Chapter 6: Problem 30
Use the given information to determine the values of the remaining five trigonometric functions. (The angles are assumed to be acute angles. ) $$\cos B=3 / 8$$
Short Answer
Expert verified
\( \sin B = \frac{\sqrt{55}}{8}, \tan B = \frac{\sqrt{55}}{3}, \sec B = \frac{8}{3}, \csc B = \frac{8\sqrt{55}}{55}, \cot B = \frac{3\sqrt{55}}{55} \).
Step by step solution
01
Identify Known Value
We know that \( \cos B = \frac{3}{8} \). This is the ratio of the adjacent side to the hypotenuse in a right-angled triangle.
02
Use Pythagorean Theorem
To find \( \sin B \), use the Pythagorean identity: \[ \sin^2 B + \cos^2 B = 1 \]Substituting \( \cos B = \frac{3}{8} \) into the equation:\[ \sin^2 B + \left(\frac{3}{8}\right)^2 = 1 \]\[ \sin^2 B + \frac{9}{64} = 1 \]\[ \sin^2 B = 1 - \frac{9}{64} \]\[ \sin^2 B = \frac{64}{64} - \frac{9}{64} \]\[ \sin^2 B = \frac{55}{64} \]\[ \sin B = \sqrt{\frac{55}{64}} \]\[ \sin B = \frac{\sqrt{55}}{8} \]
03
Find Tangent
The tangent of angle B is the ratio of the sine to the cosine. Therefore:\[ \tan B = \frac{\sin B}{\cos B} = \frac{\frac{\sqrt{55}}{8}}{\frac{3}{8}} \]\[ \tan B = \frac{\sqrt{55}}{3} \]
04
Find Secant
The secant of B is the reciprocal of the cosine:\[ \sec B = \frac{1}{\cos B} = \frac{1}{\frac{3}{8}} \]\[ \sec B = \frac{8}{3} \]
05
Find Cosecant
The cosecant of B is the reciprocal of the sine:\[ \csc B = \frac{1}{\sin B} = \frac{1}{\frac{\sqrt{55}}{8}} \]\[ \csc B = \frac{8}{\sqrt{55}} \]Rationalize the denominator:\[ \csc B = \frac{8}{\sqrt{55}} \times \frac{\sqrt{55}}{\sqrt{55}} = \frac{8\sqrt{55}}{55} \]
06
Find Cotangent
The cotangent of B is the reciprocal of the tangent:\[ \cot B = \frac{1}{\tan B} = \frac{1}{\frac{\sqrt{55}}{3}} \]\[ \cot B = \frac{3}{\sqrt{55}} \]Rationalize the denominator:\[ \cot B = \frac{3}{\sqrt{55}} \times \frac{\sqrt{55}}{\sqrt{55}} = \frac{3\sqrt{55}}{55} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pythagorean theorem
The Pythagorean theorem is a fundamental principle in geometry, particularly useful in dealing with right-angled triangles. This theorem states that for any right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides. It can be expressed as: \[ a^2 + b^2 = c^2 \]where \( c \) is the hypotenuse, and \( a \) and \( b \) are the other two sides. This simple but powerful principle allows us to calculate the unknown side of a triangle if the other two are known.
In the context of trigonometric identities, this theorem underpins relationships like \[ \sin^2 \theta + \cos^2 \theta = 1 \]For angle \( B \) in our problem, using the fact that \( \cos B = \frac{3}{8} \), we applied this identity to find \( \sin B \). By rearranging the identity, \( \sin^2 B = 1 - \cos^2 B \), we were able to determine \( \sin B = \frac{\sqrt{55}}{8} \). Therefore, the Pythagorean theorem not only applies to side lengths but also extends to trigonometric functions through these identities.
In the context of trigonometric identities, this theorem underpins relationships like \[ \sin^2 \theta + \cos^2 \theta = 1 \]For angle \( B \) in our problem, using the fact that \( \cos B = \frac{3}{8} \), we applied this identity to find \( \sin B \). By rearranging the identity, \( \sin^2 B = 1 - \cos^2 B \), we were able to determine \( \sin B = \frac{\sqrt{55}}{8} \). Therefore, the Pythagorean theorem not only applies to side lengths but also extends to trigonometric functions through these identities.
reciprocal identities
Reciprocal identities are a key concept in trigonometry that relate the basic trigonometric functions to each other. They essentially provide a way to find the reciprocal of these functions easily:
Similarly, once \( \sin B \) was determined, we applied its reciprocal identity to find \( \csc B = \frac{8}{\sqrt{55}} \). Rationalizing the denominator, it simplified to \( \frac{8\sqrt{55}}{55} \). The same process was used to calculate \( \cot B = \frac{3\sqrt{55}}{55} \) using the reciprocal of \( \tan B \). These identities simplify the process of finding one trigonometric function from another.
- \( \sec \theta = \frac{1}{\cos \theta} \)
- \( \csc \theta = \frac{1}{\sin \theta} \)
- \( \cot \theta = \frac{1}{\tan \theta} \)
Similarly, once \( \sin B \) was determined, we applied its reciprocal identity to find \( \csc B = \frac{8}{\sqrt{55}} \). Rationalizing the denominator, it simplified to \( \frac{8\sqrt{55}}{55} \). The same process was used to calculate \( \cot B = \frac{3\sqrt{55}}{55} \) using the reciprocal of \( \tan B \). These identities simplify the process of finding one trigonometric function from another.
right-angled triangle
A right-angled triangle is a type of triangle that includes a 90-degree angle. It has three sides: the hypotenuse, opposite, and adjacent sides. The hypotenuse is the longest side opposite the right angle, while the other two are identified relative to a particular acute angle.
Use this understanding of a right-angled triangle to apply trigonometric functions and ultimately find the values needed in various trigonometric identities. Such knowledge can be extended to solve many geometric and real-world problems efficiently.
- Adjacent side: The side next to the angle considered, excluding the hypotenuse.
- Opposite side: The side opposite the angle considered.
- \( \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} \)
- \( \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} \)
- \( \tan \theta = \frac{\text{opposite}}{\text{adjacent}} \)
Use this understanding of a right-angled triangle to apply trigonometric functions and ultimately find the values needed in various trigonometric identities. Such knowledge can be extended to solve many geometric and real-world problems efficiently.