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91Ó°ÊÓ

write each equation in logarithmic form. (a) \(9=3^{2}\) (b) \(1000=10^{3}\) (c) \(7^{3}=343\) (d) \(\sqrt{2}=2^{1 / 2}\)

Short Answer

Expert verified
(a) \(\log_3 9 = 2\); (b) \(\log_{10} 1000 = 3\); (c) \(\log_7 343 = 3\); (d) \(\log_2 \sqrt{2} = \frac{1}{2}\).

Step by step solution

01

Convert Equation (a)

The equation given is \(9 = 3^2\). To convert this into logarithmic form, we need the format \( \log_{ ext{base}}( ext{result}) = ext{exponent}\). Here, the base is 3, the result is 9, and the exponent is 2. Thus, the logarithmic form is \(\log_3 9 = 2\).
02

Convert Equation (b)

The equation given is \(1000 = 10^3\). For logarithmic form \(\log_{ ext{base}}( ext{result}) = ext{exponent}\), the base is 10, the result is 1000, and the exponent is 3. Therefore, the logarithmic form is \(\log_{10} 1000 = 3\).
03

Convert Equation (c)

The equation given is \(7^3 = 343\). In logarithmic form \(\log_{ ext{base}}( ext{result}) = ext{exponent}\), the base is 7, the result is 343, and the exponent is 3. The logarithmic form is \(\log_7 343 = 3\).
04

Convert Equation (d)

The equation is \(\sqrt{2} = 2^{1/2}\). To write in logarithmic form \(\log_{ ext{base}}( ext{result}) = ext{exponent}\), the base is 2, the result is \(\sqrt{2}\), and the exponent is \(\frac{1}{2}\). The logarithmic form is \(\log_2 \sqrt{2} = \frac{1}{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Logarithms
A logarithm is a mathematical concept used to find out what exponent is needed to achieve a specific number through a given base. Simply put, if you have an equation of the form \( b^x = y \), the equivalent logarithmic form will be \( \log_b(y) = x \). Here, \( b \) is the base, \( y \) is the result, and \( x \) is the exponent.
Logarithms are particularly useful in solving equations where the exponent is the unknown value. They express the notion of repeated multiplication in equations:
  • The base represents the number being multiplied.
  • The result is the outcome of the multiplication.
  • The exponent shows how many times the base is multiplied by itself.
For example, if we consider the equation \( 9 = 3^2 \), to convert it into logarithmic form, identify the base as 3, the exponent as 2, and the result as 9, which gives \( \log_3(9) = 2 \). This tells us that multiplying 3 two times results in 9.
Exploring Exponential Equations
Exponential equations involve variables located in the exponent position. They are characterized by expressions where a constant base is raised to the power of a variable. These equations can take the form \( a^x = y \), where \( x \) is the variable exponent.
Exponential growth and decay are common applications of exponential equations. Here’s how they work:
  • Exponential growth occurs when the base (greater than 1) is repeatedly multiplied, leading to increasing numbers.
  • Exponential decay occurs when a base between 0 and 1 repeatedly multiplies, resulting in decreasing numbers.
For instance, with \( 1000 = 10^3 \), you see the base of 10 raised to the power of 3 to get 1000. This tells us that multiplying 10 by itself three times equals 1000. Converting this to logarithmic form helps us express the relationship \( \log_{10}(1000) = 3 \).
Mathematical Conversions between Forms
Converting between exponential and logarithmic forms is essential for solving mathematical problems efficiently. Understanding how to transition between these forms can simplify the process of solving complex equations.
Here are the key steps for conversions:
  • Identify the base, exponent, and result in the exponential equation.
  • Apply the formula: \( \log_\text{base}(\text{result}) = \text{exponent} \).
  • Translate each part accurately to its respective position in the logarithmic equation.
In equation (d), for example, \( \sqrt{2} = 2^{1/2} \), the square root expression converts cleanly as \( \log_2(\sqrt{2}) = \frac{1}{2} \). This method provides a direct means to express roots and powers within logarithmic contexts, allowing for a broader understanding of data representation and computational solutions.

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Most popular questions from this chapter

Strontium-90, with a half-life of 28 years, is a radioactive waste product from nuclear fission reactors. One of the reasons great care is taken in the storage and disposal of this substance stems from the fact that strontium-90 is, in some chemical respects, similar to ordinary calcium. Thus strontium-90 in the biosphere, entering the food chain via plants or animals, would eventually be absorbed into our bones. (a) Compute the decay constant \(k\) for strontium-90. (b) Compute the time required if a given quantity of strontium-90 is to be stored until the radioactivity is reduced by a factor of \(1000 .\) (c) Using half-lives, estimate the time required for a given sample to be reduced by a factor of \(1000 .\) Compare your answer with that obtained in (b).

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