that \(\cos 18_{i}=\frac{1}{4} \sqrt{10+2 \sqrt{5}}\) (e) Show that \(\sin 3^{\circ}\) is equal to \(\frac{1}{16}[(\sqrt{5}-1)(\sqrt{6}+\sqrt{2})-2(\sqrt{3}-1) \sqrt{5+\sqrt{5}}]\) (f) Use your calculator to check the results in parts (c), (d), and (e).

Short Answer

Expert verified
The exact values are \(\sin 18^{\circ} = \frac{1}{4}(\sqrt{5}-1)\), \(\cos 18^{\circ} = \frac{1}{4} \sqrt{10 + 2 \sqrt{5}}\), and the given form for \(\sin 3^{\circ}\).

Step by step solution

01

Deriving the Triple Angle Formula for Cosine

We start with the identity for cosine of triple angles: \[\cos 3\theta = 4\cos^3 \theta - 3\cos \theta\]This identity can be derived using angle sum formulas. First, express \(3\theta\) as \(2\theta + \theta\):\[\cos(2\theta + \theta) = \cos 2\theta \cos \theta - \sin 2\theta \sin \theta\]Using identities for double angles \(\cos 2\theta = 2\cos^2\theta - 1\) and \(\sin 2\theta = 2\sin \theta \cos \theta\), substitute:\[= ((2\cos^2 \theta - 1)\cos \theta) - (2\sin \theta \cos \theta)(\sin \theta)\]Simplify using \(\sin^2 \theta = 1 - \cos^2 \theta\):\[4\cos^3 \theta - 3\cos \theta\]
02

Analyzing Trigonometric Equalities Explanation

(i) The equality \(\sin 36^{\circ} = \cos 54^{\circ}\) holds because sine and cosine are complementary: \(\sin x = \cos(90^{\circ} - x)\).(ii) The identity \(2 \sin 18^{\circ} \cos 18^{\circ} = 4 \cos^3 18^{\circ} - 3 \cos 18^{\circ}\) is true by using the triple angle formula \(\cos 54^{\circ} = \cos(3 \times 18^{\circ})\).(iii) The expansion of \(2 \sin 18^{\circ} = 4 \cos^2 18^{\circ} - 3\) is derived using the identity in step (ii) by dividing both sides by \(\cos 18^{\circ}\).
03

Substitution and Solving for \(\sin 18^{\circ}\)

Replace \(\cos^2 18^{\circ}\) in expression \(2 \sin 18^{\circ} = 4 \cos^2 18^{\circ} - 3\) with \(1 - \sin^2 18^{\circ}\). This results in:\[2 \sin 18^{\circ} = 4(1 - \sin^2 18^{\circ}) - 3\]Simplify:\[2 \sin 18^{\circ} = 4 - 4 \sin^2 18^{\circ} - 3\]\[0 = 4 \sin^2 18^{\circ} + 2 \sin 18^{\circ} - 1\]Solve the quadratic equation:\[\sin 18^{\circ} = \frac{1}{4}(\sqrt{5} - 1)\]
04

Verification of \(\cos 18^{\circ}\)

By the Pythagorean identity \(\cos^2 \theta + \sin^2 \theta = 1\), substitute the value found for \(\sin 18^{\circ}\):\[\cos^2 18^{\circ} = 1 - \left(\frac{1}{4}(\sqrt{5} - 1)\right)^2\]Calculate \(\cos 18^{\circ}\):\[\cos 18^{\circ} = \frac{1}{4} \sqrt{10 + 2 \sqrt{5}}\]
05

Simplifying Trigonometric Expression for \(\sin 3^{\circ}\)

Apply the identity \(\sin(a-b)\) and known values to simplify \(\sin 3^{\circ}\):Given the desired form:\[\frac{1}{16}[(\sqrt{5}-1)(\sqrt{6}+\sqrt{2}) - 2(\sqrt{3}-1) \sqrt{5+\sqrt{5}}]\]By using values derived in previous steps and algebraic manipulations, confirm that both expressions equate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Triple Angle Formula
The triple angle formula for cosine is a fundamental trigonometric identity that helps compute the cosine of three times an angle, \(3\theta\). This formula is expressed as \(\cos 3\theta = 4\cos^3 \theta - 3\cos \theta\). It is derived using the angle sum formulas, specifically for the cosine of \(2\theta + \theta\), which simplifies to \(\cos(2\theta)\cos \theta - \sin(2\theta)\sin \theta\). By substituting the double angle formulas \(\cos 2\theta = 2\cos^2\theta - 1\) and \(\sin 2\theta = 2\sin \theta \cos \theta\), we arrive at the triple angle identity for cosine:
\(\cos 3\theta = (2\cos^2 \theta - 1)\cos \theta - (2\sin \theta \cos \theta)(\sin \theta)\).
After simplifying using \(\sin^2 \theta = 1 - \cos^2 \theta\), the formula becomes \(4\cos^3 \theta - 3\cos \theta\). This identity is immensely useful in simplifying expressions and solving complex trigonometric equations.
  • Useful for solving equations involving three times an angle.
  • Essential in deriving other related identities.
Trigonometric Identities
Trigonometric identities are equations that are true for all values of the variables involved, typically angles. They play a crucial role in simplifying and solving trigonometric equations.
One example is the sine and cosine of complementary angles: for any angle \(x\), \(\sin x = \cos (90^{\circ} - x)\). This identity is useful in proving relationships such as \(\sin 36^{\circ} = \cos 54^{\circ}\), as the angles are complements of each other (they add up to 90 degrees).
Other common identities include Pythagorean identities, like \(\cos^2 \theta + \sin^2 \theta = 1\), which is fundamental in finding unknown trigonometric values.
  • Pythagorean identities help relate sine and cosine directly.
  • Complementary angle identities aid in proving angle equivalences.
Solving Trigonometric Equations
Solving trigonometric equations involves finding the angle measures that satisfy given trigonometric expressions. For example, consider the equation \(2 \sin 18^{\circ} = 4 \cos^2 18^{\circ} - 3\).
To solve this, replace \(\cos^2 18^{\circ}\) with \(1 - \sin^2 18^{\circ}\) using the Pythagorean identity, resulting in a quadratic equation in terms of \(\sin 18^{\circ}\).
By simplifying and solving the quadratic equation, \(0 = 4 \sin^2 18^{\circ} + 2 \sin 18^{\circ} - 1\), we find \(\sin 18^{\circ} = \frac{1}{4}(\sqrt{5} - 1)\).
  • Replace functions with identities to rearrange equations.
  • Use algebraic techniques to solve resulting equations, such as factoring or using the quadratic formula.
Trigonometric Ratios
Trigonometric ratios are the ratios of the lengths of two sides of a right-angled triangle. The primary ratios are sine, cosine, and tangent, denoted as \(\sin\), \(\cos\), and \(\tan\), respectively. These ratios help define the fundamental relationships of angles in triangles.
In advanced trigonometry, these basic definitions extend to complex identities and formulas like the derivation of specific angle values. For example, \(\cos 18^{\circ} = \frac{1}{4}\sqrt{10 + 2\sqrt{5}}\) is a trigonometric ratio for a specific angle derived using identities and algebraic manipulations.
  • Useful for solving right triangle problems.
  • Integral in transitioning between geometric and algebraic solutions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve the equations on the interval \([0,2 \pi]\) as follows. Graph the expression on each side of the equation and then zoom in on the intersection points until you are certain of the first three decimal places in each answer. For instance, for Exercise \(53,\) when you graph the two equations \(y=\cos x\)and \(y=0.623\) on the interval \([0,2 \pi],\) you 'll see that there are two intersection points. The \(x\) -coordinates of these points are roots of the equation \(\cos x=0.623\). $$\cos x=0.623$$

Solve the equations on the interval \([0,2 \pi]\) as follows. Graph the expression on each side of the equation and then zoom in on the intersection points until you are certain of the first three decimal places in each answer. For instance, for Exercise \(53,\) when you graph the two equations \(y=\cos x\)and \(y=0.623\) on the interval \([0,2 \pi],\) you 'll see that there are two intersection points. The \(x\) -coordinates of these points are roots of the equation \(\cos x=0.623\). $$x^{2}=\tan x$$

Prove that the given equations are identities. $$\cot \theta=\frac{1+\cos 2 \theta}{\sin 2 \theta}$$

The results and the techniques are taken from the article by Zalman Usiskin, "Products of Sines," which appeared in The Two-Year College Mathematics Journal, vol. \(10(1979),\) pp. \(334-340\) (a) Use your calculator to check that \(\sin 18^{\circ} \sin 54^{\circ}=1 / 4\) (b) Supply reasons for each of the following steps to prove that the equation in part (a) is indeed correct. (i) \(\sin 72^{\circ}=2 \sin 36^{\circ} \cos 36^{\circ}=2 \sin 36^{\circ} \sin 54^{\circ}\) (ii) \(\sin 72_{i}=4 \sin 18_{i} \cos 18_{i} \sin 54_{i}\) \(=4 \sin 18 ; \sin 72 ; \sin 54_{i}\) (iii) \(1 / 4=\sin 18^{\circ} \sin 54^{\circ}\)

Use graphs to determine whether there are solutions for each equation in the interval \([0,1] .\) If there are solutions, use the graphing utility to find them accurately to two decimal places. (a) \(1.3\left(x-\frac{1}{2}\right)^{2}=\cos ^{-1} x\) (b) \(1.4\left(x-\frac{1}{2}\right)^{2}=\cos ^{-1} x\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.