Chapter 7: Problem 16
Determine the amplitude, period, and phase shift for the given function. Graph the function over one period. Indicate the \(x\) -intercepts and the coordinates of the highest and lowest points on the graph. $$f(x)=\sin \left(x-\frac{\pi}{6}\right)$$
Short Answer
Expert verified
Amplitude: 1. Period: \(2\pi\). Phase shift: \(\frac{\pi}{6}\) to the right.
Step by step solution
01
Identify the Basic Form
The given function is \( f(x) = \sin\left(x - \frac{\pi}{6}\right) \). The basic form of a sine function is \( y = a\sin(bx - c) + d \). From this, we identify: - \( a = 1 \) (amplitude), - \( b = 1 \) (altering the period), - \( c = \frac{\pi}{6} \) (phase shift), and - \( d = 0 \) (vertical shift).
02
Determine Amplitude
The amplitude is the absolute value of \( a \), which is the coefficient outside the sine function. Here, \( a = 1 \), so the amplitude is \( 1 \).
03
Find the Period
The period of the sine function is given by the formula \( \frac{2\pi}{b} \). As the coefficient \( b = 1 \), the period of the function is \( \frac{2\pi}{1} = 2\pi \).
04
Calculate Phase Shift
The phase shift is determined by \( \frac{c}{b} \). Here, \( c = \frac{\pi}{6} \) and \( b = 1 \), so the phase shift is \( \frac{\pi}{6} \) to the right.
05
Identify Key Points.
The graph of \( f(x) = \sin(x - \frac{\pi}{6}) \) follows the basic sine curve shifted right by \( \frac{\pi}{6} \). - The x-intercepts occur at the points where \( \sin(x - \frac{\pi}{6}) = 0 \), which are \( x = \frac{\pi}{6}, \frac{7\pi}{6}, \frac{13\pi}{6} \), etc. - Highest point at \((x, 1)\) when \((x - \frac{\pi}{6}) = \frac{\pi}{2} + 2k\pi \), leading to \( x = \frac{2\pi}{3} + 2k\pi \). - Lowest point at \((x, -1)\) when \((x - \frac{\pi}{6}) = \frac{3\pi}{2} + 2k\pi \), leading to \( x = \frac{5\pi}{3} + 2k\pi \).
06
Graph the Function
Plot the function over the interval \( [0, 2\pi] \). The graph will start at \( x = \frac{\pi}{6} \) (first x-intercept), rise to a maximum at \( x = \frac{2\pi}{3} \), drop to zero at \( x = \frac{7\pi}{6} \) (second x-intercept), fall to a minimum at \( x = \frac{5\pi}{3} \), and return to zero at \( x = \frac{13\pi}{6} \). This provides one full period.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Amplitude
The amplitude of a trigonometric function such as the sine function is essentially the peak value of the wave above its central axis. For the function \( f(x) = \sin(x - \frac{\pi}{6}) \), the amplitude can be directly determined by the absolute value of the coefficient before the sine function, denoted by \( a \) in the standard form \( y = a\sin(bx - c) + d \).
Since \( a = 1 \), the amplitude is \( 1 \).
This means that the function will oscillate 1 unit above and below the horizontal axis at its highest and lowest points:
Since \( a = 1 \), the amplitude is \( 1 \).
This means that the function will oscillate 1 unit above and below the horizontal axis at its highest and lowest points:
- The maximum point is at \( y = 1 \)
- The minimum point is at \( y = -1 \)
Periodicity
Periodicity refers to the length of one complete cycle of a trigonometric function before it starts repeating. For sine functions, the standard period is \( 2\pi \).
To calculate the period of a sine function formatted as \( y = a\sin(bx - c) + d \), we use the formula \( \frac{2\pi}{b} \).
In our function \( f(x) = \sin(x - \frac{\pi}{6}) \), the coefficient \( b \) is \( 1 \). Thus, the period is:
This repeating nature makes trigonometric functions particularly useful in modeling real-world phenomena, like sound waves or tidal movements, that also exhibit periodic behavior.
To calculate the period of a sine function formatted as \( y = a\sin(bx - c) + d \), we use the formula \( \frac{2\pi}{b} \).
In our function \( f(x) = \sin(x - \frac{\pi}{6}) \), the coefficient \( b \) is \( 1 \). Thus, the period is:
- \( \frac{2\pi}{1} = 2\pi \)
This repeating nature makes trigonometric functions particularly useful in modeling real-world phenomena, like sound waves or tidal movements, that also exhibit periodic behavior.
Phase Shift
Phase shift describes how far the graph of a trigonometric function has been shifted horizontally from its original position.
In the function \( f(x) = \sin(x - \frac{\pi}{6}) \), we determine the phase shift using \( \frac{c}{b} \), where \( c \) is the horizontal shift component and \( b \) alters the frequency.
Visually, the phase shift can be seen as the starting point of one cycle of the sine wave is no longer at \( x = 0 \), but is instead at \( x = \frac{\pi}{6} \). The oscillations remain the same; only the starting point on the x-axis has changed.
In the function \( f(x) = \sin(x - \frac{\pi}{6}) \), we determine the phase shift using \( \frac{c}{b} \), where \( c \) is the horizontal shift component and \( b \) alters the frequency.
- Given \( c = \frac{\pi}{6} \) and \( b = 1 \), the phase shift is \( \frac{\pi}{6} \) to the right.
Visually, the phase shift can be seen as the starting point of one cycle of the sine wave is no longer at \( x = 0 \), but is instead at \( x = \frac{\pi}{6} \). The oscillations remain the same; only the starting point on the x-axis has changed.